
In the series of reaction \[{C_6}{H_5}N{H_2} + NaN{O_2}/HCl(0 - {5^ \circ }C)\,\, \to \,\,Y + N2 + HCl\] X and Y are respectively
(A) ${C_6}{H_5} - N = N - {C_6}{H_5},\,{C_6}{H_5}{N_2}^ + C{l^ - }$
(B) ${C_6}{H_5}{N_2}^ + C{l^ - },\,{C_6}{H_5} - N = N - {C_6}{H_5}$
(C) ${C_6}{H_5}{N_2}^ + C{l^ - },\,{C_6}{H_5} - N = N - {C_6}{H_5}$
(D) ${C_6}{H_5}N{O_2},\,{C_6}{H_6}$
Answer
233.1k+ views
Hint: Nitromethane \[\left( {C{H_3}N{O_2}} \right)\] is one of the most widely used organic chemical building blocks and an essential organic chemical raw material. Nitro functional groups are the functional group found in CH3NO2 (NO2). When it reacts in the presence of $Sn$ and $HCl$ it forms methyl amine having chemical formula $C{H_3}N{H_2}$ .
Complete Step by Step Solution:
An amino functional group is substituted for one of the benzene hydrogens in aniline, a primary arylamine. It belongs to the class of anilines and is a primary arylamine. Organic substance aniline has the chemical formula\[{C_6}{H_5}N{H_2}\] . The simplest aromatic amine is aniline, which consists of an amino group joined to a phenyl group. It is an important commodity chemical for industry and a flexible starting point for the synthesis of fine chemicals.
C6H5NH2 is aniline. If we consider its structure we see that it has a benzene ring and amine functional is present at one carbon atom.
When it is made to react with sodium nitrite with $HCl$ under ${0^ \circ } - {5^ \circ }C$ temperature condition. Whenever sodium nitrite and hydrochloric acid react with each other they form a nitrous acid compound. When this compound reacts with primary amine compound, diazonium ion \[\left( {{C_6}{H_5}{N_2}^ + C{l^ - }} \right)\] is formed whose structure has benzene ring and the amine group is converted into diazonium ion having positive charge on sodium and negative charge on chloride.
Now it is further reacted with water under warm conditions. When diazonium ion react with water in warm conditions it forms a phenol compound.
Hence, option B. is the answer.
Note: To create dyed fabrics, benzene diazonium chloride is used in the dye and pigment industries. Particularly aryl derivatives, they are helpful in the synthesis of a wide range of chemical molecules. At 273-278 K, aniline and nitrous acid react to produce it. The interaction between sodium nitrite and hydrochloric acid results in the production of nitrous acid in the reaction mixture.
Complete Step by Step Solution:
An amino functional group is substituted for one of the benzene hydrogens in aniline, a primary arylamine. It belongs to the class of anilines and is a primary arylamine. Organic substance aniline has the chemical formula\[{C_6}{H_5}N{H_2}\] . The simplest aromatic amine is aniline, which consists of an amino group joined to a phenyl group. It is an important commodity chemical for industry and a flexible starting point for the synthesis of fine chemicals.
C6H5NH2 is aniline. If we consider its structure we see that it has a benzene ring and amine functional is present at one carbon atom.
When it is made to react with sodium nitrite with $HCl$ under ${0^ \circ } - {5^ \circ }C$ temperature condition. Whenever sodium nitrite and hydrochloric acid react with each other they form a nitrous acid compound. When this compound reacts with primary amine compound, diazonium ion \[\left( {{C_6}{H_5}{N_2}^ + C{l^ - }} \right)\] is formed whose structure has benzene ring and the amine group is converted into diazonium ion having positive charge on sodium and negative charge on chloride.
Now it is further reacted with water under warm conditions. When diazonium ion react with water in warm conditions it forms a phenol compound.
Hence, option B. is the answer.
Note: To create dyed fabrics, benzene diazonium chloride is used in the dye and pigment industries. Particularly aryl derivatives, they are helpful in the synthesis of a wide range of chemical molecules. At 273-278 K, aniline and nitrous acid react to produce it. The interaction between sodium nitrite and hydrochloric acid results in the production of nitrous acid in the reaction mixture.
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