
One poise is equal to:
A. 100 centipoise
B. 0.1 kg $m^{ -1 }s^{ -1 }$
C. Both A and B
D. 1 kg $m^{ -1 }s^{ -1 }$
Answer
224.1k+ views
Hint: To answer this question you should know that poise is a unit of dynamic viscosity. Now you can write the formula of viscosity and from there you can write the units.
Complete step by step answer:
Now, we will discuss the stepwise answer.
Poise - The poise (P) is the unit of dynamic viscosity (absolute viscosity) in the CGS system of units. This unit is named after Jean Léonard Marie Poiseuille.
Dynamic viscosity - Dynamic viscosity is the measurement of the fluid’s internal resistance to flow.
The formula for dynamic viscosity can be written as,
$\eta \quad =\quad \dfrac { F/A }{ dv/dx }$
Where,
$\eta$ = viscosity
F/A = pressure = unit - N/$m^{ 2 }$
dv/dx = change in velocity of liquid with respect to change in distance travelled by the liquid = unit - $s^{ -1 }$
So, the unit of viscosity ($\eta$) can be written as - N $m^{ -2 }$s or Pa.s or kg $m^{ -1 }s^{ -1 }$
We can convert this SI unit (N $m^{ -2 }$.s) to CGS unit (Poise) as,
1 kg $m^{ -1 }s^{ -1 }$ = 10 P
So, 1 P = 0.1 kg $m^{ -1 }s^{ -1 }$
Also,
1 cP (centipoise) = $10^{ -2 }$ P
1 P = 100 cP
Hence, we can conclude that,
One poise = 100 centipoise = 0.1 kg $m^{ -1 }s^{ -1 }$
Therefore, we can conclude that the correct answer to this question is option C.
Note: We should be aware of the fact that the poise is often used with the metric prefix centi- because the viscosity of water at 20 $^{ 0 }$C (NTP) is almost exactly 1 centipoise.
We already know a centipoise is one-hundredth of poise.
Complete step by step answer:
Now, we will discuss the stepwise answer.
Poise - The poise (P) is the unit of dynamic viscosity (absolute viscosity) in the CGS system of units. This unit is named after Jean Léonard Marie Poiseuille.
Dynamic viscosity - Dynamic viscosity is the measurement of the fluid’s internal resistance to flow.
The formula for dynamic viscosity can be written as,
$\eta \quad =\quad \dfrac { F/A }{ dv/dx }$
Where,
$\eta$ = viscosity
F/A = pressure = unit - N/$m^{ 2 }$
dv/dx = change in velocity of liquid with respect to change in distance travelled by the liquid = unit - $s^{ -1 }$
So, the unit of viscosity ($\eta$) can be written as - N $m^{ -2 }$s or Pa.s or kg $m^{ -1 }s^{ -1 }$
We can convert this SI unit (N $m^{ -2 }$.s) to CGS unit (Poise) as,
1 kg $m^{ -1 }s^{ -1 }$ = 10 P
So, 1 P = 0.1 kg $m^{ -1 }s^{ -1 }$
Also,
1 cP (centipoise) = $10^{ -2 }$ P
1 P = 100 cP
Hence, we can conclude that,
One poise = 100 centipoise = 0.1 kg $m^{ -1 }s^{ -1 }$
Therefore, we can conclude that the correct answer to this question is option C.
Note: We should be aware of the fact that the poise is often used with the metric prefix centi- because the viscosity of water at 20 $^{ 0 }$C (NTP) is almost exactly 1 centipoise.
We already know a centipoise is one-hundredth of poise.
Recently Updated Pages
JEE Main 2026 Session 1 Correction Window Started: Check Dates, Edit Link & Fees

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Trending doubts
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Hybridisation in Chemistry – Concept, Types & Applications

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Organic Chemistry Some Basic Principles And Techniques Class 11 Chemistry Chapter 8 CBSE Notes - 2025-26

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

