Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

Perimeter and Area

ffImage
Last updated date: 28th Apr 2024
Total views: 422.1k
Views today: 5.22k
hightlight icon
highlight icon
highlight icon
share icon
copy icon

Perimeter and Area Formulas for All Shapes Notes on Vedantu

For a two-dimensional figure, perimeter refers to the boundary or path around a shape. On the other hand, the area of a two-dimensional figure is the space occupied within the surface of a shape. There are various types of shapes, but the common ones are square, rectangle, triangle, circle, etc. In this content, you will be able to know the perimeter and area of basic shapes.

 

Let’s start!

1. Rectangle


(Image will be uploaded soon)

 

A rectangle is a shape whose opposite sides are equal, and all the angles are right angles (90 degrees).

Perimeter of rectangle = \[2 ( a + b )\]

Area of rectangle = \[ a \times b \]

 

2. Square


(Image will be uploaded soon)

 

A square is a shape whose all four sides are equal, and all the angles are 90 degrees.

Perimeter of square = \[ 4 \times a \]

Area of square = \[ a^{2} \]

 

3. Circle


(Image will be Uploaded soon)

 

A circle refers to a round shape that contains no edges or corners.

Perimeter of circle = \[2 \pi r\] (r = radius)

Area of circle = \[ \pi r^{2} \]

 

Note: Here the value of pi is either \[\frac{22}{7} \] or 3.14. You can use any one of them if not mentioned in the question.

 

4. Triangle


(Image will be Uploaded soon)

 

A triangle is a shape with three angles and three straight lines. Triangles can be classified into three kinds, such as:

  1. Equilateral Triangle

Perimeter of equilateral triangle = 3 a

Area of equilateral triangle = \[ \frac{1}{4} \times \sqrt{3} \times a^{2} \]

 

  1. Isosceles Triangle

Perimeter of isosceles triangle = 2s + b

Area of isosceles triangle = \[\frac{1}{2} \times\] b \[\times\] hb 

 

  1. Scalene Triangle

Perimeter of scalene triangle = a + b + c

Area of scalene triangle = \[\frac{1}{2} \times b \times h \]

 

5. Parallelogram


(Image will be Uploaded soon)

 

This shape is a quadrilateral whose opposite sides are parallel.

Perimeter of parallelogram = \[2 ( a + b ) \]

Area of parallelogram = \[b \times  h\]

 

6. Rhombus


(Image will be Uploaded soon)

 

It is a parallelogram whose sides are equal.

Area of rhombus = \[a \times h \]

Perimeter of Rhombus = \[4 \times a \]


7. Trapezoid

This shape is a quadrilateral which has a minimum of 1 pair of parallel sides.

Perimeter of trapezoid = \[a_1 + a_2 + b_1 + b_2 \]

Area of trapezoid = \[(\frac{( a1 + a2 )}{2}) \times h \]

 

8. Regular N-Gon


(Image will be Uploaded soon)

 

A regular polygon refers to a polygon whose number of sides and angles are the same.

Area of regular n-gon = \[\frac{1}{2} \times ( a \times n \times s) \]

Perimeter of Regular n-gon = \[n \times s \]

 

Here are some illustrative examples you can go through to understand the solving procedure.

 

Ex 1. A rectangular field has length 12 m and breadth 10 m. What will be the area as well as the perimeter of that field?

Solution. Length of the rectangular field = 12 m

Breadth of the rectangular field = 10 m

Therefore, area of the field =\[ l \times b = 12 \times 10 = 120 m^2\]

And perimeter = \[2 ( l + b ) = 2 ( 10 + 12 ) = 44 m\]

 

Ex 2. Find the perimeter of circles whose radius are (i) 14cm (ii) 10m and (iii) 4km.

Solution. 

  1. According to the formula \[ 2 \pi r = 2 \times 3.14 \times 14 cm = 87.92 cm \]

  2. \[ 2 \pi r = 2 \times 3.14 \times 10 m = 62.8 m \]

  3. \[ 2 \pi r = 2 \times 3.14 \times 4 km = 25.12 km \]

 

Ex 3. If a rhombus has base and height 10 cm and 7 cm respectively, calculate its area.

Solution. With regards to the question base = 6 cm

Height = 8 cm

Therefore, the area of rhombus = \[b \times h\]

= \[10 \times 7 cm^{2} \]

= \[70 cm^{2} \]

 

This material is mainly for students who belong to standard VII, so here only the basic formulas are provided. There are some other methods also to solve perimeter and area specifically for shapes like rhombus, triangles, etc. which you will learn in higher classes. 

 

If you want to refer to other solved examples of area and perimeter numerical, download the Vedantu app today.

FAQs on Perimeter and Area

1. Why are area and perimeter important?

Perimeter and area are the physical aspects of maths, and that is the reason why they are essential. Also, they are the base for comprehending other geometrical aspects like mathematical theorems and volume that helps everyone to understand trigonometry, algebra and calculus.


In everyday life, perimeter and area are used for many purposes, including measuring plots, fencing an area. Some other examples are when engineers plan to construct a house or a swimming pool, farming, covering rooms with carpet, etc.

2. What will be the area of a square park with a perimeter of 320 m?

Given the shape of the park is a square.Perimeter of the park = 320m Therefore, the length of each side = \[\frac{320}{4} m= 80 m. \] 


So, the area of the park will be = (length of sides)\[^2 = 80 \times 80 m^2= 6400 m^2\]

3. How to find a rhombus area by diagonals?

First, draw a rhombus, ABCD, which has two diagonals AC and BD. The next step is to determine the length of 1st diagonal which is equivalent to the distance from A to C.Similarly, for the 2nd diagonal, evaluate its length which is the distance from B to D. Remember that rhombus’s diagonals are perpendicular to one another, which makes four 90-degree angles when intersecting each other at the middle of rhombus. Then multiply the diagonals d1 and d2 and divide it by 2.

4. Where can I find the study material for perimeter and area, formula for all shapes?

The students can find the study material for every concept of mathematics such as perimeter and area at Vedantu where they can easily download these offline too. Vedantu provides the perimeter and area formula of all shapes available for no charge at all and brings you all the content curated by master teachers and experts. The students can easily sign in at the Vedantu website or app and gain access to loads of study material which makes studies easier and simpler.

5. How can I find the perimeter and area of any closed shape?

The easiest way for the students to calculate the perimeter of any given closed shape is to add all the lengths given to each side. 


For example, if we wish to calculate the perimeter of a rectangle of sides AB, BC, CD and DA with length 4 cm and breadth of 6 cm.


Then, 


Sum of all sides= measurement of sides (AB, BC, CD and DA)

= 4+4+6+6 = 20 cm. 


Thus, the perimeter of the rectangle ABCD is 20 cm.


To calculate the area,


The students need to know that an area of a given shape is defined as the total space enclosed by it. The formula varies from one shape to another as required. For instance, the area of the aforementioned rectangle ABCD will be calculated by multiplying the length and breadth.


I.e 4 × 6 = 24 cm².


But for some other shapes, the formula will change accordingly.


Refer to Vedantu for free solutions chapter wise and get free access to other online resources to improve your learning in several folds.