
The coordination number of an atom in a fcc lattice is:
(A) 12
(B) 8
(C) 4
(D) 6
Answer
507.7k+ views
Hint:
In a fcc lattice there is one constituent particle at each corner and one at the centre of each face. The number of nearest neighbours is called coordination number.
Complete step by step answer:
A face centred cubic unit cell contains atoms at all the corners of the unit cell and at the centre of all the faces of the cube.
Coordination number is the number of other atoms that each atom in a crystalline solid contacts. In simple words the number of nearest neighbours of an atom forms the coordination number.
In an fcc unit cell the total number of atoms is:
(a) 8 corner atoms with each one contributing $1/8$ of it to the unit cell = 1 atom
(b) 6 face centre atoms with each one contributing $1/2$ of it to the unit cell = 3 atoms
So, a total of 4 atoms in an fcc unit cell.

In an fcc structure atoms are packed as closely to each other as possible and the 4 atoms occupy 74% of the volume of the unit cell. It has unit cell vectors a = b = c and interaxial angles α = β = γ = 90$^{\circ}$
In an fcc lattice the face centre atoms are the nearest atoms and one corner atom is surrounded by 4 faces in the x-plane, 4 faces in the y-plane and 4 faces in the z-plane. So, every corner atom is surrounded by (4 × 3) = 12 face centre atoms. Since they are the nearest they form the coordination number.
Also if we consider the atom at the face centre, it is surrounded by 4 corner atoms of its own plane and the 8 adjacent face centred atoms (4 from above and 4 from below). This also makes the coordination number to be 12.
Hence, the coordination number of an fcc lattice is 12.
So, the correct option is (A).
Note:
While imagining the structure of the fcc unit cell, always be precise regarding the position of the atoms. Also remember that there are 4 faces associated with the 3 axes.
In a fcc lattice there is one constituent particle at each corner and one at the centre of each face. The number of nearest neighbours is called coordination number.
Complete step by step answer:
A face centred cubic unit cell contains atoms at all the corners of the unit cell and at the centre of all the faces of the cube.
Coordination number is the number of other atoms that each atom in a crystalline solid contacts. In simple words the number of nearest neighbours of an atom forms the coordination number.
In an fcc unit cell the total number of atoms is:
(a) 8 corner atoms with each one contributing $1/8$ of it to the unit cell = 1 atom
(b) 6 face centre atoms with each one contributing $1/2$ of it to the unit cell = 3 atoms
So, a total of 4 atoms in an fcc unit cell.

In an fcc structure atoms are packed as closely to each other as possible and the 4 atoms occupy 74% of the volume of the unit cell. It has unit cell vectors a = b = c and interaxial angles α = β = γ = 90$^{\circ}$
In an fcc lattice the face centre atoms are the nearest atoms and one corner atom is surrounded by 4 faces in the x-plane, 4 faces in the y-plane and 4 faces in the z-plane. So, every corner atom is surrounded by (4 × 3) = 12 face centre atoms. Since they are the nearest they form the coordination number.
Also if we consider the atom at the face centre, it is surrounded by 4 corner atoms of its own plane and the 8 adjacent face centred atoms (4 from above and 4 from below). This also makes the coordination number to be 12.
Hence, the coordination number of an fcc lattice is 12.
So, the correct option is (A).
Note:
While imagining the structure of the fcc unit cell, always be precise regarding the position of the atoms. Also remember that there are 4 faces associated with the 3 axes.
Recently Updated Pages
Is PPh3 a strong ligand class 12 chemistry JEE_Main

Full name of DDT is A 111trichloro22bispchlorophenyl class 12 chemistry JEE_Main

Sodium acetate on heating with soda lime produce A class 12 chemistry JEE_Main

Find the isoelectric point pI of Lysine A 556 B 974 class 12 chemistry JEE_Main

The order of basicity among the following compounds class 12 chemistry JEE_Main

The number of isomers in C4H10O are a7 b8 c6 d5 class 12 chemistry JEE_Main

Trending doubts
Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Understanding Centrifugal Force in Physics

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding Electromagnetic Waves and Their Importance

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
Understanding Average and RMS Value in Electrical Circuits

NCERT Solutions For Class 12 Chemistry Chapter 9 Amines

Understanding Excess Pressure Inside a Liquid Drop

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 4 The D and F Block Elements

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

Understanding Elastic Collisions in Two Dimensions

