Question

The final product C, obtained in the reaction, would be:


A.
B.
C.
D.

Answer 1

Hint: \[A{c_2}O\] stands for acetic anhydride which is used as a acetylating reagent in the first step. In the second step bromination takes place with bromine in acetic acid and in the third step hydrolysis takes place.

Complete step by step solution:By looking in the reaction sequence, it can be seen that the reaction is taking place in three steps.
In the first step p-toluidine reacts with acetic anhydride to form an acetylated compound known as N-p-tolylacetamide. Acetylation is a reaction where an acetyl group is introduced to the reactant. In the first step, amine is getting converted to amide.
In the second step, p-tolyl acetamide reacts with bromine in presence of acetic acid to form N-(2-bromo-4-methylphenyl)acetamide. The reaction is known as bromination reaction where bromine is added to the ortho position of the reactant.
In the third step, N-(2-bromo-4-methylphenyl)acetamide undergoes hydrolysis to form 2-bromo-4-methylbenzenamine. Hydrolysis is a reaction where one of the reactants is water or in other way a water molecule is added to the reactant. Here, the amide group is again converted to amine group.
The overall reaction for the conversion is shown below.
Image: Reaction sequence

Image: Reaction sequence

Therefore, option C is correct.

Note: The common name of N-(2-bromo-4-methylphenyl)acetamide is bromoacetanilide. The final compound formed is a monobromo compound as only one bromine atom is attached. It should be noted that acetic acid in bromination is used as a solvent.