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NCERT Solutions for Class 6 Maths Chapter 7: Fractions - Exercise 7.5

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NCERT Solutions for Class 6 Maths Chapter 7 (Ex 7.5)

Free PDF download of NCERT Solutions for Class 6 Maths Chapter 7 Exercise 7.5 (Ex 7.5) and all chapter exercises at one place prepared by an expert teacher as per NCERT (CBSE) books guidelines. Class 6 Maths Chapter 7 Fractions Exercise 7.5 Questions with Solutions to help you to revise complete Syllabus and Score More marks. Register and get all exercise solutions in your emails.


Class:

NCERT Solutions for Class 6

Subject:

Class 6 Maths

Chapter Name:

Chapter 7 - Fractions

Exercise:

Exercise - 7.5

Content-Type:

Text, Videos, Images and PDF Format

Academic Year:

2023-24

Medium:

English and Hindi

Available Materials:

  • Chapter Wise

  • Exercise Wise

Other Materials

  • Important Questions

  • Revision Notes



Every NCERT Solution is provided to make the study simple and interesting on Vedantu. Subjects like Science, Maths, English,Hindi will become easy to study if you have access to NCERT Solution for Class 6 Science , Maths solutions and solutions of other subjects.

Access NCERT Solutions for Class 6 Maths Chapter 7- Fractions

Exercise 7.5

1. Write the fractions appropriately as additions or subtractions.

(a) 


The first Image represents the fraction of 1/5, second one shows 2/5 and third one shows 3/5


Ans: The first figure represents $\dfrac{1}{5}$, second one shows $\dfrac{2}{5}$ and third one shows $\dfrac{3}{5}$.  

The addition is $\dfrac{1}{5} + \dfrac{2}{5} = \dfrac{{1 + 2}}{5} = \dfrac{3}{5}$.


(b) 

The first Image represents the fraction of 5/5 , second one shows 3/5 and third one shows 2/5.


Ans: The first figure represents $\dfrac{5}{5}$, second one shows $\dfrac{3}{5}$ and third one shows $\dfrac{2}{5}$.  

The subtraction is $\dfrac{5}{5} - \dfrac{3}{5} = \dfrac{{5 - 3}}{5} = \dfrac{2}{5}$.


(c) 

The first Image represents fraction of 2/6, second one shows 3/6 and third one shows 5/6


Ans: The first figure represents $\dfrac{2}{6}$, second one shows $\dfrac{3}{6}$ and third one shows $\dfrac{5}{6}$.  

The addition is $\dfrac{2}{6} + \dfrac{3}{6} = \dfrac{{2 + 3}}{6} = \dfrac{5}{6}$.


2. Solve:

(a) $\dfrac{1}{{18}} + \dfrac{1}{{18}}$ 

Ans: Add the numerator and then simplify the fraction.

$\dfrac{1}{{18}} + \dfrac{1}{{18}} = \dfrac{{1 + 1}}{{18}} = \dfrac{2}{{18}} = \dfrac{1}{9}$


(b) $\dfrac{8}{{15}} + \dfrac{3}{{15}}$

Ans: Add the numerator to get the result.

$\dfrac{8}{{15}} + \dfrac{3}{{15}} = \dfrac{{8 + 3}}{{15}} = \dfrac{{11}}{{15}}$


(c) $\dfrac{7}{7} - \dfrac{5}{7}$

Ans: Subtract the numerator to get the result.

$\dfrac{7}{7} - \dfrac{5}{7} = \dfrac{{7 - 5}}{7} = \dfrac{2}{7}$


(d) $\dfrac{1}{{22}} + \dfrac{{21}}{{22}}$

Ans: Add the numerator and then simplify the fraction.

$\dfrac{1}{{22}} + \dfrac{{21}}{{22}} = \dfrac{{1 + 21}}{{22}} = \dfrac{{22}}{{22}} = 1$


(e) $\dfrac{{12}}{{15}} - \dfrac{7}{{15}}$

Ans: Subtract the numerator and then simplify the fraction.

$\dfrac{{12}}{{15}} - \dfrac{7}{{15}} = \dfrac{{12 - 7}}{{15}} = \dfrac{5}{{15}} = \dfrac{1}{3}$


(f) $\dfrac{5}{8} + \dfrac{3}{8}$

Ans: Add the numerator and then simplify the fraction.

$\dfrac{5}{8} + \dfrac{3}{8} = \dfrac{{5 + 3}}{8} = \dfrac{8}{8} = 1$


(g) $1 - \dfrac{2}{3}\left( {1 = \dfrac{3}{3}} \right)$

Ans: Subtract the numerator to get the result.

$1 - \dfrac{2}{3} = \dfrac{3}{3} - \dfrac{2}{3} = \dfrac{{3 - 2}}{3} = \dfrac{1}{3}$


(h) $\dfrac{1}{4} + \dfrac{0}{4}$

Ans: Add the numerator to get the result.

$\dfrac{1}{4} + \dfrac{0}{4} = \dfrac{{1 + 0}}{4} = \dfrac{1}{4}$


(i) $3 - \dfrac{{12}}{5}$

Ans: Write $3$ as a fraction with denominator as $5$ then subtract to get the result.

$3 - \dfrac{{12}}{5} = \dfrac{{15}}{5} - \dfrac{{12}}{5} = \dfrac{{15 - 12}}{5} = \dfrac{3}{5}$


3. Shubham painted $\dfrac{2}{3}$ of the wall space in his room. His sister Madhavi helped and painted $\dfrac{1}{3}$ of the wall space. How much did they paint together?

Ans: Fraction of wall painted by Shubham $ = \dfrac{2}{3}$

Fraction of wall painted by Madhavi $ = \dfrac{1}{3}$

Total painting by both of them $ = \dfrac{2}{3} + \dfrac{1}{3} = \dfrac{{2 + 1}}{3} = \dfrac{3}{3} = 1$ 

Therefore, they painted a complete wall.


4. Fill in the missing fractions:

(a) $\dfrac{7}{{10}} - \boxed{} = \dfrac{3}{{10}}$ 

Ans: Subtract the fraction to get the missing fraction.

$\dfrac{7}{{10}} - \dfrac{3}{{10}} = \dfrac{4}{{10}}$

The missing fraction is $\dfrac{4}{{10}}$

(b) $\boxed{} - \dfrac{3}{{21}} = \dfrac{5}{{21}}$ 

Ans: Add the fraction to get the missing fraction.

$\dfrac{5}{{21}} + \dfrac{3}{{21}} = \dfrac{8}{{21}}$

The missing fraction is $\dfrac{8}{{21}}$

(c) $\boxed{} - \dfrac{3}{6} = \dfrac{3}{6}$ 

Ans: Add the fraction to get the missing fraction.

$\dfrac{3}{6} + \dfrac{3}{6} = \dfrac{6}{6}$

The missing fraction is $\dfrac{6}{6}$.

(d) $\boxed{} + \dfrac{5}{{27}} = \dfrac{{12}}{{27}}$ 

Ans: Subtract the fraction to get the missing fraction.

$\dfrac{{12}}{{27}} - \dfrac{5}{{27}} = \dfrac{7}{{27}}$

The missing fraction is $\dfrac{7}{{27}}$


5. Javed was given $\dfrac{5}{7}$ of a basket of oranges. What fraction of oranges was left in the basket?

Ans: Total $ = 1$ 

Fraction of Orange left $ = 1 - \dfrac{5}{7}$ 

$ = \dfrac{7}{7} - \dfrac{5}{7} = \dfrac{{7 - 5}}{7} = \dfrac{2}{7}$ 

Thus, $\dfrac{2}{7}$ oranges were left in the basket.


NCERT Solutions for Class 6 Maths Chapter 7 Fractions Exercise 7.5

Opting for the NCERT solutions for Ex 7.5 Class 6 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 7.5 Class 6 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.


Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 6 students who are thorough with all the concepts from the Maths textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 6 Maths Chapter 7 Exercise 7.5 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.


Besides these NCERT solutions for Class 6 Maths Chapter 7 Exercise 7.5, there are plenty of exercises in this chapter which contain innumerable questions as well. All these questions are solved/answered by our in-house subject experts as mentioned earlier. Hence all of these are bound to be of superior quality and anyone can refer to these during the time of exam preparation. In order to score the best possible marks in the class, it is really important to understand all the concepts of the textbooks and solve the problems from the exercises given next to it.

 

Do not delay any more. Download the NCERT solutions for Class 6 Maths Chapter 7 Exercise 7.5 from Vedantu website now for better exam preparation. If you have the Vedantu app in your phone, you can download the same through the app as well. The best part of these solutions is these can be accessed both online and offline as well.