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NCERT Solutions for Class 8 Maths Chapter 4 - Data Handling Exercise 4.1

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Class 8 Maths NCERT Solutions Chapter 4 Data Handling Exercise 4.1 - FREE PDF Download

NCERT Solutions for class 8 Maths Ex 4.1, Data Handling, focuses on teaching students how to collect, organize, and interpret data effectively. This chapter is crucial as it lays the foundation for understanding various data representation methods, such as bar graphs, histograms, and pie charts, which are essential for solving real-world problems.

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Table of Content
1. Class 8 Maths NCERT Solutions Chapter 4 Data Handling Exercise 4.1 - FREE PDF Download
2. Glance on NCERT Solutions Class 8 Maths Chapter 4 Exercise 4.1 | Vedantu
3. Formula Used in Class 8 Chapter 4 Exercise 4.1 
4. Access NCERT Solutions for Class 8 Maths Chapter 4 Data Handling Exercise 4.1
5. Class 8 Maths Chapter 4: Exercises Breakdown
6. CBSE Class 8 Maths Chapter 4 Other Study Materials
7. Chapter-Specific NCERT Solutions for Class 8 Maths
FAQs


Class 8 Maths Exercise 4.1 Solutions PDF provides practical application of these concepts, offering problems that help students practice organizing and interpreting data. Understanding the proper methods to solve the NCERT solutions for Class 8 Maths will help students tackle different types of exam questions. Mastery of these solutions will enhance their problem-solving speed and boost their self-confidence, as highlighted by Vedantu.


Glance on NCERT Solutions Class 8 Maths Chapter 4 Exercise 4.1 | Vedantu

  • A pictograph is a way of representing data using images or symbols where each image or symbol represents a certain number of items.

  • A bar graph displays data using rectangular bars where the length of each bar is proportional to the value it represents.

  • A double bar graph is used to compare two sets of data side by side using pairs of bars for each category.

  • Circle graphs, also known as pie charts, represent data as slices of a circle, where each slice corresponds to a proportion of the whole.

  • A pie chart is a circular chart divided into sectors, each representing a fraction of the total data.

  • Circle graph or pie chart both refer to a circular chart where data is visualized as segments of a circle, showing parts of a whole.

  • This article contains exercise notes, important questions, exemplar solutions, exercises and video links for class 8 exercise 4.1 - Data Handling, which you can download as PDFs.

  • There are five questions in class 8 maths exercise 4.1 solutions pdf  which are fully solved by experts at Vedantu.


Formula Used in Class 8 Chapter 4 Exercise 4.1 

  • Mean (Average): Mean = $\dfrac{\sum observations}{number of observations}$

Access NCERT Solutions for Class 8 Maths Chapter 4 Data Handling Exercise 4.1

1. A survey was made to find the type of music that a certain group of young people liked in a city. The pie chart shows the findings of this survey. From this pie chart, answer the following: 


Pie chart Representing type of Music


Pie chart Representing type of Music


(i) If \[{\mathbf{20}}\] people liked classical music, how many young people were surveyed?

Ans: In this part it is given that 20 people liked classical music and we have to find the total number of people who were surveyed.

So, from a given pie chart it is given that \[10\% \] peoples like classical music.

Let the total number of people who were surveyed be $x$.

So, \[10\% \] of $x$ must be equal to \[20\].

That is,

$x \times \frac{{10}}{{100}} = 20$

$\frac{x}{{10}} = 20$

By cross multiplication we get,

$x = 200$

So, \[200\] young people were surveyed.


(ii) Which type of music is liked by the maximum number of people? 

Ans: In this part we have to find which type of music is liked by the maximum number of people.

So, from the given pie chart it is clear that light music is liked by the maximum number of people (\[40\% \]of the total number of people which is maximum in all categories).


(iii) If a cassette company were to make \[{\mathbf{1000}}\] CDs, how many of each type would they make?

Ans: In this part it is given that if a cassette company were to make \[100\] CDs, then how many of each type would they make?


For CDs of classical music:$$

Cassette Company has to make \[10\% \]CDs of classical music.

That is, \[10\% \]of the total number of CDs.

Let, \[x\]be the number of classical music CDs made by the company.

So,

$x = 1000 \times \frac{{10}}{{100}}$

$x = 100$

That is, the number of classical music CDs made by the company is\[100\].


For CDs of semi classical music:

Cassette Company has to make \[20\% \] CDs of semi classical music.

That is, \[20\% \] of the total number of CDs.

Let, \[y\] be the number of semi classical music CDs made by the company.

So, $y = 1000 \times \frac{{20}}{{100}}$

 $y = 200$

That is, the number of semi classical music CDs made by the company is \[200\].


For CDs of light music:

Cassette Company has to make \[40\% \] CDs of light music.

That is, \[40\% \]of the total number of CDs.

Let, \[z\] be the number of light music CDs made by the company.

So, $z = 1000 \times \frac{{40}}{{100}}$

$z = 400$

That is, the number of light music CDs made by the company is\[400\].


For CDs of Folk music:

Cassette Company has to make \[30\% \] CDs of Folk music.

That is, \[30\% \]of the total number of CDs.

Let $t$ be the number of Folk music CDs made by the company.

So, $t = 1000 \times \frac{{30}}{{100}}$

$t = 300$

That is, the number of Folk music CDs made by the company is \[300\].


2. A group of \[{\mathbf{360}}\] people were asked to vote for their favorite season from the three seasons: rainy, winter, and summer.

Season

No. of Votes

Summer

\[90\]

Rainy

\[120\]

Winter

\[150\]


(i) Which season got the most votes?

Ans: From the given table it is clear that winter season got the most votes

That is,\[150\]votes.


(ii) Find the central angle of each sector.

Ans: In this part we have to find the central angle of each sector. That is the angle made by each sector at the Centre of circle or pie chart.

So, the total number of votes is \[360\].

Therefore, the central angle of summer season$ = \frac{{90 \times {{360}^ \circ }}}{{360}}$

\[ = 90\]

The central angle of rainy season $ = \frac{{120 \times {{360}^ \circ }}}{{360}}$

\[ = {\text{ }}120\]

The central angle of winter season \[\]$ = \frac{{150 \times {{360}^ \circ }}}{{360}}$

\[ = {\text{ }}150\]


(iii) Draw a pie chart to show this information.

Ans: To draw the pie chart we use the central angle which is calculated in the part (i) of this question.

The pie chart of the following data is as follows:


Pie chart representing favorite seasons of people


Pie chart representing favorite seasons of people


3. Draw a pie chart showing the following information. The table shows the colours preferred by a group of people.


Find the Proportion of each sector


Colours

Number of People

Blue

Green

Red

Yellow

\[{\mathbf{18}}\]

0

\[{\mathbf{6}}\]

\[{\mathbf{3}}\]

Total

\[{\mathbf{36}}\]


Ans: To draw the pie chart of the following information we have to calculate the central angle of each sector first.

Total central angle \[ = 360\]

Total number of people \[ = {\text{ }}36\]

So, the central angle of Blue colour$ = \frac{{18 \times {{360}^ \circ }}}{{36}}$

$ = {180^ \circ }$

The central angle of Green colour$ = \frac{{9 \times {{360}^ \circ }}}{{36}}$

$ = {90^ \circ }$

The central angle of Red colour$ = \frac{{6 \times {{360}^ \circ }}}{{36}}$

$ = {60^ \circ }$

The Central angle of Yellow colour$ = \frac{{3 \times {{360}^ \circ }}}{{36}}$

$ = {30^ \circ }$

The pie chart is as follows:


Pie chart representing colours preferred by a group of people


Pie chart representing colours preferred by a group of people


4. The adjoining pie chart gives the marks scored in an examination by a student in Hindi, English, Mathematics, Social Science and Science. If the total marks obtained by the students were\[{\mathbf{540}}\], answer the following questions: 


Pie chart representing the marks scored


Pie chart representing the marks scored


(i) In which subject did the student score \[{\mathbf{105}}\] marks? 

(Hint: for \[{\mathbf{540}}\] marks, the central angle =\[{\mathbf{360}}\]. So, for \[{\mathbf{105}}\] marks, what is the central angle?)

Ans: Given, Total marks\[ = 540\].

And we know that the central angle\[ = 360^ \circ\].

So, the central angle made by the sector having 105 marks$ = \frac{{105 \times {{360}^ \circ }}}{{540}}$

$ = {70^ \circ }$

Therefore, In Hindi students score \[105\] marks.


(ii) How many more marks were obtained by the student in Mathematics than in Hindi? 

Ans: From the previous part we know that the student scores \[105\] marks in Hindi.

Now we have to calculate the marks in Mathematics.

 We know that the central angle made by the Mathematics sector$ = {90^ \circ }$.

And the total scored marks\[ = 540\].

Let the marks scored in Mathematics be $x$.

Therefore, 

$\frac{{x \times {{360}^ \circ }}}{{540}} = {90^ \circ }$

\[x = \frac{{90 \times 54}}{{36}}\]

So, 

\[x = 135\]

Now, the difference of marks scored in Mathematics and Hindi \[ = {\text{ }}30\].

So, the student obtained \[30\] more marks in Mathematics than in Hindi.


(iii) Examine whether the sum of the marks obtained in Social Science and Mathematics is more than that in Science and Hindi. 

(Hint: Just study the central angles)

Ans: From the previous parts we know that the student score \[105\] marks in Hindi and \[135\] marks in Mathematics.

Now we have to calculate the marks in Science and Social Science.

For Science:

We know that the central angle made by the Science sector $ = {80^ \circ }$.

And the total scored marks \[ = 540\].

Let the marks scored in science be y.

Therefore, 

$\frac{{y \times 360}}{{540}} = 80$

$y = \frac{{80 \times 54}}{{36}}$

So, $y = 120$

That is, students score \[120\] marks in science.

For Social Science:

As we know that the central angle is made by the Social Science sector $ = {65^ \circ }$.

And the total scored marks \[ = 540\].

Let the marks scored in Social Science be $y$.

Therefore, 

$\frac{{y \times 360}}{{540}} = 65$

$y = \frac{{65 \times 54}}{{36}}$

So,

\[y = 97.5\]

That is, student score \[97.5\] marks in Social Science.

Now, the sum of the marks scored in Social Science and Mathematics \[ = 97.5 + 135\]

\[ = 232.5\]

And the sun of the marks scored in Science and Hindi \[ = {\text{ }}120 + 105\]

\[ = {\text{ }}225\]

Therefore, the sum of the marks obtained in Social Science and Mathematics is more than that in Science and Hindi.


5. The number of students in a hostel, speaking different languages is given below. Display the data in a pie chart. 

Language

Hindi

English

Marathi

Tamil

Bengali

Total

No. of Students

\[{\mathbf{40}}\]

\[{\mathbf{12}}\]

\[{\mathbf{9}}\]

\[{\mathbf{7}}\]

\[{\mathbf{4}}\]

\[{\mathbf{72}}\]


Ans: To draw the pie chart of the given data. First we have to find the central angle of each sector.

Given, the total number of students \[ = {\text{ }}72\].

The total central angle $ = {360^ \circ }$

Now, calculating the central angle of each sector.


For Hindi:

Central angle of Hindi $ = \frac{{40 \times 360}}{{72}}$

So, the central angle of Hindi \[ = 200\]


For English:

Central angle of English $ = \frac{{12 \times 360}}{{72}}$

So, the central angle of English \[ = 60\]


For Marathi:

Central angle of Marathi $ = \frac{{9 \times 360}}{{72}}$

So, the central angle of Marathi \[ = 45\]


For Tamil:

Central angle of Tamil $ = \frac{{7 \times 360}}{{72}}$

So, the central angle of Tamil \[ = 35\]


For Bengali:

Central angle of Bengali $ = \frac{{4 \times 360}}{{72}}$

So, the central angle of Bengali\[ = 20\]

Now, the pie chart of the following data is as follows:


Pie chart representing different languages spoken


Pie chart representing different languages spoken


Conclusion

Class 8 Exercise 4.1 Maths Chapter 4 focuses on the foundational concepts of data handling. It teaches students how to organize data using frequency distribution tables and calculate the mean. Understanding these basics is crucial as they form the basis for more complex data representation methods, like bar graphs and pie charts, covered in later exercises. Students should focus on accurately organizing data and computing the mean, as these skills are essential for interpreting data effectively. By mastering these techniques, students will enhance their analytical abilities and be better prepared for solving various data-related problems. This exercise is a stepping stone towards building confidence in handling data, which is vital for academic success.


Class 8 Maths Chapter 4: Exercises Breakdown

Exercise

Number of Questions

Exercise 4.2

5 Questions with Solutions


CBSE Class 8 Maths Chapter 4 Other Study Materials


Chapter-Specific NCERT Solutions for Class 8 Maths

Given below are the chapter-wise NCERT Solutions for Class 8 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.


FAQs on NCERT Solutions for Class 8 Maths Chapter 4 - Data Handling Exercise 4.1

1. What is data handling in class 8 maths exercise 4.1 solutions pdf?

Data handling involves collecting, organizing, and interpreting data to make it useful and understandable. It helps in representing data in various formats such as tables, charts, and graphs. This process is essential for making sense of large amounts of information and drawing meaningful conclusions.

2. Why is it important to learn data handling?

Learning data handling is crucial because it develops analytical skills and helps in making informed decisions based on data. It is also a fundamental skill used in various fields like science, business, and economics. Mastery of data handling techniques can improve one's ability to manage and utilize data effectively.

3. What is a frequency distribution table in class 8 exercise 4.1 ?

In class 8 exercise 4.1 a frequency distribution table is a way to organize data into categories and show the number of occurrences (frequency) of each category. It helps in summarizing large data sets for easier interpretation. By grouping data into intervals or categories, it simplifies the analysis of patterns and trends.

4. What is the difference between mean, median, and mode in class 8 maths ex 4.1?

In class 8 maths ex 4.1 the mean is the average of all observations, the median is the middle value when the data is ordered, and the mode is the value that appears most frequently in the data set. Each measure gives a different perspective on the data distribution and is useful in different scenarios.

5. How can organizing data help in problem-solving oin maths class 8 chapter 4 exercise 4.1?

Organizing data helps in identifying patterns and trends, making it easier to analyze and draw conclusions. It simplifies complex data and aids in effective problem-solving. Properly organized data allows for better visualization and understanding, leading to more accurate and efficient solutions.

6. What is the significance of the mean in data handling in maths class 8 chapter 4 exercise 4.1?

The mean is significant because it provides a central value for a data set, representing a balance point. It is useful in comparing different data sets and identifying overall trends. The mean is widely used in statistics, economics, and everyday calculations to find average values.

7. How can a frequency distribution table be created in class 8 math exercise 4.1 ?

To create a frequency distribution table, list all the distinct values or intervals of the data set. Then, count the number of times each value or interval occurs and record these frequencies in a table format. This process helps in organizing and summarizing the data effectively.

8. What types of questions are likely to be asked from class 8 math exercise 4.1 ?

Questions from class 8 math exercise 4.1  may include creating and interpreting frequency distribution tables, calculating the mean, and organizing data. Students may also be asked to analyze data and draw conclusions based on the frequency distribution. Understanding these concepts is essential for solving various types of data-related problems.

9. How does mastering class 8 maths 4.1 help in exams?

Mastering class 8 maths 4.1 helps in exams by improving problem-solving speed and accuracy. It builds a strong foundation in data handling, which is crucial for tackling more complex problems in later chapters. Practicing these exercises boosts confidence and prepares students for data-related questions in exams.