
Identify ‘B’ in the reaction,
$Acetamide\xrightarrow[\Delta ]{{{P_2}{O_5}}}A\xrightarrow{{4H}}B$
(A) $C{H_3}N{H_2}$
(B) $C{H_3}C{H_2}N{H_2}$
(C) $C{H_3}CN$
(D) $C{H_3}COON{H_4}$
Answer
219.9k+ views
Hint: As in the above given reaction in the question we have to find the product from acetamide reacts with phosphorus pentoxide as in the presence of heat we get the first product as compound A. Now by getting a reduction reaction of compound A with the presence Hydrogen atom we get the final product as B. And as given in the question we have to identify B as from completing the reaction.
Complete Step by Step Solution:
Firstly, we react acetamide with phosphorus pentoxide with giving it heat to get the first product as A,
$C{H_3}CON{H_2}\xrightarrow[\Delta ]{{{P_2}{O_5}}}C{H_3}CN + {H_2}O$
In the above reaction we get the product as Methyl Cyanide as with the presence of water.
Now By taking another reaction to find the product B, we react Methyl Cyanide as in the presence of Hydrogen atom we get the following reaction as,
$C{H_3}CN\xrightarrow{{4H + }}C{H_3}C{H_2}N{H_2}$
As in above reaction we get the final product which we need in this question now we write whole reaction in one form to simplify full process of the reaction,
$C{H_3}CON{H_2}\xrightarrow[\Delta ]{{{P_2}{O_5}}}C{H_3}CN\xrightarrow{{4H + }}C{H_3}C{H_2}N{H_2}$
By taking the full conclusion about the reaction we get the ‘B’ in this reaction is $C{H_3}C{H_2}N{H_2}$ .
Hence, the correct option is (B).
Note: We get $C{H_3}C{H_2}N{H_2}$ as a product in this question which is also said by the name of Ethylamine. This is also a method by which we can prepare amine using a Amide and a part of Preparation of amines using Amides and easy to execute in reactions.
Complete Step by Step Solution:
Firstly, we react acetamide with phosphorus pentoxide with giving it heat to get the first product as A,
$C{H_3}CON{H_2}\xrightarrow[\Delta ]{{{P_2}{O_5}}}C{H_3}CN + {H_2}O$
In the above reaction we get the product as Methyl Cyanide as with the presence of water.
Now By taking another reaction to find the product B, we react Methyl Cyanide as in the presence of Hydrogen atom we get the following reaction as,
$C{H_3}CN\xrightarrow{{4H + }}C{H_3}C{H_2}N{H_2}$
As in above reaction we get the final product which we need in this question now we write whole reaction in one form to simplify full process of the reaction,
$C{H_3}CON{H_2}\xrightarrow[\Delta ]{{{P_2}{O_5}}}C{H_3}CN\xrightarrow{{4H + }}C{H_3}C{H_2}N{H_2}$
By taking the full conclusion about the reaction we get the ‘B’ in this reaction is $C{H_3}C{H_2}N{H_2}$ .
Hence, the correct option is (B).
Note: We get $C{H_3}C{H_2}N{H_2}$ as a product in this question which is also said by the name of Ethylamine. This is also a method by which we can prepare amine using a Amide and a part of Preparation of amines using Amides and easy to execute in reactions.
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