
The relationship between osmotic pressures at $273K$ when $10g$ glucose $\left( {{P}_{1}} \right)$ $10g$ urea $\left( {{P}_{2}} \right)$ and $10g$ sucrose $\left( {{P}_{3}} \right)$ are dissolved in $250mL$ of water is:
A. \[{{P}_{1}}>{{P}_{2}}>{{P}_{3}}\]
B. \[{{P}_{3}}>{{P}_{2}}>{{P}_{1}}\]
C. \[{{P}_{2}}>{{P}_{1}}>{{P}_{3}}\]
D. None of these
Answer
164.4k+ views
Hint: Osmotic pressure follows the direct relationship with molarity. Molarity is defined as the number of moles of substance present per unit volume. Osmotic pressure depends on the molecular weight inversely.
Complete Step by Step Answer:
The formula for osmotic pressure is given as follows:
\[\pi =iMRT\]
Here $i$ is the van't hoff’s factor.
$M$ is the molarity of the solution.
$R$ is the Rydberg constant and $T$ is the temperature.
From the above relation we can say that osmotic pressure is directly proportional to molarity again molarity is inversely proportional to molecular weight. Thus osmotic pressure is also inversely proportional to molecular weight.
The molecular weight of sugar cane is $342$ grams.
The molecular weight of glucose is $180$ grams.
The molecular weight of urea is $60$ grams.
Thus the osmotic pressure of urea will be higher followed by glucose and cane sugar.
So, the correct relation is \[{{P}_{2}}>{{P}_{1}}>{{P}_{3}}\].
Thus the correct option is C.
Note: The molecular weight of a compound can be determined using osmotic pressure. Osmotic pressure is also widely used in the desalination and purification of seawater, which involves the process of reverse osmosis. Osmotic pressure can be measured in terms of concentration of solution.
Complete Step by Step Answer:
The formula for osmotic pressure is given as follows:
\[\pi =iMRT\]
Here $i$ is the van't hoff’s factor.
$M$ is the molarity of the solution.
$R$ is the Rydberg constant and $T$ is the temperature.
From the above relation we can say that osmotic pressure is directly proportional to molarity again molarity is inversely proportional to molecular weight. Thus osmotic pressure is also inversely proportional to molecular weight.
The molecular weight of sugar cane is $342$ grams.
The molecular weight of glucose is $180$ grams.
The molecular weight of urea is $60$ grams.
Thus the osmotic pressure of urea will be higher followed by glucose and cane sugar.
So, the correct relation is \[{{P}_{2}}>{{P}_{1}}>{{P}_{3}}\].
Thus the correct option is C.
Note: The molecular weight of a compound can be determined using osmotic pressure. Osmotic pressure is also widely used in the desalination and purification of seawater, which involves the process of reverse osmosis. Osmotic pressure can be measured in terms of concentration of solution.
Recently Updated Pages
Environmental Chemistry Chapter for JEE Main Chemistry

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Types of Solutions

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
