The price of sugar is reduced by \[2\% \]. How many kg of sugar now can be bought for the money, which was sufficient to buy 49 kg of sugar earlier?
A. 1 kg less
B. 1 kg more
C. 2 kg more
D. 2 kg less
Answer
265.5k+ views
Hint: First, we will first assume the value of the price with any variable. Then we will find the new price of the sugar and the total amount of sugar for the obtained price.
Apply these, and then use the given conditions to find the required value.
Complete step-by-step solution
We are given that the price of sugar is reduced by \[2\% \].
Let us assume that the price of sugar is \[x\].
We will now calculate the price for 49 kg in terms of \[x\].
\[49 \times x = 49x\]
We will now find the new price of sugar by subtracting the reduction of 2 percent from the total.
\[
\left( {1 - \dfrac{2}{{100}}} \right)x = \left( {1 - 0.02} \right)x \\
= 0.98x \\
\]
We will now calculate the total amount of sugar for a new price by dividing the 49 kg of sugar by the new price sugar.
\[
\dfrac{{49x}}{{0.98x}} = \dfrac{{4900}}{{98}} \\
= 50{\text{ kg}} \\
\]
Thus, the total amount of sugar for a new price is 50 kg.
Subtracting the 49 kg of sugar from the total amount of sugar for a new price, we get
\[
50{\text{ kg}} - 49{\text{ kg}} = \left( {50 - 49} \right){\text{kg}} \\
= 1{\text{ kg}} \\
\]
Thus, 1 kg more can be bought with a new price.
Therefore, 1 kg of sugar now is bought for the money, which was sufficient to buy 49 kg of sugar earlier.
Hence, the option B is correct.
Note: In solving these types of questions, we have to consider in terms of some unknown variable then deal with the problem in the same variable. Students have to calculate the total amount of sugar for a new price by dividing the 49 kg of sugar by the new price sugar. We must note that we have to find the amount of sugar for a new price by subtracting the old amount from the new amount of sugar.
Apply these, and then use the given conditions to find the required value.
Complete step-by-step solution
We are given that the price of sugar is reduced by \[2\% \].
Let us assume that the price of sugar is \[x\].
We will now calculate the price for 49 kg in terms of \[x\].
\[49 \times x = 49x\]
We will now find the new price of sugar by subtracting the reduction of 2 percent from the total.
\[
\left( {1 - \dfrac{2}{{100}}} \right)x = \left( {1 - 0.02} \right)x \\
= 0.98x \\
\]
We will now calculate the total amount of sugar for a new price by dividing the 49 kg of sugar by the new price sugar.
\[
\dfrac{{49x}}{{0.98x}} = \dfrac{{4900}}{{98}} \\
= 50{\text{ kg}} \\
\]
Thus, the total amount of sugar for a new price is 50 kg.
Subtracting the 49 kg of sugar from the total amount of sugar for a new price, we get
\[
50{\text{ kg}} - 49{\text{ kg}} = \left( {50 - 49} \right){\text{kg}} \\
= 1{\text{ kg}} \\
\]
Thus, 1 kg more can be bought with a new price.
Therefore, 1 kg of sugar now is bought for the money, which was sufficient to buy 49 kg of sugar earlier.
Hence, the option B is correct.
Note: In solving these types of questions, we have to consider in terms of some unknown variable then deal with the problem in the same variable. Students have to calculate the total amount of sugar for a new price by dividing the 49 kg of sugar by the new price sugar. We must note that we have to find the amount of sugar for a new price by subtracting the old amount from the new amount of sugar.
Recently Updated Pages
JEE Main Mock Test 2025-26: Principles Related To Practical

JEE Main 2025-26 Experimental Skills Mock Test – Free Practice

JEE Main 2025-26 Electronic Devices Mock Test: Free Practice Online

JEE Main 2025-26 Mock Tests: Free Practice Papers & Solutions

JEE Main 2025-26: Magnetic Effects of Current & Magnetism Mock Test

JEE Main Statistics and Probability Mock Test 2025-26

Trending doubts
JEE Main Marks vs Percentile 2026: Predict Your Score Easily

JEE Main Cutoff 2026: Category-wise Qualifying Percentile

JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Marks vs Rank 2026: Expected Rank for 300 to 0 Marks

NIT Cutoff 2026: Tier-Wise Opening and Closing Ranks for B.Tech. Admission

JEE Mains 2026 Subject Wise Percentile Explained

Other Pages
CBSE Class 10 Maths Question Paper 2026 OUT Download PDF with Solutions

Complete List of Class 10 Maths Formulas (Chapterwise)

NCERT Solutions For Class 10 Maths Chapter 11 Areas Related To Circles - 2025-26

All Mensuration Formulas with Examples and Quick Revision

NCERT Solutions For Class 10 Maths Chapter 13 Statistics - 2025-26

NCERT Solutions For Class 10 Maths Chapter 14 Probability - 2025-26

