
Why does pressure increase when volume decreases?
Answer
163.5k+ views
Hint: Before we get an answer to this question let’s understand pressure and volume. Pressure is the force which is exerted on the object by something in contact with it. Volume is defined as the amount of space that an object or a substance occupies. Now let us solve the given question.
Complete step by step solution:
Consider Boyle’s law which gives the relation between pressure and volume. It states that at a constant temperature the volume of a gas varies inversely with the pressure exerted on it. Let’s see how the volume of a gas decreases when the pressure is increased. Assume that you have taken a mixture of gas in a large container, there are a number of gas molecules in there which try to push the walls of the container thereby creating pressure.
Now reduce the volume of the container, then, the gas particles are now restricted to move in a smaller volume but still exert the same pushing force (due to the same amount of gas being present) and hence increasing the pressure. Consider another example. Let us assume we have a box half-filled with soft candies. Let this be a substitute for the molecules within a material.
Now, let us start shrinking the box’s volume by 1% for every second. So, with the reduction in the volume of the box, the candies start getting closer together. By the time the box is reduced to the size of a matchbox, the candies will all be crushed together (hence leading to the higher density of the candy). Reduction in volume leads to higher pressure and higher density.
Note:If the volume remains constant (in a closed container) the temperature increases thereby increasing the pressure. The temperature increases because the movement of the atoms increases leading to an increase in the pressure.
Complete step by step solution:
Consider Boyle’s law which gives the relation between pressure and volume. It states that at a constant temperature the volume of a gas varies inversely with the pressure exerted on it. Let’s see how the volume of a gas decreases when the pressure is increased. Assume that you have taken a mixture of gas in a large container, there are a number of gas molecules in there which try to push the walls of the container thereby creating pressure.
Now reduce the volume of the container, then, the gas particles are now restricted to move in a smaller volume but still exert the same pushing force (due to the same amount of gas being present) and hence increasing the pressure. Consider another example. Let us assume we have a box half-filled with soft candies. Let this be a substitute for the molecules within a material.
Now, let us start shrinking the box’s volume by 1% for every second. So, with the reduction in the volume of the box, the candies start getting closer together. By the time the box is reduced to the size of a matchbox, the candies will all be crushed together (hence leading to the higher density of the candy). Reduction in volume leads to higher pressure and higher density.
Note:If the volume remains constant (in a closed container) the temperature increases thereby increasing the pressure. The temperature increases because the movement of the atoms increases leading to an increase in the pressure.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Charging and Discharging of Capacitor

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
