Revision Notes for CBSE Class 8 Maths Chapter 11 - Free PDF Download
Perimeter: A simple closed figure's perimeter is the length of its boundary.
Rectangle$=2\left( l+b \right)$
Square$=4a$
Parallelogram$=2$(sum of adjacent sides)
Area: The size of a territory encompassed in a simple closed figure is referred to as its area.
The area of a trapezium is equal to half of the sum of the parallel sides' lengths divided by the perpendicular distance between them.
\[\begin{align} & \text{Area of a rhombus = half the product of its diagonals}\text{. }\!\!~\!\!\text{ } \\& \text{Triangle = }\dfrac{1}{2}\text{ }\!\!~\!\!\text{ }\times \text{ base }\times \text{ height }\!\!~\!\!\text{ } \\ \end{align}\]
Diagonal of:
Rectangle$=\sqrt{{{l}^{2}}+{{b}^{2}}}$
Square$=\sqrt{2a}$
A solid's surface area is equal to the sum of its face areas.
Surface area of cuboid \[\text{=2}\left( lb+bh+lh \right)\]
Surface area of cube $=6{{l}^{2}}$
Surface area of a cylinder $=2\pi r\left( r+h \right)$
The volume of a solid is the amount of space it takes up.
Volume of
a cuboid $=l\times b\times h$
a cube $={{l}^{3}}$
a cylinder $=\pi {{r}^{2}}h$
Few basic measurements value are as follows:
$\left( i \right)1c{{m}^{3}}=1mL$
$\left( ii \right)1L=1000c{{m}^{3}}$
$\left( iii \right)1{{m}^{3}}=1000000c{{m}^{3}} $
$=1000L$
Download Maths Class 8 Mensuration Notes - Free PDF
Vedantu is an online platform that initiates to provide free Revision Notes Maths Class 8 Chapter 11 and other study material for students. These can be easily downloaded and students can easily use it as future reference. Class 8 Chapter 11 will become quite easy for you to study if you refer to Mensuration Class 8 Chapter 11 NCERT Solutions along with Mensuration Class 8 Notes provided by Vedantu.
Maths Class 8 Mensuration Notes offered by Vedantu is important for aspiring students who are aiming to score top marks in their examination. This revision notes Class 8 Maths Chapter 11 will help you in preparing for your upcoming Class 8 examination as well as other competitive exams like Olympiad. Opt for Maths Class 8 Mensuration notes online to learn about various shortcut techniques that help you to solve numerical questions in a step by step manner.
Download revision notes Class 8 Maths Chapter 11 free PDF just with a single click on the PDF link given below and gain access anytime and anywhere at your convenience. Mastering the revision notes will help you get an idea about the type of questions and time required to solve the questions given in Chapter 11 Mensuration. This will enable you to improve your performance and understanding of the chapter.
A Quick Glimpse of Class 8 Chapter 11 Mensuration
This chapter 11 titled Mensuration introduces you with different geometrical figures and their parameters like perimeter, area, surface area, length, volume, lateral surface area, etc. In your previous classes, you must have learned that for a close figure, the perimeter is defined as the distance around its boundary and the area of the closed figure is the region covered by it. You must have also learned to calculate the area and perimeter of different plane figures such as circles, triangles, rectangles, etc. You must also be aware of the formulas used to calculate the area of pathways or borders in a rectangular shape.
In this chapter Mensuration, you will learn to find the perimeter and area of other closed figures such as Quadrilateral. You will also learn to find the surface area and volume of solids such as a cube, cuboid, and cylinder.
Students should have clarity on the important formulas and concepts of Mensuration so that they do not face any issues in solving the numerical questions related to Mensuration in their CBSE Class 8 exams.
Topics and Subtopics Covered in Chapter 11 Mensuration
Here, you can find the list of the topics and subtopics covered in Chapter 11 Mensuration.
(Table will be updated soon)
Mensuration Important Formulas
Some important Mensuration formulas are discussed below:
Area of Trapezium
½ of the sum of the length of parallel sides * Perpendicular distance between them.
Surface Area of Cuboid - 2 (LB + BH + HL) or 2 (Length * Breadth + Breadth * Height + Length * Height )
Surface Area of Cube - 6 * side²
Surface Area of Cylinder - 2radius ( radius + height)
Volume of Cuboid - LBH or (Length * Breadth * Height)
Volume of Cube - Side³
Volume of Cylinder - πr²h
In the above formula
H - Height of cylinder
To get a detailed view of this chapter, download our latest Class 8 Maths revision notes Chapter 11 free PDF. This free PDF will help you to understand all the important concepts related to Mensuration and solve all your doubts regarding the chapter.
Key Highlights of CBSE Class 8 Maths Revision Notes Chapter 11
Some of the key highlights of CBSE Class 8 Maths revision notes Chapter 11 are discussed below:
1. Clear Understanding, Practice, and Revision: Easily grasp, practice, and revise essential concepts of Chapter 11 with these revision notes for Class 8 Maths.
2. Crisp and Precise Coverage: The revision notes succinctly define important topics, providing a clear and concise understanding.
3. Time-Saving Resource: Save valuable time by accessing all key concepts and formulas in a well-organized sequence in the Maths Class 8 Mensuration notes.
4. Effective Problem Solving Tips: Vedantu's Mensuration notes offer important tips for solving numerical questions efficiently, enhancing problem-solving skills.
5. Expert-Written and Structured: Crafted by subject experts at Vedantu, these notes are neatly structured, making learning attractive and simpler for students.
Conclusion
For an enhanced comprehension of this subject, NCERT - Class 8 Maths Chapter 11 - Mensuration thoughtfully prepared by experienced educators at Vedantu is your invaluable companion. These notes break down the complexities of Mensuration into easily digestible sections, helping you grasp new concepts, master formulas, and navigate through questions effortlessly quickly in the last minute as well. By immersing yourself in these notes, you not only prepare for your studies more efficiently but also develop a profound understanding of the subject matter.
FAQs on Mensuration Class 8 Notes CBSE Maths Chapter 11 (Free PDF Download)
1. What is the definition of Mensuration according to Class 8?
Ans: Measuring the area and perimeter of different shapes is known as mensuration. The shapes include triangle, trapezium, rectangle, square, etc. You can find their area by using the required formula. The notes are free of cost. The solutions are available on the Vedantu Mobile app as well. Some example questions are as follows:
1. Find the area of a square whose side is 30 m.
Answer: Formula of the area of square= (Side)^2
Sise as given in question = 30 m.
Thus, the area of the square is = (30)2 = 900 m^2.
2. Find the perimeter of a triangle with two equal sides of 5 cm and one side of 10 cm.
Answer: The formula of the triangle is :
Triangle of given parameter= sum all the three sides of the triangle
= (5 + 5 + 10)cm.
= 20 cm.
2. A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2? (If required you can split the tiles in whatever way you want to fill up the corners)
Ans:
The base of the floor title is given as = 24 cm = 0.24 m
Height of the corresponding floor title= 10 cm = 0.10 m
Area of the floor title is= Base×Altitude
= 0.24×0.10
= 0.024
Thus the area of the flooring title is =0.024m2
Number of tiles that will be required for covering the floor= Area of floor/Area of one tile = 1080/0.024
= 45000 tiles
3. Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of the diagonals is 8 cm long, find the length of the other diagonal.
Ans: The formula of rhombus and parallelogram are similar,
The formula we get of a rhombus is = Base×Altitude
Placing the values, we get,
Area of rhombus = 6×4 = 24
The area of a rhombus is 24 cm2
The formula of rhombus = (½)×d1d2
Through the substitution formula, we get
24 = (½)×8×d2
d2 = 6
So the diagonal length is 6 cm
4. The floor of a building consists of 3000 rhombus-shaped tiles and each of its diagonals is 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m^2 is Rs. 4.
Ans:
Given length of the diagonal is, d1 = 45 cm and d2= 30 cm
We get the Area of one tile after putting the value = (½)d1d2
= (½)×45×30 = 675
Hence it isis 675 cm2
Area of 3000 tiles is
= 675×3000 = 2025000 cm2
= 2025000/10000
= 202.50 m2
cost for polishing the floor per sq. meter = 4
Cost we get per 202.50 sq. meter = 4×202.50 = 810
Total cost is= 810
5.What all things students will learn from Chapter 11 of Class 8 Maths?
Ans: The surface area and volume of these figures are thoroughly studied by the children. This chapter is vital not just for students in class 8, but also for students in higher grades. As a result, children must establish a solid foundation in this subject.
Chapter 11 of the NCERT answers for Class 8 maths is knowledge-packed. Aside from that, pupils are taught how to use visualization to their advantage. If students are asked to find the surface area of a cube, for example, they must mentally visualize the shape and comprehend its components to answer problems based on it.