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# What are the products formed when moist chlorine gas is reacted with hypo?(a) ${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{,S,HCl}}$(b) ${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{3}}}{\text{,S,HCl}}$(c) ${\text{N}}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{4}}}{{\text{O}}_{\text{6}}}{\text{,N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{3}}}{\text{,HCl}}$(d) ${\text{N}}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{4}}}{{\text{O}}_{\text{6}}}{\text{,NaCl,HCl}}$

Last updated date: 18th Sep 2024
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Hint: To solve this problem, you need to know about the moist chlorine gas and hypo. It is obvious that moist chlorine gas is the chlorine gas in the presence of water. Also, you need to know that hypo is sodium thiosulphate.

Complete step by step solution:
We can solve this problem by writing all the reactants. First of all, our reactants are the moist chlorine which is chlorine gas in the presence of water. And another reactant is hypo which is also called sodium thiosulphate having the molecular formula${\text{N}}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}$. We can write the reaction:
$N{a_2}{S_2}{O_3} + C{l_2} + {H_2}O \to N{a_2}S{O_4} + S + HCl$
So, the products formed are${\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{,S,HCl}}$. Therefore, the correct option is (a).

- The sodium thiosulphate is also called hyposulphate or hypo. The molar mass of thiosulfate is 158.11 g/mol. The thiosulphate is present also in the form of pentahydrate salt (${\text{N}}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}{\text{.5}}{{\text{H}}_{\text{2}}}{\text{O}}$) with the molar mass of 248.18 g/mol.