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Displacement and Velocity-Time Graphs: Concepts, Differences & Application

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Difference Between Displacement-Time and Velocity-Time Graphs

Displacement and Velocity Time Graphs are essential tools in JEE Main Physics for analyzing motion visually and solving kinematics numericals quickly. These graphs transform mathematical equations into interpretable shapes, letting you see at a glance how an object moves with time. By understanding how to read, sketch, and compare these motion graphs, you build a strong foundation for tackling questions in kinematics, uniform and non-uniform motion, and acceleration. This article covers core meanings, proven techniques, worked examples, and practical insights tailored for JEE students.


What Are Displacement and Velocity Time Graphs?

A displacement-time graph plots an object's position (displacement, s) versus time (t). The graph’s slope at any point gives the object’s velocity. A velocity-time graph shows velocity (v) on the vertical axis and time on the horizontal axis—the slope here indicates acceleration, and the area under the curve gives displacement. Both types directly support JEE motion analysis and help visualize how quantities change over time.



Difference Between Displacement-Time and Velocity-Time Graphs

Feature Displacement-Time Graph Velocity-Time Graph
Y-axis quantity Displacement (s) Velocity (v)
Slope meanings Velocity Acceleration
Area under curve No direct physical meaning Displacement
Graph shapes (uniform motion) Straight line (constant slope) Horizontal line
Exam focus Concept clarity, basic velocity Area analysis, acceleration, numericals



How to Draw and Interpret Displacement and Velocity Time Graphs

To sketch a displacement-time graph for uniform motion, plot a straight line with constant positive or negative slope. Curved lines indicate acceleration or deceleration—steeper curves mean faster change in velocity. A flat (horizontal) line shows zero velocity (object at rest).


  1. Mark time (t) on X-axis, displacement (s) on Y-axis.
  2. Plot known values at chosen time points.
  3. Join points smoothly for type of motion (straight for uniform, curve for non-uniform).
  4. Interpret slope: positive (forward), negative (backward), zero (stationary).

For velocity-time graphs, a straight horizontal line means constant velocity. A sloped line (up or down) means constant acceleration or deceleration. Complex curves show changing acceleration. The area under the graph gives displacement between two time intervals—a crucial skill for JEE.


Key Formulas and Example: Displacement and Velocity Time Graphs

  • Slope of displacement-time graph = velocity (v = Δs/Δt)
  • Slope of velocity-time graph = acceleration (a = Δv/Δt)
  • Area under velocity-time graph = displacement (Δs)

Let’s apply formulas with a sample problem:


Suppose a body moves with constant velocity v = 3 m/s for 5 s. The velocity-time graph is a straight horizontal line at 3. The area under the graph = velocity × time = 3 × 5 = 15 m. This is the displacement in the time interval.


For accelerated motion: if a velocity-time graph ramps up linearly from 0 to 10 m/s in 4 s, area is a triangle = (1/2) × 4 × 10 = 20 m. That’s the total displacement covered.



Common Pitfalls and Applications in JEE: Displacement and Velocity Time Graphs

Common student mistakes include misreading slopes or neglecting negative areas (for motion in the opposite direction). Always pay attention to axes, sign convention, and units. Don’t confuse area under a displacement-time graph (which has no direct meaning) versus a velocity-time graph (where it is displacement).


  • Negative slope in displacement-time graph: motion in reverse direction.
  • Flat line in velocity-time graph: zero acceleration.
  • Zero area under v-t graph: object returns to start position.
  • Test yourself using kinematics mock test and important questions for JEE.

You’ll use these graphs for problems in laws of motion, projectile motion, and to compare motion types in JEE Main pattern questions. Vedantu’s Physics faculty has deep experience interpreting these graph types, especially from past year JEE questions.



Related Motion Graphs, Practice, and What’s Next


Mastering displacement and velocity time graphs arms you with a visual approach to kinematics, supporting all levels of JEE Main Physics. Consistent practice and clear understanding make you exam ready—Vedantu’s topic guides and tests are a helpful next step for deeper mastery.


Competitive Exams after 12th Science

FAQs on Displacement and Velocity-Time Graphs: Concepts, Differences & Application

1. How do you find displacement from a velocity-time graph?

Displacement from a velocity-time graph is found by calculating the area under the curve between the two time points.

To do this:

  • Draw vertical lines at the start and end time on the graph.
  • Find the area between the velocity curve and the time axis. For straight-line (constant velocity), it is a rectangle (Area = velocity × time). For non-uniform velocity, split into triangles/rectangles or use calculus.
  • Area above time axis = positive displacement; below time axis = negative displacement.
This method is standard in JEE and CBSE exams for finding total displacement using motion graphs.

2. What is the main difference between a displacement-time and velocity-time graph?

Displacement-time and velocity-time graphs represent different aspects of motion in Physics.

  • Displacement-time graph: The slope gives velocity. A straight line means uniform velocity; a curve means changing velocity.
  • Velocity-time graph: The slope gives acceleration. Area under the graph gives displacement.
Remember, these graphs help you visualize and solve kinematics questions by connecting slope and area to physical quantities.

3. How do you draw a displacement-time graph for uniform motion?

To draw a displacement-time graph for uniform motion (constant velocity):

  • Plot time on the x-axis and displacement on the y-axis.
  • Mark the starting point (usually at origin or a given value).
  • Since velocity is uniform, draw a straight line with a constant, non-zero slope (not horizontal).
  • The slope of this line gives the value of constant velocity.
This visualization is common in CBSE, NEET, and JEE exam questions on kinematics.

4. What is the meaning of the slope of a velocity-time graph?

The slope of a velocity-time graph represents the acceleration of the object.

  • Positive slope: Object is accelerating forwards.
  • Negative slope: Object is decelerating or accelerating in reverse.
  • Zero slope: Velocity is constant; acceleration is zero.
This concept helps solve many graph-based numericals in competitive exams.

5. Are displacement-time and velocity-time graphs the same?

No, displacement-time and velocity-time graphs are not the same.

  • Displacement-time graph: Shows how position changes over time; slope gives velocity.
  • Velocity-time graph: Shows how velocity changes; slope gives acceleration; area under curve gives displacement.
Each graph has unique interpretations and formulas, important for CBSE, JEE, and NEET exams.

6. Can a velocity-time graph ever be a horizontal line? What does it mean?

Yes, a velocity-time graph can be a horizontal line. This means the object has a constant velocity.

  • Horizontal line above x-axis: Moving forwards at constant positive velocity.
  • Horizontal line below x-axis: Constant negative velocity (moving backwards).
This represents zero acceleration, a key case for motion analysis in board and JEE exams.

7. If the displacement-time graph is curved, what does this tell us about the motion?

A curved displacement-time graph indicates non-uniform motion (velocity is changing).

  • The steeper the curve, the higher the instantaneous velocity.
  • If the curve bends upward, velocity is increasing (acceleration).
  • If it bends downward, velocity is decreasing (deceleration).
This is frequently tested in graph-based kinematics questions for CBSE and JEE.

8. Are negative slopes possible in these graphs and what do they represent?

Yes, negative slopes are common in both types of motion graphs.

  • Negative slope in displacement-time graph: Object is moving in the reverse direction (negative velocity).
  • Negative slope in velocity-time graph: Object is decelerating or accelerating in the reverse direction (negative acceleration).
Understanding slope direction is important for accurate motion interpretation in exams.

9. How can you avoid common mistakes in interpreting motion graphs in exams?

To avoid mistakes with motion graphs in exams:

  • Follow proper axis labels: time on x-axis, displacement/velocity on y-axis.
  • Remember what the slope and area represent for each graph type.
  • Double-check units and sign (positive/negative slopes).
  • Read the question carefully to find what is being asked (displacement, velocity, or acceleration).
  • Practice with solved examples and MCQs from your textbook and previous years’ papers.
This reduces errors and boosts scores in Physics exams like JEE and boards.

10. What is the formula for displacement using a velocity-time graph?

The displacement from a velocity-time graph is the total area under the velocity-time curve between two time points.

  • For constant velocity (straight line): Displacement = velocity × time interval
  • For varying velocity: Displacement = Sum of individual areas (rectangle/triangle)
  • Mathematical form: Displacement = ∫ v(t) dt (definite integral if calculus is needed)
This formula is directly used in solving graphical kinematics problems in JEE and NEET.