## NCERT Solutions for Class 7 Maths Chapter 1 Integers (EX 1.2) Exercise 1.2

NCERT Solutions for Class 7 Maths Exercise 1.2 Chapter 1 ‘Integers’ are provided on this page in simple downloadable PDF format. Students can download the solution and refer to it anytime they feel comfortable and even from anywhere. Our main aim in providing solutions for this exercise is to help students to clear their concepts.

### What are Integers?

In Maths, Integers are defined as the whole value of positive or negative numbers including the number 0. Integers are formed from the set of counting numbers 1,2,3, and so on and the order of operation. For example, when a counting number is subtracted from itself, we get the result 0 such as 3-3 = 0.

### Topics Covered In Class 7 Maths Chapter 1 Exercise 1.2

In Class 7 Maths Chapter 1 Exercise 1.2, questions are based on the topic properties of addition and subtraction of integers. There are four different properties of addition and subtraction of Integers. These are:

Closure Property of Addition and Subtraction of Integer

Commutative Property of Addition and Subtraction of Integer

Associative Property of Addition and Subtraction of Integer

Additive Identity

NCERT Solutions for Class 7 Maths Chapter 1 Exercise 1.2 are available at Vedantu’s online learning portal. Our subject experts with years of experience have developed well-explained notes as per the updated NCERT guidelines. Class 7 Maths Exercise 1.2 is very significant for students as it covers those concepts that build the foundation for this subject. So don’t let mathematics haunt you rather take help from our well-learned subject experts. You can download them for free in PDF format. Every NCERT Solution is provided to make the study simple and interesting on Vedantu. Subjects like Science, Maths, English will become easy to study if you have access to NCERT Solution for Class 7 Science , Maths solutions and solutions of other subjects.

## Access NCERT Solutions for Class 7 Mathematics Chapter 1 – Integers

### Exercise 1.2

1. Write down a pair of integers whose:

(a) Sum is \[-\mathbf{7}\]

Ans: One such pair whose sum is\[-7\]: \[~-5+(-2)=\text{ }-7\]

(b) Difference is \[-\mathbf{10}\]

Ans: One such pair whose difference is\[-10\]: \[~-2-8=\text{ }-10\]

(c) Sum is \[\mathbf{0}\]

Ans. One such pair whose sum is\[0\]: \[~-5+5=0\]

2. (a) Write a pair of negative integers whose difference gives \[\mathbf{8}\].

Ans: \[-2-(-10)-2+10=8\]

(b)Write a negative integer and a positive integer whose sum is -\[5\].

Ans: \[(-7)+2=\text{ }-5\]

(c)Write a negative integer and a positive integer whose difference is -\[\mathbf{3}\].

Ans: \[(-2)-1=\text{ }-2-1=\text{ }-3\]

3. In a quiz, team A scored\[~-\mathbf{40},\mathbf{10},\mathbf{0}\] and team B scores \[\mathbf{10},\text{ }\mathbf{0},-\mathbf{40}\] in three successive rounds. Which team scored more? Can we say that we can add integers in any order?

Ans. Total score of Team A = \[-40+10+0\]=\[-30\]

Team B scored \[10,0,-40\]

Total score of Team B = \[10+0+(-40)\]=\[10+0-40\]=\[-30\]

Thus, the scores of both the teams are the same.

Yes, we can add integers in any order due to commutative property.

4. Fill in the blanks to make the following statements true:

(i) \[(-\mathbf{5})+(-\mathbf{8})=(-\mathbf{8})+(.......)\]

Ans: By applying commutative property

\[~(-5)+(-8)=(-8)+(-5)\]

(ii) \[-\mathbf{53}+.......=\text{ }-\mathbf{53}\]

Ans: By applying zero additive property

\[~-53+0=\text{ }-53\]

(iii) \[\mathbf{17}\text{ }+\text{ }\ldots \ldots .\text{ }=\text{ }\mathbf{0}\]

Ans: By applying additive inverse property

\[17+(-17)=0\]

(iv) \[\left[ 13+\left( -12 \right) \right]+\left( ....... \right)=13+\left[ \left( -12 \right)+\left( -7 \right) \right]\]

Ans: Applying associative property

\[\left[ 13+\left( 12 \right) \right]+\left( -7 \right)=13+\left[ \left( -12 \right)+\left( -7 \right) \right]\]

(v) \[\left( -4 \right)+\left[ 15+\left( -3 \right) \right]=\left[ -4+15 \right]+.........\]

Ans: Applying Associative property

\[\left( -4 \right)+\left[ 15+\left( -3 \right) \right]=\left[ -4+15 \right]+\left( -3 \right)\]

### NCERT Solutions for Class 7 Maths Chapter 1 Other Exercises

Chapter 1 - Integers Other Exercises in PDF Format | |

10 Questions & Solutions | |

9 Questions & Solutions | |

7 Questions & Solutions |

## Brace Yourself with the Best Class 7 Maths Exercise 1.2 Solutions

According to our experts providing Class 7 Maths Exercise 1.2 Solutions, Mathematics is one of the complex subjects that many students may not enjoy studying. This is because of innumerable theorems, formulae, concepts, etc. Remembering each and every concept along with the associated formulae is not a cakewalk. However, if a student has a strong command over this subject, then he can score a perfect 100. Talking about chapter 1 of the NCERT Class 7 textbook, it is based on the topic called ‘Integer’. These are the numbers that have no fractional part or decimal. The difference between two consecutive integers is one unit. These can be negative or positive.

The knowledge of integer will help in dealing with real-life problems. For instance, measuring lengths or other dimensions, counting money, increase in price, age, etc. Without knowledge of integers, one cannot attain computing efficiency. Many students face difficulties in understanding the concepts of integers. But, with our top-quality NCERT Solutions for Class 7 Maths Chapter 1 Exercise 1.2, you can build a strong base for this subject. With Vedantu’s solutions for Exercise 1.2 Class 7 Maths, you can learn all the concepts of integers and their applications. With their smart learning methods, our experts have made the learning so simple that students won’t feel boredom while studying maths.

There are various exercises containing questions on various properties of integers and their usage. However, Exercise 1.2 of Class 7 Maths is the most interesting among them. It covers many concepts that are important to build a deep understanding of this subject. The Class 7 Maths Exercise 1.2 has four questions in total. Each one of them is based on a unique aspect of the integer.

Talking about the very first question, it is based on the positive and negative characteristics of an integer. In order to attempt this question, you need to have a basic knowledge of the integers. An integer can be positive or negative depending upon its location on the number line. If an integer lies in the right side of the zero or other words, it is greater than zero, then it is positive. On the other hand, if its location is on the left side of the zero or the number is less than zero, then it is a negative integer. Many a time, students get confused in placing the right sign in front of the integer that results in a deduction of marks. However, with our experts' advice for solving Class 7 Maths Exercise 1.2, you can avoid committing such blunders and score well in exams.

Coming on the next question, it is based on combinations of two integers to get a particular sum or difference as mentioned in the questions. For attempting this question, it is important for you to note that there are infinite integers and to work out a particular difference or sum, there can be infinite pairs of integers. For instance, the sum of 2 and 4 is 6, whereas the sum of 1 and 5 is also 6. Hence, the pair of integers whose sum is 6 can be (2, 4) or (1, 5). Similarly, it is true in the case of getting a particular difference. This might look a bit confusing but you can reach our well-learned faculties to get solutions for Class 7 Maths Exercise 1.2.

The third question is about the addition or subtraction of a pair of integers in different orders. The integers have certain properties, such as the commutative property of addition & multiplication, associative property of addition & multiplication, and the distributive property of addition and multiplication. In the third question, the main confusion that the majority of students have is regarding the addition of integers in various orders. The solution to this doubt is that one can add integers in any order due to commutative property that says A+B = B+A. Apart from this, one can also multiply integers in any order. Talking about the associative property, adding more than two integers in different groups will yield the same result i.e., A+ (B+C) = (A+B) + C. Similar rule applies to the multiplication of integers.

Talking about the last question, it is based on the aforementioned properties of addition or multiplication of two or more integers. The sub-parts of the question are fill in the blank type that requires the application of properties. It has been noticed that students get confused between commutative and distributive property and commit some errors in exams.

The chapter is quite easy in comparison to other chapters in the book. With the correct knowledge of the concepts, one can easily score high marks in this particular chapter. However, in case you face any sort of issue while solving questions, then you can refer to our highly-rated NCERT Solutions for Class 7 Maths Chapter 1 Exercise 1.2.

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