
In the isolation of fluorine a number of difficulties were encountered. Which of the following statements are incorrect:
(The question has multiple correct options.)
(A) Fluorine reacts with moist glass vessels
(B) Fluorine has a great affinity for hydrogen
(C) Electrolysis of aqueous $HF$ gives ozonized oxygen
(D) The potential required for the discharge of the fluoride ions is the lowest.
Answer
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Hint: Fluorine is extracted from minerals like fluorite or calcium fluoride. It can be stored in cylinders of stainless steel under high pressure if the valves of the cylinders are free from traces of organic matter. It is greenish yellow in colour.
Complete Step by Step Solution:
(A) Fluorine does not react with moist glass vessels. It reacts with water and glass vessels. In reaction with water, it gives hydrogen fluoride ($HF$). So, this is the incorrect statement.
(B) Fluorine has a great affinity for hydrogen. It has a tendency to react with hydrogen to form $HF$. The hydrogen-fluorine bond is a very strong bond. But it does not create any difficulty in the extraction of fluorine. So, this is the incorrect statement.
(C) Electrolysis of aqueous $HF$ does not give ozonised oxygen(${{O}_{3}}$). It gives oxygen(${{O}_{2}}$ ). So, this is the incorrect statement.
(D) The potential required for the discharge of the fluoride ions is the lowest. This statement is correct.
Correct Options: (A), (B) and (C).
Note: Fluorine is a very reactive metal, and the bond formed between hydrogen and fluorine in $HF$ is very strong. When this $HF$ is dissolved in water, it becomes hydrofluoric acid.
Complete Step by Step Solution:
(A) Fluorine does not react with moist glass vessels. It reacts with water and glass vessels. In reaction with water, it gives hydrogen fluoride ($HF$). So, this is the incorrect statement.
(B) Fluorine has a great affinity for hydrogen. It has a tendency to react with hydrogen to form $HF$. The hydrogen-fluorine bond is a very strong bond. But it does not create any difficulty in the extraction of fluorine. So, this is the incorrect statement.
(C) Electrolysis of aqueous $HF$ does not give ozonised oxygen(${{O}_{3}}$). It gives oxygen(${{O}_{2}}$ ). So, this is the incorrect statement.
(D) The potential required for the discharge of the fluoride ions is the lowest. This statement is correct.
Correct Options: (A), (B) and (C).
Note: Fluorine is a very reactive metal, and the bond formed between hydrogen and fluorine in $HF$ is very strong. When this $HF$ is dissolved in water, it becomes hydrofluoric acid.
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