Question

IUPAC name of $[Cr{{(N{{H}_{3}})}_{5}}C{{O}_{3}}]Cl$

Answer 1

Hint: To answer this question we have to know about IUPAC naming rules for inorganic compounds. At first we have to determine the oxidation state of the central metal atom that is $Cr$.

Complete Step by Step Solution:
The given compound is $[Cr{{(N{{H}_{3}})}_{3}}C{{O}_{3}}]Cl$.
We know that amine group is a neutral group so, it does not contribute any charge. Again this complex has five amine groups so, the naming for amine is pentaammine.
The $C{{O}_{3}}$ group has $-2$ charge and the term for this group is carbonato.
Here the central metal atom is chromium.
The symbol of chloride ligand is $Cl$ .
Let the oxidation state of $Cr$ is $x$ .
Again chloride is a negative ligand so, the charge of chloride ligand is $-1$ .
The charge due to amine is zero.
The $C{{O}_{3}}$ group has $-2$ charge.
Thus we can write as follows-
$x+0\times 5+(-2)-1=0$
$x-3=0$
$x=+3$
So, the value of $x$ by solving the above equation is $+3$ .
So, the oxidation state of the central metal atom chromium is also $+3$ .
Thus the IUPAC name of the given complex is $[Cr{{(N{{H}_{3}})}_{3}}C{{O}_{3}}]Cl$ is pentaamminechlorochromium(III)chloride.

Additional information: Chromium is a transition element. In the $+3$ oxidation state the metal $d$ orbital has $6$ electrons and acts as an oxidizing agent. The symbol of chromium is $Cr$ .

Note: The full form of IUPAC is International Union of Pure and Applied Chemistry. These naming rules are used to name the inorganic and organic compounds.