
In the following reaction the catalyst used is-

A. Al2O3
B. Cr2O3
C. Al2O3 & Cr2O3
D. Zn dust
Answer
162k+ views
Hint: In most of the oxidation reactions in organic chemistry Cr2O3 is used to oxidize the compounds and also for cyclization. Cr2O3 is a strong oxidizing agent. Al2O3 is also a good oxidizing agent and also a dehydrogenation catalyst. It removes H2 molecules from the compounds. Together they act as a good oxidizing agent and as well as used as a catalyst for aromatization. The conversion of aliphatic organic compounds into aromatic compounds is called aromatization. Aromatic compounds are more stable than aliphatic compounds.
Complete Step by Step Answer:
Given reaction in the question is-

This chemical reaction is practically, chemically, or thermodynamically not possible because the reactant in this reaction contains 6 radical carbon which is a highly unstable compound so it cannot be formed even as an intermediate in the reaction.
But we can convert n-Hexane into benzene using Al2O3 & Cr2O3 as catalyst because Cr2O3 & Al2O3 acts as a good oxidizing agent and good dehydrogenating agent respectively. So together in combination with each other, they act as a good catalyst for cyclization & aromatization in organic chemistry. It is also called a reforming process.
The given reaction will be:

And the mechanism of the reaction is

In the reaction, the terminal carbons oxidized in presence of Cr2O3 and form a covalent bond converting n-hexane into cyclohexane. Then in presence of Al2O3, it aromatizes and forms benzene.
Thus, Option (C) is correct
Note: Vanadium oxide is also used for the aromatization of benzene. To produce toluene from n-hexane we can use Friedel Craft Alkylation. This aromatization of n-hexane is also called dehydroaromatization.
Complete Step by Step Answer:
Given reaction in the question is-

This chemical reaction is practically, chemically, or thermodynamically not possible because the reactant in this reaction contains 6 radical carbon which is a highly unstable compound so it cannot be formed even as an intermediate in the reaction.
But we can convert n-Hexane into benzene using Al2O3 & Cr2O3 as catalyst because Cr2O3 & Al2O3 acts as a good oxidizing agent and good dehydrogenating agent respectively. So together in combination with each other, they act as a good catalyst for cyclization & aromatization in organic chemistry. It is also called a reforming process.
The given reaction will be:

And the mechanism of the reaction is

In the reaction, the terminal carbons oxidized in presence of Cr2O3 and form a covalent bond converting n-hexane into cyclohexane. Then in presence of Al2O3, it aromatizes and forms benzene.
Thus, Option (C) is correct
Note: Vanadium oxide is also used for the aromatization of benzene. To produce toluene from n-hexane we can use Friedel Craft Alkylation. This aromatization of n-hexane is also called dehydroaromatization.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main Mock Test Series Class 12 Chemistry for FREE

Classification of Drugs Based on Pharmacological Effect, Drug Action

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2026 Syllabus PDF - Download Paper 1 and 2 Syllabus by NTA

JEE Main Eligibility Criteria 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

Solutions Class 12 Notes: CBSE Chemistry Chapter 1
