
Laboratory method for the preparation of acetyl chloride is.
(a) \[C{H_3}COOH + SOC{l_2} \to C{H_3}COCl\]
(b) \[C{H_3}COOH + PC{l_3} \to C{H_3}COCl\]
(c) \[C{H_3}COONa + PC{l_3} \to C{H_3}COCl\]
(d) All of these
Answer
220.2k+ views
Hint: The acylation involves the removal of \[ - OH\] group of carboxylic acids through chlorine (\[ - Cl\]) to form acyl chlorides or acid chlorides(\[RCOCl\]).
Complete step-by-step answer:
Sulphur dichloride oxide or thionyl chloride (\[SOC{l_2}\])
It is a colourless liquid form at room temperature.
In the reaction of thionyl chloride with carboxylic acid, the formation of an acyl chloride occurs with the liberation of gaseous byproducts such as sulphur dioxide (\[S{O_2}\]) and hydrogen chloride (\[HCl\] ) gases. In this method, the separation of acid chlorides (\[RCOCl\]) is simplified to an extent because the by-products are both gases. Therefore, this method is preferable for laboratory use.
\[C{H_3}COOH + SOC{l_2} \to C{H_3}COCl + S{O_2} + HCl\]
Phosphorus trichloride (\[PC{l_3}\])
It is a colourless liquid and reacts with water violently with the formation of hydrogen chloride (\[HCl\] ) gas.
Similar to thionyl chloride the \[PC{l_3}\]also reacts with carboxylic acids and forms acid chlorides. The byproduct of this reaction is phosphoric acid (\[{H_3}P{O_4}\]) which is solid in nature and cannot be separated easily from the reaction product (\[RCOCl\]).
\[C{H_3}COOH + PC{l_3} \to C{H_3}COCl + {H_3}P{O_4}\]
When \[PC{l_3}\]react with sodium salt acetic acid (\[C{H_3}COONa\]) it forms \[C{H_3}COCl\] and \[NaCl\] as a byproduct. Due to poor yield, this method is not acceptable for laboratory use.
\[C{H_3}COONa + PC{l_3} \to C{H_3}COCl + NaCl\]
The above discussion indicates that thionyl chloride is a suitable candidate for laboratory use because the by-products are gases which can easily escape. Hence, answer (a) is correct.
Note: The thionyl chloride and phosphorus trichloride need to be handled very carefully because when they encounter water they react vigorously.
Complete step-by-step answer:
Sulphur dichloride oxide or thionyl chloride (\[SOC{l_2}\])
It is a colourless liquid form at room temperature.
In the reaction of thionyl chloride with carboxylic acid, the formation of an acyl chloride occurs with the liberation of gaseous byproducts such as sulphur dioxide (\[S{O_2}\]) and hydrogen chloride (\[HCl\] ) gases. In this method, the separation of acid chlorides (\[RCOCl\]) is simplified to an extent because the by-products are both gases. Therefore, this method is preferable for laboratory use.
\[C{H_3}COOH + SOC{l_2} \to C{H_3}COCl + S{O_2} + HCl\]
Phosphorus trichloride (\[PC{l_3}\])
It is a colourless liquid and reacts with water violently with the formation of hydrogen chloride (\[HCl\] ) gas.
Similar to thionyl chloride the \[PC{l_3}\]also reacts with carboxylic acids and forms acid chlorides. The byproduct of this reaction is phosphoric acid (\[{H_3}P{O_4}\]) which is solid in nature and cannot be separated easily from the reaction product (\[RCOCl\]).
\[C{H_3}COOH + PC{l_3} \to C{H_3}COCl + {H_3}P{O_4}\]
When \[PC{l_3}\]react with sodium salt acetic acid (\[C{H_3}COONa\]) it forms \[C{H_3}COCl\] and \[NaCl\] as a byproduct. Due to poor yield, this method is not acceptable for laboratory use.
\[C{H_3}COONa + PC{l_3} \to C{H_3}COCl + NaCl\]
The above discussion indicates that thionyl chloride is a suitable candidate for laboratory use because the by-products are gases which can easily escape. Hence, answer (a) is correct.
Note: The thionyl chloride and phosphorus trichloride need to be handled very carefully because when they encounter water they react vigorously.
Recently Updated Pages
Difference Between Alcohol and Phenol: Structure, Tests & Uses

Class 12 Chemistry Mock Test Series for JEE Main – Free Online Practice

Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

The D and F Block Elements Class 12 Chemistry Chapter 4 CBSE Notes - 2025-26

NCERT Solutions for Class 12 Chemistry Chapter Chapter 7 Alcohol Phenol and Ether

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 8 Aldehydes Ketones And Carboxylic Acids

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

