The structure of \[{\text{N}}{{\text{a}}_{\text{2}}}{\text{O}}\] crystal is:
(A) \[{\text{CsCl}}\]type
(B) \[{\text{NaCl}}\]type
(C) \[{\text{KCl}}\]type
(D) Anti-fluorite
Answer
316.5k+ views
Hint: Sodium oxide has a chemical formula \[{\text{N}}{{\text{a}}_{\text{2}}}{\text{O}}{\text{.}}\] The main use of this chemical is in ceramics and in the formation of glasses. It is a base anhydride of sodium hydroxide \[{\text{(NaOH)}}{\text{.}}\] This means that when water is added to sodium oxide, sodium hydroxide is formed. The reaction is as follows –
\[N{a_2}O{\text{ }} + {\text{ }}{H_2}O{\text{ }} \to {\text{ }}2NaOH\]
Complete step by step answer:
Sodium oxide or \[{\text{N}}{{\text{a}}_{\text{2}}}{\text{O}}\] possesses the structure of anti-fluorite. Sodium ions are smaller in size than the oxide ions so they go to the voids. Moreover, the number of sodium ions present is twice that of the oxide ions so all the tetrahedral voids get filled by sodium ions. The oxide ions are larger in size so they occupy the face and corners of the lattice. Therefore, the structure formed is all the oxide ions occupy the face and corners while the sodium ions occupy the tetrahedral voids.
The anti-fluorite structure is derived from fluorite structure by interchanging the positive and negative positions in the lattice crystal.
Hence, the correct answer is (D) i.e., anti-fluorite.
Note: Sodium oxide is widely used in the manufacturing of ceramic and glass products. Also, sodium oxide is insoluble in water, but when added to water, it would result in the formation of sodium hydroxide.
\[N{a_2}O{\text{ }} + {\text{ }}{H_2}O{\text{ }} \to {\text{ }}2NaOH\]
Complete step by step answer:
Sodium oxide or \[{\text{N}}{{\text{a}}_{\text{2}}}{\text{O}}\] possesses the structure of anti-fluorite. Sodium ions are smaller in size than the oxide ions so they go to the voids. Moreover, the number of sodium ions present is twice that of the oxide ions so all the tetrahedral voids get filled by sodium ions. The oxide ions are larger in size so they occupy the face and corners of the lattice. Therefore, the structure formed is all the oxide ions occupy the face and corners while the sodium ions occupy the tetrahedral voids.
The anti-fluorite structure is derived from fluorite structure by interchanging the positive and negative positions in the lattice crystal.
Hence, the correct answer is (D) i.e., anti-fluorite.
Note: Sodium oxide is widely used in the manufacturing of ceramic and glass products. Also, sodium oxide is insoluble in water, but when added to water, it would result in the formation of sodium hydroxide.
Recently Updated Pages
JEE Main Equilibrium Mock test-2 (2025-26) – Free Practice

JEE Main 2025-26 Hydrocarbons Mock Test: Free Practice Online

JEE Main 2025-26 Mock Test: Some Basic Principles of Organic Chemistry

JEE Main 2025-26 Mock Test: Coordination Compounds Practice

JEE Main 2025-26 Atomic Structure Mock Test – Free Practice Online

JEE Main Mock Test 2025-26: Coordination Compounds Online Practice

Trending doubts
JEE Main 2027: Registration Open, Session 1 & 2 Exam Dates, City Slip, Admit Card & Complete Guide

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Angle of Deviation in a Prism

Other Pages
NCERT Solutions For Class 12 Chemistry Chapter 2 Electrochemistry - 2026-27 Free PDF Download (Sign-in Required)

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2026-27 Free PDF Download (Sign-in Required)

CBSE Notes Class 12 Chemistry Chapter 1 - Solutions - 2026-27 PDF Download (Login Required)

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes - 2026-27 Free PDF Download (Sign-In Required)

NCERT Solutions For Class 12 Chemistry Chapter 7 Alcohol Phenol And Ether - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 12 Chemistry Chapter 5 Coordination Chemistry - 2026-27

