
Assertion:If $|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$, then the angle between $\vec{A}$ and $\vec{B}$ is $90{}^\circ $.
Reason: $\vec{A}+\vec{B}=\vec{B}+\vec{A}$
A. Both assertion and reason are correct and reason is the correct explanation for assertion
B. Both assertion and reason are correct but reason is not the correct explanation for assertion.
C. Assertion is correct but reason is incorrect.
D. Both assertion and reason are incorrect.
Answer
217.8k+ views
Hint: We are given an assertion and by following the assertion we are given the reason for that assertion. We are asked to find out whether the assertion and reason are correct and incorrect. Given $|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$. We first show that the angle between the two is $90{}^\circ $. Then we find out whether the reason is the correct explanation of assertion or not and choose the option which satisfies our answer.
Formula used:
$|\vec{A}+\vec{B}|=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }$
$|\vec{A}-\vec{B}|= \sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos (\pi -\theta )}$
Here, $A$ and $B$ are vectors and $\theta$ is the angle between them.
Complete step by step solution:
Given $|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$
We take square root on both sides, we get
$\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos (\pi -\theta )}$
As the square root cancel from both sides, we get
${{A}^{2}}+{{B}^{2}}+2AB\cos \theta ={{A}^{2}}+{{B}^{2}}+2AB(-\cos \theta )$
We know $-(\cos \theta )=-\cos \theta $
${{A}^{2}}+{{B}^{2}}+2AB\cos \theta ={{A}^{2}}+{{B}^{2}}-2AB\cos \theta $
By solving the above equation, we get
$4AB\cos \theta =0$
Hence, $\cos \theta =0$
We know $\cos 90{}^\circ =0$
Then $\cos \theta =\cos 90{}^\circ $
Which gives $\theta =90{}^\circ $
Also, we know in the properties of vector addition that vector addition is commutative.
Then $\vec{A}+\vec{B}=\vec{B}+\vec{A}$
Hence the assertion is correct but reason is not the correct explanation of the assertion.
Thus, option B is correct.
Note: In these types of questions, remember that while adding two vectors, do not only consider the magnitude of vectors but also consider the direction of the vectors. Students must know the basic trigonometric functions for finding out the correct option.
Formula used:
$|\vec{A}+\vec{B}|=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }$
$|\vec{A}-\vec{B}|= \sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos (\pi -\theta )}$
Here, $A$ and $B$ are vectors and $\theta$ is the angle between them.
Complete step by step solution:
Given $|\vec{A}+\vec{B}|=|\vec{A}-\vec{B}|$
We take square root on both sides, we get
$\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos (\pi -\theta )}$
As the square root cancel from both sides, we get
${{A}^{2}}+{{B}^{2}}+2AB\cos \theta ={{A}^{2}}+{{B}^{2}}+2AB(-\cos \theta )$
We know $-(\cos \theta )=-\cos \theta $
${{A}^{2}}+{{B}^{2}}+2AB\cos \theta ={{A}^{2}}+{{B}^{2}}-2AB\cos \theta $
By solving the above equation, we get
$4AB\cos \theta =0$
Hence, $\cos \theta =0$
We know $\cos 90{}^\circ =0$
Then $\cos \theta =\cos 90{}^\circ $
Which gives $\theta =90{}^\circ $
Also, we know in the properties of vector addition that vector addition is commutative.
Then $\vec{A}+\vec{B}=\vec{B}+\vec{A}$
Hence the assertion is correct but reason is not the correct explanation of the assertion.
Thus, option B is correct.
Note: In these types of questions, remember that while adding two vectors, do not only consider the magnitude of vectors but also consider the direction of the vectors. Students must know the basic trigonometric functions for finding out the correct option.
Recently Updated Pages
Apparent Frequency Explained: Formula, Uses & Examples

Calorimetry: Definition, Principles & Calculations

Centrifugal Force Explained: Definition, Formula & Examples

Charge in a Magnetic Field: Definition, Formula & Examples

Charging and Discharging of a Capacitor Explained Simply

Combination of Capacitors: Series and Parallel Explained

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

Understanding Atomic Structure for Beginners

