Answer
Verified
37.5k+ views
Hint: We can understand from the question that we have to produce Carbon dioxide gas. Hence we should think along the lines of using carbonates or bicarbonates of some substance that must be reacted with acetic acid (commonly known as Vinegar).
Complete step by step answer:
1 mole of Sodium bicarbonate (Commonly known as baking soda) reacting with 1mole of acetic acid produces 1 mole Carbon dioxide gas, 1 mole of Sodium acetate and 1 mole of water.
Hence, the substance we need to add to acetic acid is Sodium Bicarbonate.
The chemical reaction is as follows:
\[NaHC{O_3}\,(s) + C{H_3}COOH(l) \to \,C{O_2}(g)\, + {H_2}O(l)\, + C{H_3}COONa\]
The gas produced can be tested in the laboratory by passing it through lime water which is transparent. If we see that the lime water turns milky due to formation of Calcium carbonate we can conclude that the gas evolved in the experiment was Carbon dioxide. The gas produced must also be passed through acidified Potassium dichromate solution where it should not produce any observable change.
Additional Information:
We can perform a simple experiment to ascertain if Carbon dioxide is produced. We should take 2 tablespoons of baking soda and add a teaspoon of vinegar to it. We can see that a gas is evolved with effervescence. This gas is Carbon dioxide.
Note: While testing for Carbon dioxide, we must remember to perform the acidified Potassium dichromate test after the lime water test as both Sulphur dioxide and Carbon dioxide turns lime water milky but Sulphur dioxide solution turns acidified potassium chromate solution green whereas carbon dioxide shows no change.
Complete step by step answer:
1 mole of Sodium bicarbonate (Commonly known as baking soda) reacting with 1mole of acetic acid produces 1 mole Carbon dioxide gas, 1 mole of Sodium acetate and 1 mole of water.
Hence, the substance we need to add to acetic acid is Sodium Bicarbonate.
The chemical reaction is as follows:
\[NaHC{O_3}\,(s) + C{H_3}COOH(l) \to \,C{O_2}(g)\, + {H_2}O(l)\, + C{H_3}COONa\]
The gas produced can be tested in the laboratory by passing it through lime water which is transparent. If we see that the lime water turns milky due to formation of Calcium carbonate we can conclude that the gas evolved in the experiment was Carbon dioxide. The gas produced must also be passed through acidified Potassium dichromate solution where it should not produce any observable change.
Additional Information:
We can perform a simple experiment to ascertain if Carbon dioxide is produced. We should take 2 tablespoons of baking soda and add a teaspoon of vinegar to it. We can see that a gas is evolved with effervescence. This gas is Carbon dioxide.
Note: While testing for Carbon dioxide, we must remember to perform the acidified Potassium dichromate test after the lime water test as both Sulphur dioxide and Carbon dioxide turns lime water milky but Sulphur dioxide solution turns acidified potassium chromate solution green whereas carbon dioxide shows no change.
Recently Updated Pages
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
The path difference between two waves for constructive class 11 physics JEE_MAIN
What is the difference between solvation and hydra class 11 chemistry JEE_Main
IfFxdfrac1x2intlimits4xleft 4t22Ft rightdt then F4-class-12-maths-JEE_Main
Sodium chloride is purified by passing hydrogen chloride class 11 chemistry JEE_Main
Consider the following oxyanions PO43P2O62SO42MnO4CrO4S2O52S2O72 class 11 chemistry JEE_Main
Other Pages
Formula for number of images formed by two plane mirrors class 12 physics JEE_Main
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
Explain the construction and working of a GeigerMuller class 12 physics JEE_Main
A currentcarrying coil is placed in a magnetic field class 12 physics JEE_Main
In the given circuit the current through the 5mH inductor class 12 physics JEE_Main
In a family each daughter has the same number of brothers class 10 maths JEE_Main