## NCERT Solutions for Class 8 Maths Chapter 9 (EX 9.2)

## FAQs on NCERT Solutions for Class 8 Maths Chapter 9: Mensuration - Exercise 9.2

1. Which website provides NCERT Solutions for Class 8 Maths Chapter 9 Mensuration Exercise 9.2?

NCERT Solutions for Class 8 CBSE Mathematics Chapter 9 Mensuration Exercise 9.2 as well as other exercises are available on Vedantu. Vedantu, a well-renowned online learning platform, provides the free PDF of exercise-wise NCERT Solutions for 8 Maths Chapter 9 Mensuration to help students prepare for exams and have a clear understanding of the chapter. These solutions are prepared by subject matter experts who have years of teaching experience and in-depth subject knowledge. They are also familiar with the board guidelines and NCERT syllabus. Without any further ado, students can download these solutions and clear their doubt regarding the exercise.

2. How can NCERT Solutions for Class 8 Maths Chapter 9 Mensuration Exercise 9.2 help in exam preparation?

NCERT Solutions for Exercise 9.2 Chapter 9 Mensuration of CBSE Class 8 is a great help to students. Students can avail the free PDF of NCERT Solutions for Class 8 Maths Chapter 9 Exercise 9.2 and learn the chapter effectively at their convenience. These solutions include step-wise explanations for the exercise problems. Vedantu’s NCERT Solutions for Class 8 Maths Chapter 9 as well as other chapters are readily available over the internet and are created by experienced tutors. Mensuration is a lengthy chapter which consists of four exercises. In order to solve the exercise correctly, students must seek proper guidance and download these solutions available on Vedantu’s site.

3. What will students learn from the third exercise of Class 8 Maths Chapter 9 Mensuration?

Students will learn about different solid shapes and how to solve problems based on them in Exercise 9.2 of Class 8 Maths Chapter 9 Mensuration. These shapes include cube, cuboid and cylinder. Students will learn how to calculate surface areas of these three-dimensional objects in this exercise. For having a clear understanding of the topic, students can refer to NCERT Solutions for Class 8 Maths Chapter 9 Mensuration Exercise 9.2 available in free PDF form on Vedantu.

4. How to calculate the surface areas of a cube, cuboid and cylinder?

The formulas to calculate the surface areas of cube, cuboid and cylinder are given below:

**Surface Area of a Cuboid =**2(lb + bh + hl)

l=Length, b= Breadth and h=Height

**Surface Area of a Cube =**6*a^{2}

a= Edge Length

**Lateral Surface Area of a Cylinder =**2πrh**Total Surface Area of a Cylinder =**2πr(r + h)

r= Radius of the Base

h= Height of the Cylinder

5. What are the theories or ideas on which Exercise 9.2 of Chapter 9 Class 8 Maths is based on?

The list of the topics on which Exercise 9.2 of Chapter 9 Class 8 is based on:

Solid Shapes

Cuboid

Cylinder

Cone

Cube

Pyramid

Surface Area of Cuboid, Cube and Cylinder

In the NCERT book, many examples are given which are related to the above-mentioned topics. Students must solve these examples before solving the exercise. The students will comprehend the concepts if they solve the examples and the exercise.

6. Provide some information about cube, cuboids and cylinders, according to Exercise 9.2 of Chapter 9 of Class 8 Maths.

**(a) Cube –** It is a 3-D shape whose faces are in the shape of a square. The cube has eight vertices, 12 edges and six identical plane faces. There are five parts of the cube vertex, edge, face, space diagonals and face diagonals.

**(b) Cuboid – **The opposite faces of the cuboid are equal and in a rectangular shape. It is also one of the 3-D shapes. There are 12 edges, six faces and eight vertices in the cuboid. The volume and area of the cuboid are calculated in length, width and height.

**(c) Cylinder – **A cylinder is curved from the middle and has circular plane surfaces on the top and the bottom. It contains two edges, zero vertices, two plane surfaces and one curved surface.

7. What will be the height of the cylinder having a radius of 7cm and the total surface area is 968cm sq.?

Let us assume that the height of the cylinder is ‘h’ cm. We are given that the radius is 7 cm and the total surface area is 968cm sq.

Therefore, by using the formula we can find out the height of the cylinder.

Cylinder's total surface area = 2 π r (h + r)

2 × 3.14 × 7 (h + 7) = 968

44 × (h + 7) = 968

h = 15cm

Thus, the height of the cylinder is 15cm.

8. A cuboidal box has external measures as 80cm × 30cm × 40cm. All the faces and the base need to be covered. What will be the area of paper needed?

We are given external measures.

Length of the box = 80cm

Width of the box = 30cm

Height of the box = 40cm

As all the faces and the base are needed to be covered, therefore,

Base area = l × b = 80 × 30 = 2400cm sq.

Side face area = b × h = 30 × 40 = 1200cm sq.

Back face area = l × h = 80 × 40 = 3200cm sq.

Total area = base area + back face area + (2 × side face area)

2400 + 3200 + (2 × 1200) = 8000cm sq.

9. What are the best study materials for preparing Exercise 9.2 of Chapter 9 Class 8 Maths?

To prepare Exercise 9.2 of Chapter 9 Class 8 Maths, students need the best study materials. They should give priority to the NCERT book. Read the theory from this book so that you can solve each question of the exercise. Practice the examples before solving the exercise. Take help from the Vedantu website or the Vedantu app, as it will provide you with all the NCERT Solutions free of cost. You can also solve extra questions available on Vedantu to understand the topic better.