Question

When $C{{l}_{2}}$ ​ gas is passed through hot and conc. solution of $KOH$ following compound is formed
A. $KCl$
B. $KCl{{O}_{3}}$
C. $KCl{{O}_{2}}$
D. $KCl{{O}_{4}}$

Answer 1

Hint: Strength of the base depends on its ionisation in water. Stronger bases easily ionize into OH ions. Potassium hydroxide is a strong base and chlorine is an acid type of gas. So, both undergo an acid base type of reaction to form a salt-like compound potassium chlorate. Chlorine is a gaseous substance which can liberate potassium chloride from a hot and concentrated solution of potassium hydroxide.

Complete Step by Step Answer:
When chlorine gas is passed through a hot and concentrated solution of potassium hydroxide, a strong base Chlorine gas reacts with the potassium hydroxide to produce potassium chloride, a salt of potassium, water along with potassium chlorate or $KCl{{O}_{3}}$. The reaction can be given as follows:
$3C{{l}_{2}}+6KOH\to 5KCl+KCl{{O}_{3}}+3{{H}_{2}}O$

Thus in this reaction three moles of chlorine gas reacts with six moles of a hot and concentrated solution of a strong base potassium hydroxide to produce five moles of a salt potassium chloride along with one mole of potassium chlorate and three moles of water as products.

Thus we can write that $C{{l}_{2}}$ ​ gas is passed through hot and conc. solution of $KOH$or potassium hydroxide two major products potassium chloride and potassium chlorate are formed.
Thus the correct options are A and B.

Note: The acid base reaction is also known as neutralisation reaction as acid and base reacts to form a neutral salt. Thus this reaction can be called a neutralisation reaction. In a reaction in water, it results in there being no excess of hydrogen or hydroxide ions present in the solution.