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Complete Guide to Chemistry Derivations and Formula Proofs

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Stepwise derivations of important chemistry formulas and laws for exams

Ideal gas law was first stated by Emile Clapeyron in 1834. As we know, anything ideal doesn’t exist. So, in ideal gas equation or ideal gas law, ideal gas is a hypothetical gas. In ideal gas forces don’t exist between its particles and these particles do not have any volume or don’t take any space. It means in ideal gas inter molecular forces and atomic volume have been completely ignored. An ideal gas must follow the Kinetic Molecular Theory. While real gases don’t follow kinetic molecular theory, so they show deviations from ideal gas behavior.

Ideal gas Law 

Ideal gas law is based on behavior of ideal gas. It is an approximation of the behavior of many real gases under many conditions. It is actually a combination of Boyle’s law, Charles’ Law and Avogadro’s law. 

Charles’ Law and Avogadro’s law. 

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To understand the ideal gas law first you need to know Boyle’s law, Charles law, Avogadro’s law and Gay-Lussac’s Law. 

Boyle’s law – Boyle’s law states that the absolute pressure exerted by a given mass of an ideal gas is inversely proportional to the volume it occupies if temperature and amount of gas remain unchanged within a closed system. 

Mathematical expression of Boyle’s law - P1V 

where P is the pressure of the gas and V is the volume.

 

Charle’s Law – Charle’s Law states that when the pressure on a sample of a dry gas is held constant, the kelvi the voln temperature and volume will be in direct proportion. 

Mathematical equation can be written as follows – V T,

where V is the volume of the gas and T is the temperature of the gas.

 

Gay-Lussac’s Law – Gay-Lussac’s law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. 

Mathematically it can be expressed as follows – P T ,

where P is pressure of the gas and T is temperature of the gas.

 

Avogadro’s law- Avogadro’s law states that at the same temperature and pressure, equal volumes of gases contain equal numbers of moles. 

Mathematically it can be expressed as follows – V n ,

where V is volume of gas and n is number of moles of the gas 

Now, let’s understand ideal gas law. Ideal gas law is expressed by the general gas equation which is a thermodynamics equation relating state variables such as pressure, volume and temperature with ideal gas. 

Ideal gas law can be easily expressed by – PV = nRT

Ideal Gas Equation 

Ideal gas law is expressed by an ideal gas equation.

The ideal gas equation is written as – PV = nRT

Where P = pressure of the gas 

V = volume of the gas 

n= number of moles of the ideal gas 

R = Gas constant or ideal gas constant 

T = temperature 

Molar form of the ideal gas can be written as follows – 

‘n’ number of moles of the gas is equal to the total mass of the gas divided by its molar mass. So, we can write n= m/M

 Now let’s put the value of n in the above gas equation -PV = mMRT

Where m = total mass of the gas in kg 

             M = Molar mass (in kilograms per mole)

Derivation of Ideal Gas equation 

If V = volume of the gas, P = pressure on gas and T = temperature then – 

According to Boyle’s Law-

V 1P    at constant T or temperature………………………………………. (I)

According to Charle’s Law-

V T   at constant P or pressure……………………………………………… (II)

According to Avogadro’s Law-

V n   at constant T and P………………………………………………………..(III)

Where n = number of moles of the gas 

From equations (I), (II) and (III) we can write – 

V 1P ×T ×n

We can write the above equation as – 

V = R1P ×T×n , where R is the Universal Gas Constant and its value is 8.314 Jmol-1K-1

V = RTnP

After rearranging the above equation – 

PV = nRT

Universal Gas Constant 

Universal gas constant is also known as gas constant or ideal gas constant. It is denoted by ‘R’. it is an experimentally derived number that is used in ideal gas equations and other equations. 

Ideal gas constant and its experimental values in different units are given below – 

R (Numerical value)

Units 

8.314

JK-1mol-1

0.082

L atm K-1 mol-1

8.205

m3 atm K-1 mol-1

8.314 

cm3atm K-1mol-1


Applications of Ideal Gas Law 

  • It is largely used in thermodynamics. 

  • It can be used in stoichiometry problems. 

  • It can be used to determine densities of gases. 

  • Ideal gas law is used in the working mechanics of airbags which are used in vehicles. 

  • Using ideal gas equations, we are able to use coolant gases in refrigerators, air conditioners etc. 


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FAQs on Complete Guide to Chemistry Derivations and Formula Proofs

1. What is meant by derivation in chemistry?

A derivation in chemistry is the step-by-step mathematical process of obtaining a formula or equation from basic laws or principles. It shows how a final equation is logically developed from fundamental concepts.

  • Uses established laws such as gas laws, thermodynamic laws, or electrochemical principles.
  • Involves algebraic manipulation and substitution.
  • Helps in understanding the origin and limitations of formulas.
For example, the ideal gas equation is derived by combining Boyle’s, Charles’s, and Avogadro’s laws.

2. How is the ideal gas equation derived?

The ideal gas equation PV = nRT is derived by combining Boyle’s law, Charles’s law, and Avogadro’s law.

  • Boyle’s law: V ∝ 1/P (at constant T, n)
  • Charles’s law: V ∝ T (at constant P, n)
  • Avogadro’s law: V ∝ n (at constant P, T)
Combining these proportionalities gives V ∝ nT/P, which becomes PV = nRT after introducing the proportionality constant R (gas constant).

3. How do you derive the combined gas law?

The combined gas law is derived by merging Boyle’s and Charles’s laws into one expression: P1V1/T1 = P2V2/T2.

  • Boyle’s law: PV = constant (at constant T)
  • Charles’s law: V/T = constant (at constant P)
Combining both gives PV/T = constant for a fixed amount of gas, which leads to the final combined gas law equation.

4. How is the Nernst equation derived?

The Nernst equation is derived from the relationship between Gibbs free energy and cell potential: ΔG = −nFE.

  • From thermodynamics: ΔG = ΔG° + RT ln Q
  • Substitute ΔG = −nFE and ΔG° = −nFE°
This gives E = E° − (RT/nF) ln Q. At 298 K, it simplifies to E = E° − (0.0591/n) log Q, where n is electrons transferred and Q is the reaction quotient.

5. How do you derive the rate law from a reaction mechanism?

The rate law is derived from the slow (rate-determining) step of a reaction mechanism.

  • Identify the rate-determining step.
  • Write the rate expression based on reactants in that step.
  • If intermediates appear, eliminate them using equilibrium approximations.
For example, if the slow step is A + B → C, then Rate = k[A][B].

6. How is the Henderson–Hasselbalch equation derived?

The Henderson–Hasselbalch equation is derived from the acid dissociation constant expression.

  • For weak acid HA: HA ⇌ H+ + A
  • Ka = [H+][A]/[HA]
Rearranging and taking −log gives pH = pKa + log([A]/[HA]), which relates pH to buffer composition.

7. How is the expression for pH derived?

The pH formula is derived from the definition of hydrogen ion concentration as pH = −log[H+].

  • Based on logarithmic scale to simplify very small concentrations.
  • For pure water at 25°C: [H+] = 1.0 × 10−7 mol L−1
Thus, pH = −log(1.0 × 10−7) = 7.

8. How is the integrated rate equation for a first-order reaction derived?

The first-order integrated rate equation is derived by integrating the differential rate law Rate = k[A].

  • Write: −d[A]/dt = k[A]
  • Separate variables and integrate.
This gives ln[A] = ln[A]0 − kt, or equivalently ln([A]0/[A]) = kt.

9. How is the equilibrium constant expression derived?

The equilibrium constant (K) expression is derived from the law of mass action.

  • For aA + bB ⇌ cC + dD
  • K = [C]c[D]d / [A]a[B]b
Each concentration is raised to the power of its stoichiometric coefficient from the balanced chemical equation.

10. How is the Arrhenius equation derived?

The Arrhenius equation is derived by relating rate constant to activation energy and temperature: k = Ae−Ea/RT.

  • Based on collision theory and energy distribution.
  • Taking natural log gives: ln k = ln A − (Ea/R)(1/T).
This linear form helps determine activation energy (Ea) from experimental data.