
Which of the given sets of temperature and pressure will cause gas to exhibit the greatest deviation from ideal gas behaviour?
(A) ${100^ \circ }C$ and $4atm$
(B) ${100^ \circ }C$ and $2atm$
(C) $ - {100^ \circ }C$ and $4atm$
(D) ${0^ \circ }C$ and $2atm$
Answer
233.1k+ views
Hint: In order to solve this question, we should first understand the Van der Waals equation. In the year $1873$ A.D. Van der Waals made some changes with the ideal law of gas equation in order to explain the behaviour of the real gases in which he considered the volume of the gas molecules and also the forces of attraction between the gas molecules.
Complete Step by Step Solution:
The ideal gas behaviour is a theory which expects the gases to act in a particular way and assume that the gases have very negligible or no space at all and they also have no intermolecular force of attraction among them.
Van der Waals did some changes with the ideal law of gas equation and the outcome of it is as follows:
$\left( {P + \dfrac{a}{{{v^2}}}} \right)\left( {v - b} \right) = RT$
If there are $n$ moles of the gas, then the equation will be as follows:
$\left( {P + \dfrac{{a{n^2}}}{{{v^2}}}} \right)\left( {v - nb} \right) = nRT$
Here, the constants $a$ and $b$ represent the scale of intermolecular attraction and the excluded volume respectively. If the value of $a$ is more, then the molecular attraction is more and the gas can be compressed easily. The value of the constant $b$ is used to represent the excluded volume that is occupied by gas particles.
Gases deviate from ideal gas behaviour to real gas according to the above equation at low temperature and high pressure. Among the given sets of temperature and pressure, $ - {100^ \circ }C$ and $4atm$ will cause gas to exhibit the greatest deviation from ideal gas behaviour
Therefore, the correct answer is option C.
Note: It is important to note that if the value of $a$ is more, then the molecular attraction is more and the gas can be compressed easily. The value of the constant $b$ is used to represent the excluded volume that is occupied by gas particles.
Complete Step by Step Solution:
The ideal gas behaviour is a theory which expects the gases to act in a particular way and assume that the gases have very negligible or no space at all and they also have no intermolecular force of attraction among them.
Van der Waals did some changes with the ideal law of gas equation and the outcome of it is as follows:
$\left( {P + \dfrac{a}{{{v^2}}}} \right)\left( {v - b} \right) = RT$
If there are $n$ moles of the gas, then the equation will be as follows:
$\left( {P + \dfrac{{a{n^2}}}{{{v^2}}}} \right)\left( {v - nb} \right) = nRT$
Here, the constants $a$ and $b$ represent the scale of intermolecular attraction and the excluded volume respectively. If the value of $a$ is more, then the molecular attraction is more and the gas can be compressed easily. The value of the constant $b$ is used to represent the excluded volume that is occupied by gas particles.
Gases deviate from ideal gas behaviour to real gas according to the above equation at low temperature and high pressure. Among the given sets of temperature and pressure, $ - {100^ \circ }C$ and $4atm$ will cause gas to exhibit the greatest deviation from ideal gas behaviour
Therefore, the correct answer is option C.
Note: It is important to note that if the value of $a$ is more, then the molecular attraction is more and the gas can be compressed easily. The value of the constant $b$ is used to represent the excluded volume that is occupied by gas particles.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

Organic Chemistry Some Basic Principles And Techniques Class 11 Chemistry Chapter 8 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reactions (2025-26)

