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NCERT Solutions for Class 6 Maths Chapter 6: Integers - Exercise 6.2

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NCERT Solutions for Class 6 Maths Chapter 6 (Ex 6.2)

Free PDF download of NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 (Ex 6.2) and all chapter exercises at one place prepared by an expert teacher as per NCERT (CBSE) books guidelines. Class 6 Maths Chapter 6 Integers Exercise 6.2 Questions with Solutions to help you to revise complete Syllabus and Score More marks. Register and get all exercise solutions in your emails.


Class:

NCERT Solutions for Class 6

Subject:

Class 6 Maths

Chapter Name:

Chapter 6 - Integers

Exercise:

Exercise - 6.2

Content-Type:

Text, Videos, Images and PDF Format

Academic Year:

2024-25

Medium:

English and Hindi

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Access NCERT Solutions for Class 6 Maths Chapter 6 – Integers

Exercise 6.2

1. Using the number line write the integer which is:

(i) 3 more than 5

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are given a statement, ‘3 more than 5’. We are required to find the integer using the number line. 

To do so, we will interpret the given statement. The given statement says three more than five. This means three places to the right of 5. So, we will first locate 5 on the number line. We will then move three places to the right of 5. 

This can be expressed on the number line as follows,


Using the number line we can found that the integer 3 more than 5 is 8.


Therefore, using the number line we have found that the integer 3 more than 5 is 8. 

(ii) 5 more than $ - 5$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are given a statement, ‘5 more than $ - 5$’. We are required to find the integer using the number line. 

To do so, we will interpret the given statement. The given statement says five more than $ - 5$. This means five places to the right of $ - 5$. So, we will first locate $ - 5$ on the number line. We will then move five places to the right of $ - 5$. 

This can be expressed on the number line as follows,


Using the number line we have found that the integer 5 more than (-5) is 0


Therefore, using the number line we have found that the integer 5 more than $ - 5$ is 0. 

(iii) 6 less than 2

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are given a statement, ‘6 less than 2’. We are required to find the integer using the number line. 

To do so, we will interpret the given statement. The given statement says six less than 2. This means six places to the left of 2. So, we will first locate 2 on the number line. We will then move six places to the left of 2. 

This can be expressed on the number line as follows,


Using the number line we have found that the integer 6 less than 2 is ( - 4).


Therefore, using the number line we have found that the integer 6 less than 2 is $ - 4$. 

(iv) 3 less than $ - 2$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are given a statement, ‘3 less than$ - 2$’. We are required to find the integer using the number line. 

To do so, we will interpret the given statement. The given statement says three less than$ - 2$. This means three places to the left of $ - 2$. So, we will first locate $ - 2$ on the number line. We will then move three places to the left of$ - 2$. 

This can be expressed on the number line as follows,


Using the number line we have found that the integer 3 less than (- 2) is (- 5).


Therefore, using the number line we have found that the integer 3 less than $ - 2$ is $ - 5$. 


2. Use number line and add the following integers:

(i) $9 + \left( { - 6} \right)$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are required to add the expression $9 + \left( { - 6} \right)$ using a number line.

To do so, we will first locate 9 on the number line starting from 0. After this, we will move six places to the left of 9. 

This can be expressed on the number line as follows,

Using the number line we have found that the value of the given expression 9 + (-6) is 3

Therefore, using the number line we have found that the value of the given expression $9 + \left( { - 6} \right)$ is 3. 

(ii) $5 + \left( { - 11} \right)$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are required to add the expression $5 + \left( { - 11} \right)$ using a number line.

To do so, we will first locate 5 on the number line starting from 0. After this, we will move eleven places to the left of 5. 

This can be expressed on the number line as follows,


Number line showing 5 + (-11)


Therefore, using the number line we have found that the value of the given expression $5 + \left( { - 11} \right)$ is $ - 6$. 

(iii) $\left( { - 1} \right) + \left( { - 7} \right)$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are required to add the expression $\left( { - 1} \right) + \left( { - 7} \right)$ using a number line.

To do so, we will first locate $ - 1$ on the number line starting from 0. After this, we will move seven places to the left of $ - 1$. 

This can be expressed on the number line as follows,


Using the number line we have found that the value of the given expression (-1) + (-7) is - 8


Therefore, using the number line we have found that the value of the given expression $\left( { - 1} \right) + \left( { - 7} \right)$ is $ - 8$. 

(iv) $\left( { - 5} \right) + 10$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are required to add the expression $\left( { - 5} \right) + 10$ using a number line.

To do so, we will first locate $ - 5$ on the number line starting from 0. After this, we will move ten places to the right of $ - 5$. 

This can be expressed on the number line as follows,


Number showing(-5)+10


Therefore, using the number line we have found that the value of the given expression $\left( { - 5} \right) + 10$ is 5. 

(v) $\left( { - 1} \right) + \left( { - 2} \right) + \left( { - 3} \right)$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are required to add the expression $\left( { - 1} \right) + \left( { - 2} \right) + \left( { - 3} \right)$ using a number line.

To do so, we will first locate $ - 1$ on the number line starting from 0. After this, we will move two places to the left of $ - 1$ to reach a number. Finally, we will move three places to the left of the number reached earlier. 

This can be expressed on the number line as follows,


using the number line we have found that the value of the given expression (-1) + (-2) + (-3) is -6


Therefore, using the number line we have found that the value of the given expression $\left( { - 1} \right) + \left( { - 2} \right) + \left( { - 3} \right)$ is $ - 6$.

(vi) $\left( { - 2} \right) + 8 + \left( { - 4} \right)$

Ans: Integer is a set of both positive and negative numbers including 0.

A number line is a line on which the numbers are marked at equal intervals.

We are required to add the expression $\left( { - 2} \right) + 8 + \left( { - 4} \right)$ using a number line.

To do so, we will first locate $ - 2$ on the number line starting from 0. After this, we will move eight places to the right of $ - 2$ to reach a number. Finally, we will move four places to the left of the number reached earlier. 

This can be expressed on the number line as follows,


Using the number line we have found that the value of the given expression (-2) + 8 + (-4) is 2


Therefore, using the number line we have found that the value of the given expression $\left( { - 2} \right) + 8 + \left( { - 4} \right)$ is 2.


3. Add without using number line:

(i) $11 + \left( { - 7} \right)$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $11 + \left( { - 7} \right)$, and we are required to add the terms without using the number line by solving them.

To do so, we will first simplify the signs. 

$11 + \left( { - 7} \right) = 11 - 7$

We will now subtract the numbers.

$11 - 7 = 4$

Therefore, the value of the given expression $11 + \left( { - 7} \right)$ is 4.

(ii) $\left( { - 13} \right) + \left( { + 18} \right)$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $\left( { - 13} \right) + \left( { + 18} \right)$, and we are required to add the terms without using the number line by solving them.

To do so, we will first simplify the signs. 

$\left( { - 13} \right) + \left( { + 18} \right) = \left( { - 13} \right) + 18$

We will now subtract the numbers.

$\left( { - 13} \right) + 18 = 5$

Therefore, the value of the given expression $\left( { - 13} \right) + \left( { + 18} \right)$ is 5.

(iii) $\left( { - 10} \right) + \left( { + 19} \right)$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $\left( { - 10} \right) + \left( { + 19} \right)$, and we are required to add the terms without using the number line by solving them.

To do so, we will first simplify the signs. 

$\left( { - 10} \right) + \left( { + 19} \right) = \left( { - 10} \right) + 19$

We will now subtract the numbers.

$\left( { - 10} \right) + 19 = 9$

Therefore, the value of the given expression $\left( { - 10} \right) + \left( { + 19} \right)$ is 9.

(iv) $\left( { - 250} \right) + \left( { + 150} \right)$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $\left( { - 250} \right) + \left( { + 150} \right)$, and we are required to add the terms without using the number line by solving them.

To do so, we will first simplify the signs. 

$\left( { - 250} \right) + \left( { + 150} \right) = \left( { - 250} \right) + 150$

We will now subtract the numbers.

$\left( { - 250} \right) + 150 =  - 100$

Therefore, the value of the given expression $\left( { - 250} \right) + \left( { + 150} \right)$ is $ - 100$.

(v) $\left( { - 380} \right) + \left( { - 270} \right)$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $\left( { - 380} \right) + \left( { - 270} \right)$, and we are required to add the terms without using the number line by solving them.

To do so, we will first simplify the signs. 

$\left( { - 380} \right) + \left( { - 270} \right) = \left( { - 380} \right) - 270$

We will now add the numbers.

$\left( { - 380} \right) - 270 =  - 650$

Therefore, the value of the given expression $\left( { - 380} \right) + \left( { - 270} \right)$ is $ - 650$.

(vi) $\left( { - 217} \right) + \left( { - 100} \right)$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $\left( { - 217} \right) + \left( { - 100} \right)$, and we are required to add the terms without using the number line by solving them.

To do so, we will first simplify the signs. 

$\left( { - 217} \right) + \left( { - 100} \right) = \left( { - 217} \right) - 100$

We will now add the numbers.

$\left( { - 217} \right) - 100 =  - 317$

Therefore, the value of the given expression $\left( { - 217} \right) + \left( { - 100} \right)$ is $ - 317$.


4. Find the sum of:

(i) 137 and $ - 354$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given two numbers, 137 and $ - 354$. We are required to find the sum of the two given numbers. To do so, we will first write an expression out of it. The required expression will be,

$137 + \left( { - 354} \right)$

We will now solve the expression. For that we will first simplify the signs. 

$137 + \left( { - 354} \right) = 137 - 354$

We will now add the numbers.

$137 - 354 =  - 217$

Therefore, the sum of the given two numbers 137 and $ - 354$is $ - 217$.

(ii) $ - 52$ and 52

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given two numbers,$ - 52$ and 52. We are required to find the sum of the two given numbers. To do so, we will first write an expression out of it. The required expression will be,

$\left( { - 52} \right) + \left( { + 52} \right)$

We will now solve the expression. For that we will first simplify the signs. 

$\left( { - 52} \right) + \left( { + 52} \right) = \left( { - 52} \right) + 52$

We will now add the numbers.

$\left( { - 52} \right) + 52 = 0$

Therefore, the sum of the given two numbers $ - 52$and 52 is 0.

(iii) $ - 213$, 39 and 192

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given three numbers, $ - 213$, 39 and 192. We are required to find the sum of the three given numbers. To do so, we will first write an expression out of it. The required expression will be,

$\left( { - 213} \right) + \left( { + 39} \right) + \left( { + 192} \right)$

We will now solve the expression. For that we will first simplify the signs. 

$\left( { - 213} \right) + \left( { + 39} \right) + \left( { + 192} \right) = \left( { - 213} \right) + 39 + 192$

We will now add the numbers with the same sign.

$\left( { - 213} \right) + 39 + 192 = \left( { - 213} \right) + 231$

Finally, we will solve the remaining expression. On doing so,

$\left( { - 213} \right) + 231 = 18$

Therefore, the sum of the given two numbers $ - 213$, 39 and 192 is 18.

(iv) $ - 50$, $ - 200$ and 300

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given three numbers, $ - 50$, $ - 200$ and 300. We are required to find the sum of the three given numbers. To do so, we will first write an expression out of it. The required expression will be,

$\left( { - 50} \right) + \left( { - 200} \right) + \left( { + 300} \right)$

We will now solve the expression. For that we will first simplify the signs. 

$\left( { - 50} \right) + \left( { - 200} \right) + \left( { + 300} \right) = \left( { - 50} \right) - 200 + 300$

We will now add the numbers with the same sign.

$\left( { - 50} \right) - 200 + 300 = \left( { - 250} \right) + 300$

Finally, we will solve the remaining expression. On doing so,

$\left( { - 250} \right) + 300 = 50$

Therefore, the sum of the given two numbers $ - 50$, $ - 200$ and 300 is 50.


5. Find the value of:

(i) $\left( { - 7} \right) + \left( { - 9} \right) + 4 + 16$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $\left( { - 7} \right) + \left( { - 9} \right) + 4 + 16$, and we are required to find the value of the given expression. 

To do so, we will first simplify the signs. 

$\left( { - 7} \right) + \left( { - 9} \right) + 4 + 16 = \left( { - 7} \right) - 9 + 4 + 16$

After this, we will now add the terms with the same signs. 

$\left( { - 7} \right) - 9 + 4 + 16 =  - 16 + 20$

We will now add the numbers.

$ - 16 + 20 = 4$

Therefore, the value of the given expression $\left( { - 7} \right) + \left( { - 9} \right) + 4 + 16$ is 4.

(ii) $37 + \left( { - 2} \right) + \left( { - 65} \right) + \left( { - 8} \right)$

Ans: Integer is a set of both positive and negative numbers including 0. 

We are given an expression $37 + \left( { - 2} \right) + \left( { - 65} \right) + \left( { - 8} \right)$, and we are required to find the value of the given expression. 

To do so, we will first simplify the signs. 

$37 + \left( { - 2} \right) + \left( { - 65} \right) + \left( { - 8} \right) = 37 - 2 - 65 - 8$

After this, we will now add the terms with the same signs. 

$37 - 2 - 65 - 8 = 37 - 75$

We will now add the numbers.

$37 - 72 =  - 38$

Therefore, the value of the given expression $37 + \left( { - 2} \right) + \left( { - 65} \right) + \left( { - 8} \right)$ is $ - 38$.


NCERT Solutions for Class 6 Maths Chapter 6 Integers Exercise 6.2

Opting for the NCERT solutions for Ex 6.2 Class 6 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 6.2 Class 6 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.

Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 6 students who are thorough with all the concepts from the Maths textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 6 Maths Chapter 6 Exercise 6.2 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.

Besides these NCERT solutions for Class 6 Maths Chapter 6 Exercise 6.2, there are plenty of exercises in this chapter which contain innumerable questions as well. All these questions are solved/answered by our in-house subject experts as mentioned earlier. Hence all of these are bound to be of superior quality and anyone can refer to these during the time of exam preparation. In order to score the best possible marks in the class, it is really important to understand all the concepts of the textbooks and solve the problems from the exercises given next to it. 

Do not delay any more. Download the NCERT solutions for Class 6 Maths Chapter 6 Exercise 6.2 from Vedantu website now for better exam preparation. If you have the Vedantu app in your phone, you can download the same through the app as well. The best part of these solutions is these can be accessed both online and offline as well.