
How to Draw Graphs of Inverse Trigonometric Functions with Domain and Range
The Formula of Inverse Trigonometric Functions
Domain and Range of Inverse Trigonometric Formulas
It is important to note the following formulas considering the domain and range of inverse function
sin(sin-1x) = x, if -1 ≤ x ≤ 1 and sin-1(sin y) = y if -\[\frac{\pi}{2}\] ≤ y ≤ \[\frac{\pi}{2}\].
cos(cos-1x) = x, if -1 ≤ x ≤ 1 and cos-1(cos y) = y if 0 ≤ y(arccos) ≤ π.
tan(tan-1x) = x, if -∞ < x < ∞ and cos-1(cos y) = y if -\[\frac{\pi}{2}\] ≤ y(arctan) ≤ \[\frac{\pi}{2}\].
cot(cot-1x) = x, if -∞ < x < ∞ and cot-1(cot y) = y if 0 < y <π.
sec(sec-1x) = x, if -∞ ≤ x ≤ -1 or 1 ≤ x ≤ ∞ and sec-1(sec y) = y if -0 ≤ y ≤ π, y ≠ \[\frac{\pi}{2}\].
cosec(cosec-1x) = x, if -∞ ≤ x ≤- 1 or 1 ≤ x ≤ ∞ and cosec-1(cosec y) = y if -\[\frac{\pi}{2}\] ≤ y ≤ \[\frac{\pi}{2}\], y ≠ 0.
Inverse trigonometric functions are also known as ‘arc functions’ because, for a given value of the trigonometric function, they produce the length of arc needed to get the particular value.
Graph of Inverse Trigonometric Function
1 - Arcsine Function
inverse sine function is defined as
y = arcsin x for – \[\frac{\pi}{2}\] ≤ y ≤ \[\frac{\pi}{2}\]
y is the angle with sine x which means x = sin y
the graph of y = arcsin x
(image will be uploaded soon)
2 - Arccosine Function
The graph of cosine does not extend beyond the point you see in the graph (if it extended, there would be multiple values of y for each x value and we would no longer have a function). The start and endpoints are indicated with dots (-1,) and (1,0)
(image will be uploaded soon)
3 - Arctangent Function
This graph can extend beyond what you see in the positive and negative direction of x and it does not cross the dashed line.
The domain of arctan x is all values of x
The range for arctan x is - \[\frac{\pi}{2}\] < arctan x < \[\frac{\pi}{2}\]
(image will be uploaded soon)
4 - Arccotangent Function
The graph of arccotangent extends in the positive and negative x directions. As shown in the graph it does not stop at -8, 8
The domain of arccot x is all values of x
The range of arccot x is −2π < arccot x ≤ 2π (arccot x ≠ 0)
(image will be uploaded soon)
5 - Arcsecant Function
Here, in the graph of sec inverse x, the curve is defined outside of the portion between -1 and 1. The starting points (-1, π) and (1,0) with dots.
The domain of arcsec x is all values of x except −1 < x < 1
The range of arcsec x is 0 ≤ arcsec x ≤ π, arcsec x \[\neq \frac{\pi}{2}\]
(image will be uploaded soon)
6 - Arccosecant Function
The graph extends from positive and negative x direction and is not defined between – 1 and 1
The domain of arccsc x is all values of x except – 1 < x < 1
The range
The range of arccsc x is - \[\frac{\pi}{2}\] ≤ arc csc x ≤ \[\frac{\pi}{2}\] , arccsc x \[\neq 0\]
(image will be uploaded soon)
Solved Examples of Inverse Trigonometric Functions
1. Find the accurate value of each of the expression in [0, 2\[\pi\]].
sin-1(−3\[\sqrt{2}\])
cos-1(−2\[\sqrt{2}\])
tan-1\[\sqrt{3}\]
solution:
a. We get – 3 \[\sqrt{2}\] from 30 - 60 - 90 triangle. Therefore, the reference angle for 3 \[\sqrt{2}\] would be 60°. As it is sine it is negative and must be in the third or fourth quadrant. Here the answer is either 4 \[\frac{\pi}{3}\] or 5\[\frac{\pi}{3}\]
b. From the isosceles right triangle we get -2\[\sqrt{2}\]. The reference angle will be 45° as it is cosine and negative. The angle is either on the second or third quadrant. The answer is 3 \[\frac{\pi}{4}\] or 5\[\frac{\pi}{4}\]
c. From the 30 - 60 - 90 triangle we get \[\sqrt{3}\]. For the reference angle 60°, a tangent is \[\sqrt{3}\]. In the first and third quadrant, the tangent is positive, therefore, the answer is \[\frac{\pi}{3}\] or 4 \[\frac{\pi}{3}\]
Note: Every example here has two answers which can be a problem when finding a single inverse for each trigonometric function. So, we have to restrict the domain in which inverse is found.
2. Get the value of (1.1106).
Solution: let B = (1.1106)
Then tan B = 1.1106
B = 48°
Tan 48 = 1.1106
Therefore, (1.1106 ) = 48°.
FAQs on Graphical Representation of Inverse Trigonometric Functions Explained Clearly
1. What is the graphical representation of inverse trigonometric functions?
The graphical representation of inverse trigonometric functions is the graph obtained by reflecting the corresponding trigonometric function across the line y = x within its restricted domain. Since trigonometric functions are not one-to-one over their entire domain, they are first restricted to make them invertible. For example:
- The graph of y = sin⁻¹x is the reflection of y = sin x (restricted to −π/2 to π/2).
- The graph of y = cos⁻¹x is the reflection of y = cos x (restricted to 0 to π).
2. Why do we restrict the domain of trigonometric functions before finding their inverse?
We restrict the domain of trigonometric functions because an inverse function exists only when the function is one-to-one. Trigonometric functions like sine and cosine are periodic and fail the horizontal line test over their full domain. Therefore:
- sin x is restricted to [−π/2, π/2]
- cos x is restricted to [0, π]
- tan x is restricted to (−π/2, π/2)
3. What is the domain and range of y = sin⁻¹x?
The domain of y = sin⁻¹x is [−1, 1] and its range is [−π/2, π/2]. Since sine values lie between −1 and 1, the inverse sine function only accepts inputs in this interval. The output (angle) lies within the principal value range −π/2 to π/2. This domain-range relationship is important when sketching the graph of the inverse sine function.
4. What is the domain and range of y = cos⁻¹x?
The domain of y = cos⁻¹x is [−1, 1] and its range is [0, π]. Because cosine values vary from −1 to 1, the inverse cosine function accepts inputs only in that interval. The output angles lie between 0 and π, which ensures the function is one-to-one and properly defined for graphical representation.
5. What is the domain and range of y = tan⁻¹x?
The domain of y = tan⁻¹x is (−∞, ∞) and its range is (−π/2, π/2). Since tangent can take any real value, the inverse tangent accepts all real numbers as input. However, its outputs are restricted between −π/2 and π/2 to maintain a one-to-one function. The graph approaches horizontal asymptotes at y = −π/2 and y = π/2.
6. How do you sketch the graph of an inverse trigonometric function?
To sketch an inverse trigonometric function, reflect the restricted trigonometric graph across the line y = x. Follow these steps:
- Draw the graph of the trigonometric function with its restricted domain.
- Draw the line y = x as a reference.
- Reflect each point across this line.
- Label the new domain and range correctly.
7. What are the key features of the graph of y = sin⁻¹x?
The key features of y = sin⁻¹x include domain [−1, 1], range [−π/2, π/2], and an increasing curve passing through (0, 0). Important characteristics:
- Intercept: (0, 0)
- Increasing function throughout its domain
- No asymptotes
- Symmetric about the origin (odd function)
8. What are the asymptotes of the graph of y = tan⁻¹x?
The graph of y = tan⁻¹x has horizontal asymptotes at y = −π/2 and y = π/2. As x approaches positive infinity, tan⁻¹x approaches π/2, and as x approaches negative infinity, it approaches −π/2. These asymptotes are essential when graphing the inverse tangent function.
9. What is the difference between sin x and sin⁻¹x graphically?
Graphically, sin x is a periodic wave, while sin⁻¹x is a non-periodic increasing curve defined only on [−1, 1]. Key differences:
- sin x has domain (−∞, ∞); sin⁻¹x has domain [−1, 1].
- sin x is periodic; sin⁻¹x is not periodic.
- sin⁻¹x is the reflection of restricted sin x across y = x.
10. Can you give an example of evaluating and locating a point on an inverse trigonometric graph?
Yes, for example, sin⁻¹(1/2) = π/6, so the point (1/2, π/6) lies on the graph of y = sin⁻¹x. Explanation:
- Since sin(π/6) = 1/2
- And π/6 lies in the principal range [−π/2, π/2]





















