
Which of the following is aryl alkyl halide?
(A) o-chlorotoluene
(B) o-bromochlorobenzene
(C) 1-chloro-2-phenylethane
(D) Toluene
Answer
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Hint: In Aryl alkyl halides, aryl stands for aromatic compound, alkyl stands for any compound having carbon and hydrogen atoms only and halide stands for halogen family members such as fluorine, chlorine, bromine, etc.
Complete step-by-step solution:
Alkyl aryl halide is formed when one or more hydrogen atoms in an aromatic alkane are replaced by halogen atoms like fluorine, chlorine, bromine or iodine. This can be seen in option (C).
1-chloro-2-phenylethane contains benzene as an aryl group and chloroethane as an alkyl halide with ethane being the alkyl group and chlorine being the halide substituent.

While option (D), toluene has no halogen in it, so it can’t be an aryl alkyl halide as it has only methyl groups on benzene rings. But if one of the hydrogens of methane is replaced by any halogen, it will become aryl alkyl halide.
Similarly, we see in option (B), two halogens are present as substituents but no alkyl group is attached to the benzene ring. So, it is just an aryl halide.
Hence, the correct option is (C).
Note: Option (A) also accounts for the same because it has a chlorine at ortho position of benzene ring and toluene, methyl group on the benzene ring. This might look as an alkyl aryl halide, but it is just an aryl halide, as the halide is bonded directly to the benzene ring in it.
Complete step-by-step solution:
Alkyl aryl halide is formed when one or more hydrogen atoms in an aromatic alkane are replaced by halogen atoms like fluorine, chlorine, bromine or iodine. This can be seen in option (C).
1-chloro-2-phenylethane contains benzene as an aryl group and chloroethane as an alkyl halide with ethane being the alkyl group and chlorine being the halide substituent.

While option (D), toluene has no halogen in it, so it can’t be an aryl alkyl halide as it has only methyl groups on benzene rings. But if one of the hydrogens of methane is replaced by any halogen, it will become aryl alkyl halide.
Similarly, we see in option (B), two halogens are present as substituents but no alkyl group is attached to the benzene ring. So, it is just an aryl halide.
Hence, the correct option is (C).
Note: Option (A) also accounts for the same because it has a chlorine at ortho position of benzene ring and toluene, methyl group on the benzene ring. This might look as an alkyl aryl halide, but it is just an aryl halide, as the halide is bonded directly to the benzene ring in it.
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