
What is the median for the following observations: \[2,5,8,4,9,6,7\]
A. \[6\]
B. \[8\]
C. \[4\]
D. \[4.5\]
Answer
232.5k+ views
Hint: The median is the middle value of the given observations when arranging the observations in an ascending or descending order. It is known as a measure of central tendency. So, to find the median of given observations, atfirst arrange those observations in ascending or descending order and then use the formula of median. The formula is different for even and odd numbers of observations.
Formula Used:
If the total number of observations is odd, then the formula of the median is
Median = \[\left( {\dfrac{{n + 1}}{2}} \right)\]-th observation, where \[n\] is the number of given observations.
If the total number of observations is even, then the formula of the median is
Median = The average of \[\left( {\dfrac{n}{2}} \right)\]-th observation and \[\left( {\dfrac{n}{2}} \right) + 1\]-th observation, where \[n\] is the number of given observations.
Complete step by step solution:
The given observations are \[2,5,8,4,9,6,7\].
Arrange the observations in ascending or descending order.
Let us take ascending order.
After arranging in ascending order, we get \[2,4,5,6,7,8,9\]
Count the number of observations.
The number of observations is \[7\].
So, \[n = 7\], which is odd.
Use the formula to calculate the median for odd number observations.
So, median = \[\left( {\dfrac{{7 + 1}}{2}} \right)\]-th observation i.e. the \[4\]-th observation.
Find the \[4\]-th observation from the given observations.
The \[4\]-th observation is \[6\].
So, the median of the given observations is \[6\].
Option ‘A’ is correct
Note: Here we have used the formula to calculate the odd number of the Median = \[\left( {\dfrac{{n + 1}}{2}} \right)\]. Do not mess up with the formula to calculate the median for odd or even number observations. Also, without arranging the terms properly, one will not get the median.
Formula Used:
If the total number of observations is odd, then the formula of the median is
Median = \[\left( {\dfrac{{n + 1}}{2}} \right)\]-th observation, where \[n\] is the number of given observations.
If the total number of observations is even, then the formula of the median is
Median = The average of \[\left( {\dfrac{n}{2}} \right)\]-th observation and \[\left( {\dfrac{n}{2}} \right) + 1\]-th observation, where \[n\] is the number of given observations.
Complete step by step solution:
The given observations are \[2,5,8,4,9,6,7\].
Arrange the observations in ascending or descending order.
Let us take ascending order.
After arranging in ascending order, we get \[2,4,5,6,7,8,9\]
Count the number of observations.
The number of observations is \[7\].
So, \[n = 7\], which is odd.
Use the formula to calculate the median for odd number observations.
So, median = \[\left( {\dfrac{{7 + 1}}{2}} \right)\]-th observation i.e. the \[4\]-th observation.
Find the \[4\]-th observation from the given observations.
The \[4\]-th observation is \[6\].
So, the median of the given observations is \[6\].
Option ‘A’ is correct
Note: Here we have used the formula to calculate the odd number of the Median = \[\left( {\dfrac{{n + 1}}{2}} \right)\]. Do not mess up with the formula to calculate the median for odd or even number observations. Also, without arranging the terms properly, one will not get the median.
Recently Updated Pages
Mutually Exclusive vs Independent Events: Key Differences Explained

Area vs Volume: Key Differences Explained for Students

Area of an Octagon Formula Explained Simply

Absolute Pressure Formula Explained: Key Equation & Examples

Central Angle of a Circle Formula Explained Quickly

Difference Between Vapor and Gas: JEE Main 2026

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Jan 21 Shift 1 Question Papers with Solutions & Answer Keys – Detailed Day 1 Analysis

JEE Main Marks vs Percentile 2026: Calculate Percentile and Rank Using Marks

JEE Main 2026 Jan 22 Shift 1 Today Paper Live Analysis With Detailed Solutions

JEE Mains 2026 January 21 Shift 2 Question Paper with Solutions PDF - Complete Exam Analysis

JEE Main 2026 Jan 22 Shift 2 Today Paper Live Analysis With Detailed Solutions

Other Pages
Pregnancy Week and Due Date Calculator: Find How Far Along You Are

NCERT Solutions For Class 10 Maths Chapter 11 Areas Related to Circles (2025-26)

NCERT Solutions For Class 10 Maths Chapter 12 Surface Areas and Volumes (2025-26)

All Mensuration Formulas with Examples and Quick Revision

Complete List of Class 10 Maths Formulas (Chapterwise)

NCERT Solutions for Class 10 Maths Chapter 13 Statistics

