
Which of the following acids adds to propene in the presence of peroxide to give anti-Markownikoff's product
A. \[HF\]
B. \[HCl\]
C. \[HBr\]
D. \[HI\]
Answer
219k+ views
Hint: According to the anti-Markovnikov rule, when a hydrogen halide is added to an asymmetric alkene, the acidic hydrogen is attached to the carbon atom that has the most alkyl substituents, and the other or negative group is associated to the carbon atom that has the most hydrogen substituents.
Complete step-by-step answer:In order to know that the Markovnikov rule states that when a hydrogen halide is added to an asymmetric alkene, the acidic hydrogen is attached to the carbon with the most hydrogen substituents and the other or the negative group is attached to the carbon with the most alkyl substituents. This rule applies when there are no peroxides present.
However, the situation in the question is that when organic peroxides are present, adding hydrogen bromide will cause radical-mediated reactions to occur with the bromides. The breaking of the peroxide \[O - O\] linkage will also produce a \[Br\] radical, which will proceed by adding to the side of the alkene that has more hydrogen substituents than the less substituted side (Anti - Markovnikov).
As an illustration, when \[HBr\] is added to propene in the presence of peroxides, the reaction proceeds by Anti-Markovnikov addition since it is exothermic.
\[C{H_3} - CH = C{H_2} + HBr\]
The peroxide effect is not observed in addition of HCl and HI. As, the H–Cl bond being stronger than H–Br bond, is not cleaved by the free radical, on the other hand the H–I bond is weaker and iodine free radicals combine to form iodine molecules but not add to the double bond. The HF is very reactive, so we don’t use this for peroxide reaction.
Option ‘C’ is correct
Note: All hydrogen halides go through Markovnikov's addition in the absence of peroxides but only HBr undergoes anti Markovnikov's addition in the presence of peroxide. According to Markanikov's addition that is the carbon atom that previously housed the most hydrogen atoms receives the hydrogen atom when a negative part is added to another C-atom of an alkene or alkyne.
Complete step-by-step answer:In order to know that the Markovnikov rule states that when a hydrogen halide is added to an asymmetric alkene, the acidic hydrogen is attached to the carbon with the most hydrogen substituents and the other or the negative group is attached to the carbon with the most alkyl substituents. This rule applies when there are no peroxides present.
However, the situation in the question is that when organic peroxides are present, adding hydrogen bromide will cause radical-mediated reactions to occur with the bromides. The breaking of the peroxide \[O - O\] linkage will also produce a \[Br\] radical, which will proceed by adding to the side of the alkene that has more hydrogen substituents than the less substituted side (Anti - Markovnikov).
As an illustration, when \[HBr\] is added to propene in the presence of peroxides, the reaction proceeds by Anti-Markovnikov addition since it is exothermic.
\[C{H_3} - CH = C{H_2} + HBr\]
The peroxide effect is not observed in addition of HCl and HI. As, the H–Cl bond being stronger than H–Br bond, is not cleaved by the free radical, on the other hand the H–I bond is weaker and iodine free radicals combine to form iodine molecules but not add to the double bond. The HF is very reactive, so we don’t use this for peroxide reaction.
Option ‘C’ is correct
Note: All hydrogen halides go through Markovnikov's addition in the absence of peroxides but only HBr undergoes anti Markovnikov's addition in the presence of peroxide. According to Markanikov's addition that is the carbon atom that previously housed the most hydrogen atoms receives the hydrogen atom when a negative part is added to another C-atom of an alkene or alkyne.
Recently Updated Pages
The hybridization and shape of NH2 ion are a sp2 and class 11 chemistry JEE_Main

What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main

Aromatization of nhexane gives A Benzene B Toluene class 11 chemistry JEE_Main

Show how you will synthesise i 1Phenylethanol from class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

Which of the following Compounds does not exhibit tautomerism class 11 chemistry JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

