
The structure and hybridization of \[Si{(C{H_3})_4}\]is
(a) Bent, \[s{p^{}}\]
(b) Trigonal, \[s{p^2}\]
(c) Octahedral, \[s{p^3}d\]
(d) Tetrahedral, \[s{p^3}\]
Answer
161.1k+ views
Hint: The methane \[C{H_4}\] molecule is the best example of\[s{p^3}\]hybridization. In which one \[s\]and three\[p\]orbital are involved in hybridization and form four \[s{p^3}\]hybridized orbital of the same energy. These four orbitals have a tetrahedral arrangement around the carbon center. Other examples of \[s{p^3}\]hybridization involve \[{C_2}{H_6}\]and \[Si{(C{H_3})_4}\], etc.
Complete step by step solution:The process of hybridization involves the mixing of atomic orbitals of an atom to produce new atomic orbitals of different shapes, sizes, and energy. These new orbitals are called hybrid orbitals.
In hybridization, the half-and fully filled orbital can take part.
By employing the concept of hybridization, we can easily predict the geometry of the molecules.
Based on the mixing of orbitals, the hybridization can be classified in the following way:
(1) \[s{p^{}}\]hybridization: Involve mixing of one \[s\]and one\[p\]orbitals. It has 50% \[s\]and 50%\[p\]characters with linear geometry. E.g., the acetylene molecule.
(2) \[s{p^2}\]hybridization: Involve mixing of one \[s\]and two\[p\]orbitals. It has 33.33% \[s\]and 66.66%\[p\]character with trigonal planar geometry. E.g., \[B{H_3}\] molecule.
(3) \[s{p^3}\]hybridization: Involve mixing of one \[s\]and three\[p\]orbitals. It has 25% \[s\]and 75%\[p\]character with tetrahedral geometry. E.g., \[C{H_4}\] molecule.
(4) \[s{p^3}d\]hybridization: Involves mixing of one \[s\], three\[p\]and one \[d\] orbitals. It has trigonal bipyramidal geometry. E.g., \[PC{l_5}\] molecule.
(5) \[s{p^3}{d^2}\]hybridization: Involves mixing of one \[s\], three\[p\]and one \[d\] orbitals. It has octahedral geometry. E.g., sulfur hexafluoride.
The tetramethyl silane (\[Si{(C{H_3})_4}\]) or TMS has a very similar structure to the methane (\[C{H_4}\]) molecule. In \[Si{(C{H_3})_4}\] molecule one \[s\]and three\[p\]orbital involved in hybridization and produce four \[s{p^3}\]hybridized orbitals. These four orbitals have a tetrahedral arrangement around the silicon (\[Si\])center and form four sigma bonds with four\[C{H_3}\] groups.

Image: structure of tetramethylsilane.
Therefore from the above explanation we can say option (d) will be the correct option:
Note: tetramethyl silane is a volatile organometallic compound.
In NMR spectroscopy tetramethyl silane is used as an internal standard to calibrate the chemical shift.
tetramethyl silane is responsible for memory loss and brain tumors in human beings.
In organic chemistry tetramethyl silane acts as a protecting group for alcohols.
Complete step by step solution:The process of hybridization involves the mixing of atomic orbitals of an atom to produce new atomic orbitals of different shapes, sizes, and energy. These new orbitals are called hybrid orbitals.
In hybridization, the half-and fully filled orbital can take part.
By employing the concept of hybridization, we can easily predict the geometry of the molecules.
Based on the mixing of orbitals, the hybridization can be classified in the following way:
(1) \[s{p^{}}\]hybridization: Involve mixing of one \[s\]and one\[p\]orbitals. It has 50% \[s\]and 50%\[p\]characters with linear geometry. E.g., the acetylene molecule.
(2) \[s{p^2}\]hybridization: Involve mixing of one \[s\]and two\[p\]orbitals. It has 33.33% \[s\]and 66.66%\[p\]character with trigonal planar geometry. E.g., \[B{H_3}\] molecule.
(3) \[s{p^3}\]hybridization: Involve mixing of one \[s\]and three\[p\]orbitals. It has 25% \[s\]and 75%\[p\]character with tetrahedral geometry. E.g., \[C{H_4}\] molecule.
(4) \[s{p^3}d\]hybridization: Involves mixing of one \[s\], three\[p\]and one \[d\] orbitals. It has trigonal bipyramidal geometry. E.g., \[PC{l_5}\] molecule.
(5) \[s{p^3}{d^2}\]hybridization: Involves mixing of one \[s\], three\[p\]and one \[d\] orbitals. It has octahedral geometry. E.g., sulfur hexafluoride.
The tetramethyl silane (\[Si{(C{H_3})_4}\]) or TMS has a very similar structure to the methane (\[C{H_4}\]) molecule. In \[Si{(C{H_3})_4}\] molecule one \[s\]and three\[p\]orbital involved in hybridization and produce four \[s{p^3}\]hybridized orbitals. These four orbitals have a tetrahedral arrangement around the silicon (\[Si\])center and form four sigma bonds with four\[C{H_3}\] groups.

Image: structure of tetramethylsilane.
Therefore from the above explanation we can say option (d) will be the correct option:
Note: tetramethyl silane is a volatile organometallic compound.
In NMR spectroscopy tetramethyl silane is used as an internal standard to calibrate the chemical shift.
tetramethyl silane is responsible for memory loss and brain tumors in human beings.
In organic chemistry tetramethyl silane acts as a protecting group for alcohols.
Recently Updated Pages
Two pi and half sigma bonds are present in A N2 + B class 11 chemistry JEE_Main

Which of the following is most stable A Sn2+ B Ge2+ class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

The specific heat of metal is 067 Jg Its equivalent class 11 chemistry JEE_Main

The increasing order of a specific charge to mass ratio class 11 chemistry JEE_Main

Which one of the following is used for making shoe class 11 chemistry JEE_Main

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2026 Syllabus PDF - Download Paper 1 and 2 Syllabus by NTA

JEE Main Eligibility Criteria 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

Degree of Dissociation and Its Formula With Solved Example for JEE
