
Which of the following is an example of an ionic crystal solid?
(a) Diamond
(b) \[LiF\]
(c) \[Li\]
(d) Silicon
Answer
164.7k+ views
Hint: The solid crystals in which the oppositely charged ions (cations and anions) are linked together by a strong electrostatic force of attraction is known as ionic crystal. For \[NaCl\] and \[KCl\] are the examples of ionic crystals in which the cations (\[N{a^ + }\] and \[{K^ + }\]) are linked with anion by the electrostatic force of attraction.
Complete Step by Step Solution:
Diamond is an example of a crystalline and covalent solid in which the carbon atoms are arranged in a well-defined order. In Diamond, each tetravalent carbon atom is fused with four carbon atoms, and each of these four carbon atoms is further linked with four other carbons via a covalent bond and forms a network-like structure.
Whereas the \[LiF\] is an example of an ionic crystalline solid in which the tiny electropositive lithium cation and electronegative fluoride anion (\[{F^ - }\] ) are fused together through electrostatic force of attraction. Unlike covalent solids, no orbital overlapping takes place in \[LiF\].
The lithium metal (\[Li\]) belongs to the class of crystalline metallic solid, and it has a metallic network in which \[Li\] metals are interconnected via metallic bonds.
Like diamonds, silicon also exists as a covalent solid and forms a network-like structure as occurs in the diamond.
Therefore, from the above discussion, it is quite clear that \[LiF\] is the ionic crystal solid. Whereas diamond, lithium, and silicon belong to the class of covalent and metallic solids. Hence, option (b) will be the correct answer.
Note: In diamond, each carbon atom is present in tetrahedral form with \[s{p^3}\] hybridization. Similarly in the structure of silicon, each silicon atom presents in \[s{p^3}\] hybridization.
Complete Step by Step Solution:
Diamond is an example of a crystalline and covalent solid in which the carbon atoms are arranged in a well-defined order. In Diamond, each tetravalent carbon atom is fused with four carbon atoms, and each of these four carbon atoms is further linked with four other carbons via a covalent bond and forms a network-like structure.
Whereas the \[LiF\] is an example of an ionic crystalline solid in which the tiny electropositive lithium cation and electronegative fluoride anion (\[{F^ - }\] ) are fused together through electrostatic force of attraction. Unlike covalent solids, no orbital overlapping takes place in \[LiF\].
The lithium metal (\[Li\]) belongs to the class of crystalline metallic solid, and it has a metallic network in which \[Li\] metals are interconnected via metallic bonds.
Like diamonds, silicon also exists as a covalent solid and forms a network-like structure as occurs in the diamond.
Therefore, from the above discussion, it is quite clear that \[LiF\] is the ionic crystal solid. Whereas diamond, lithium, and silicon belong to the class of covalent and metallic solids. Hence, option (b) will be the correct answer.
Note: In diamond, each carbon atom is present in tetrahedral form with \[s{p^3}\] hybridization. Similarly in the structure of silicon, each silicon atom presents in \[s{p^3}\] hybridization.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Types of Solutions

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
