
If the reaction of $HN{{O}_{2}}$ with ‘A’ gives quaternary ammonium salt, then what is compound "A"?
(A) Methyl amine
(B) Dimethyl amine
(C) Trimethylamine
(D) Aniline
Answer
162.3k+ views
Hint: Quaternary ammonium salt is an organic compound in which the ammonia molecule is tetra substituted with alkyl or aryl groups and has a cationic state. They are used as surfactants, electrolytes, ionic liquids, alkylating agents, phase transfer catalysts, deprotecting agents, and other materials. Examples of quaternary ammonium salts are cetylpyridinium chloride, cetylpyridinium bromide, benzethonium chloride, etc.
Complete Step by Step Solution:
Reaction of $HN{{O}_{2}}$ with aliphatic amines is an important test for distinguishing primary, secondary, and tertiary amines. On treatment of primary amine with nitrous acid ($HN{{O}_{2}}$), nitrogen gas is released, which can be seen as bubbles. Treatment of nitrous acid ($HN{{O}_{2}}$) with secondary amines gives an insoluble oil layer of nitrosamine.
Quaternary ammonium salts with a clear solution are formed only when a tertiary amine reacts with nitrous acid. In this case, nitrous acid ($HN{{O}_{2}}$) reacts with trimethyl amine to give quaternary ammonium salts. Hence, the compound ‘A’ is trimethylamine.
Correct option (C) Trimethylamine.
Additional Information: The quaternary ammonium salt produced by the reaction of nitrous acid with tertiary amine can decompose further to produce nitrosamines and alcohol.
Note: As methyl amine is a primary amine, aniline is a primary aromatic amine, and dimethyl amine is a secondary amine, so these compounds do not give quaternary salts on reaction with nitrous acid ($HN{{O}_{2}}$).
Complete Step by Step Solution:
Reaction of $HN{{O}_{2}}$ with aliphatic amines is an important test for distinguishing primary, secondary, and tertiary amines. On treatment of primary amine with nitrous acid ($HN{{O}_{2}}$), nitrogen gas is released, which can be seen as bubbles. Treatment of nitrous acid ($HN{{O}_{2}}$) with secondary amines gives an insoluble oil layer of nitrosamine.
Quaternary ammonium salts with a clear solution are formed only when a tertiary amine reacts with nitrous acid. In this case, nitrous acid ($HN{{O}_{2}}$) reacts with trimethyl amine to give quaternary ammonium salts. Hence, the compound ‘A’ is trimethylamine.
Correct option (C) Trimethylamine.
Additional Information: The quaternary ammonium salt produced by the reaction of nitrous acid with tertiary amine can decompose further to produce nitrosamines and alcohol.
Note: As methyl amine is a primary amine, aniline is a primary aromatic amine, and dimethyl amine is a secondary amine, so these compounds do not give quaternary salts on reaction with nitrous acid ($HN{{O}_{2}}$).
Recently Updated Pages
Fluid Pressure - Important Concepts and Tips for JEE

JEE Main 2023 (February 1st Shift 2) Physics Question Paper with Answer Key

Impulse Momentum Theorem Important Concepts and Tips for JEE

Graphical Methods of Vector Addition - Important Concepts for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 1) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
