
The relation Between Celsius and Fahrenheit temperature scales is:
A) $\dfrac{{C - 100}}{{212}} = \dfrac{{F - 18}}{{32}}$
B) $\dfrac{C}{{100}} = \dfrac{{F - 32}}{{180}}$
C) $\dfrac{C}{9} = \dfrac{{F - 32}}{5}$
D) $\text{None of these}$
Answer
216.3k+ views
Hint: Temperature is the degree of hotness or coldness of the body. It is measured using a device called a thermometer and has the dimensions of the Kelvin, Celsius, Fahrenheit etc. Out of which the Kelvin is the base unit of the temperature and the Celsius is the base unit of temperature.
Formula used:
The relation between the Celsius and the Fahrenheit is
$F = \dfrac{9}{5}C + 32$
Where $F$ is the temperature in Fahrenheit and $C$ is the temperature in the scale of Celsius.
Complete step by step solution:
In the scale of the Celsius, the zero degree represents the freezing point of the water and the $100$ degree represents the boiling point of the water. Let us consider the basic formula between the Celsius and the Fahrenheit which is given above.
$F = \dfrac{9}{5}C + 32$
Rearranging the above formula based on the given options,
$\left( {F - 32} \right)5 = 9C$
Forming the denominators from the above equation,
$\Rightarrow$ $\dfrac{{F - 32}}{9} = \dfrac{C}{5}$
By interchanging the left and right hand side of the equation.
$\Rightarrow$ $\dfrac{C}{5} = \dfrac{{F - 32}}{9}$
By dividing both the sides by $20$ ,
$\Rightarrow$ $\dfrac{C}{{5 \times 20}} = \dfrac{{F - 32}}{{9 \times 20}}$
By performing the basic arithmetic operation,
$\Rightarrow$ $\dfrac{C}{{100}} = \dfrac{{F - 32}}{{180}}$
Hence among the given option for the relation between the Celsius and the Fahrenheit scales, $\dfrac{C}{{100}} = \dfrac{{F - 32}}{{180}}$ is the correct answer.
Thus the option (B) is correct.
Note: The Fahrenheit scale is used for the measurement of the body temperature, and it is used in the weather forecasting in the United states and other countries. Even though there emerged many temperature naming units, the Americans still use Fahrenheit for their easy dimensioning.
Formula used:
The relation between the Celsius and the Fahrenheit is
$F = \dfrac{9}{5}C + 32$
Where $F$ is the temperature in Fahrenheit and $C$ is the temperature in the scale of Celsius.
Complete step by step solution:
In the scale of the Celsius, the zero degree represents the freezing point of the water and the $100$ degree represents the boiling point of the water. Let us consider the basic formula between the Celsius and the Fahrenheit which is given above.
$F = \dfrac{9}{5}C + 32$
Rearranging the above formula based on the given options,
$\left( {F - 32} \right)5 = 9C$
Forming the denominators from the above equation,
$\Rightarrow$ $\dfrac{{F - 32}}{9} = \dfrac{C}{5}$
By interchanging the left and right hand side of the equation.
$\Rightarrow$ $\dfrac{C}{5} = \dfrac{{F - 32}}{9}$
By dividing both the sides by $20$ ,
$\Rightarrow$ $\dfrac{C}{{5 \times 20}} = \dfrac{{F - 32}}{{9 \times 20}}$
By performing the basic arithmetic operation,
$\Rightarrow$ $\dfrac{C}{{100}} = \dfrac{{F - 32}}{{180}}$
Hence among the given option for the relation between the Celsius and the Fahrenheit scales, $\dfrac{C}{{100}} = \dfrac{{F - 32}}{{180}}$ is the correct answer.
Thus the option (B) is correct.
Note: The Fahrenheit scale is used for the measurement of the body temperature, and it is used in the weather forecasting in the United states and other countries. Even though there emerged many temperature naming units, the Americans still use Fahrenheit for their easy dimensioning.
Recently Updated Pages
Circuit Switching vs Packet Switching: Key Differences Explained

Mass vs Weight: Key Differences Explained for Students

Alpha, Beta, and Gamma Decay Explained

Alpha Particle Scattering and Rutherford Model Explained

Angular Momentum of a Rotating Body: Definition & Formula

Apparent Frequency Explained: Formula, Uses & Examples

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

JEE Main Correction Window 2026 Session 1 Dates Announced - Edit Form Details, Dates and Link

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

