Answer

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**Hint:**It is given that the polygon has 44 diagonal. So, apply the formula of diagonals of a polygon to obtain a quadratic equation of n. Solve the quadratic equation and then obtain the value of n by neglecting the negative value as the number of sides cannot be negative.

**Formula used:**

A polygon with n sides have \[\dfrac{{n(n - 3)}}{2}\] diagonals.

**Complete step by step solution:**

It is given that the polygon has 44 diagonals.

Therefore,

\[\dfrac{{n(n - 3)}}{2} = 44\]

\[{n^2} - 3n - 88 = 0\]

\[{n^2} - 11n + 8n - 88 = 0\]

\[n(n - 11) + 8(n - 11) = 0\]

\[(n + 8)(n - 11) = 0\]

\[n = - 8\] or \[n = 11\]

But number of sides of a polygon cannot be negative, therefore n=11.

**The correct option is C.**

**Additional information:**A polygon is a geometric object with two dimensions and a finite number of sides. A polygon's sides are made up of segments of straight lines that are joined end to end. As a result, a polygon's line segments are called its sides or edges. Vertex or corners correspond to the intersection of two line segments, where an angle is created. Having three sides makes a triangle which is a polygon. A circle is a plane figure as well, but it isn't regarded as a polygon because it's curved and without sides and angles. So, while all polygons are two-dimensional shapes, not all two-dimensional figures are polygons.

**Note:**Sometime students get confused and substitute 44 for n in the expression \[\dfrac{{n(n - 3)}}{2}\] and calculate to obtain the number of sides but this expression is for diagonal so we have to equate the expression \[\dfrac{{n(n - 3)}}{2}\] to 44 and solve to obtain n, where n is the number of sides.

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