Packing Efficiency - HCP and CCP structures for JEE Main Exam
We all know that the particles are arranged in different patterns in unit cells. Particles include atoms, molecules or ions. There is no concern for the arrangement of the particles in the lattice as there are always some empty spaces inside which are called void spaces. The aspect of the solid state with respect to quantity can be done with the help of packing efficiency.
“Packing efficiency can be defined as the percentage ration of the total volume of a solid occupied by spherical atoms. The formula is written as the ratio of the volume of one atom to the volume of cells is s3.”
Mathematically, the equation of packing efficiency can be written as
Number of Atoms × volume obtained by 1 share / Total volume of unit cell ×100 %
Packing efficiency is defined as the percentage ration of space obtained by constituent particles which are packed within the lattice. It can be evaluated with the help of geometry in three structures known as:
1. HCP and CCP structures 2. Body-centered cubic structures 3. Simple lattice structures of cubic
Factors of packing efficiency
There are many factors which are defined for affecting the packing efficiency of the unit cell:
1. A volume of a unit cell 2. Number of atoms in the lattice structure 3. Volume of atoms
HCP and CCP structures
In this, both types of packing efficiency, hexagonal close packing or cubical lattice closed packing is done, and the packing efficiency is the same in both. For calculating the packing efficiency in a cubical closed lattice structure, we assume the unit cell with the side length of ‘a’ and face diagonals AC to let it ‘b’.
When we see the ABCD face of the cube, we see the triangle of ABC in it. Let us suppose the radius of each sphere ball is ‘r’. Now correlating the radius and its edge of the cube, we continue with the following,
In triangle ABC, according to the Pythagoras theorem, we write it as:
AC2 = BC2 + AB2
Though AC = b and BC = a,
We substitute the values in the above equation, then we get
b2 = a2 + a2
b2 = 2a2
b = √2 a ---------- (1)
Also, the edge ‘b’ can be defined as follows in terms of radius ‘r’ which is equal to:
b = 4r ---------------- (2)
According to equation (1) and (2), we can write the following:
4r = √2 a
a = 2 √2 r
There are a total of 4 spheres in a CCP structured unit cell, the total volume occupied by it will be following:
4 × 4 / 3 π r3
And the total volume of a cube is the cube of its length of the edge (edge length)3. It means a3 or if defined in terms of ‘r’, then it
is (2 √2 r)3.
Thus, packing efficiency will be written as follows.
Packing efficiency = volume occupied by 4 spheres/ total volume of unit cell × 100 %
4 × 4 / 3 π r3 / (2 √2 r)3 × 100%
16 / 3 π r3 / (2 √2 r)3 ×100 %
Thus, packing efficiency in FCC and HCP structures is calculated as 74.05%.
In the same way, the relation between the radius ‘r’ and edge length of unit cell ‘a’ is r = 2a and the number of atoms is 6 in the HCP lattice.
Packing efficiency can be written as below,
Packing efficiency = Volume occupied by 6 spheres ×100 / Total volume of unit cells. 6 × 4 / 3 π r3 / (2 r)3 × 100% = 74.05% Examples are Magnesium, Titanium, Beryllium etc.
Body-centered structures of cubic structures
In body-centered cubic structures, the three atoms are arranged diagonally. For determining the packing efficiency, we consider a cube with the length of the edge, a face diagonal of length b and diagonal of cube represented as c.
In the triangle EFD, apply according to the theorem of Pythagoras,
b2 = a2 + a2 b2 = 2a2 b = √2 a
Now, in triangle AFD, according to the theorem of Pythagoras,
c2 = a2 + b2 = a2 + 2a2 c2 = 3a2 c = √3 a
Suppose if the radius of each sphere is ‘r’, then we can write it accordingly as follows.
c = 4r √3 a = 4r r = √3/ 4 a
There are two number of atoms in the BCC structure, then the volume of constituent spheres will be as following,
2 × (4/3) π r3
Thus, packing efficiency = Volume obtained by 2 spheres × 100 / Total volume of cell
= 2 × (4/3) π r3 / 43 / √3 r = 68%
Therefore, the value of APF = Natom Vatom / Vcrystal = 2 × (4/3) π r3 / 43 / √3 r
= π √3 / 8 = 0.68017476
Thus, the packing efficiency of the body-centered unit cell is around 68%. The metals such as iron and chromium come under BSS category.
Simple cubic lattice
In simple cubic lattice structure, the atoms are located only on the corners of the cube. It is stated that we can see the particles are in touch only at the edges.
Therefore, if the Radius of each and every atom is r and the length of the cube edge is a, then we can find a relation between them as follows,
2a = r
Though simple unit cell of cube consists of only 1 atom, and the volume of the unit cells containing only 1 atom will be as follows. 4 / 3 π r3
The volume of the unit cell will be a3 or 2a3 that gives the result of 8a3.
Thus, packing efficiency = Volume obtained by 1 sphere × 100 / Total volume of unit cells
= 4 / 3 π r3 / 8r3 × 100% = 52.4%
Therefore, the value of packing efficiency of a simple unit cell is 52.4%. Examples such as lithium and calcium come under this category.
Importance of packing efficiency
The importance of packing efficiency is in the following ways:
1. It represents the solid structure of an object. 2. It shows the different properties of solids like density, consistency, and isotropy. Different attributes of solid structure can be derived with the help of packing efficiency.
The main reason for crystal formation is the attraction between the atoms. As they attract one another, it is frequently in favour of having many neighbours. Therefore, the coordination number or the number of adjacent atoms is important.
For the structure of square lattice, the coordination number is 4 which means that the number of circles touching to any individual atom.
The void spaces between the atoms are the sites interstitial. Though each of it is touched by 4 numbers of circles, the interstitial sites are considered as 4 coordinates. Thus, this geometrical shape is square. In this, there is the same number of sites as circles.
Because the atoms are attracted to one another, there is a scope of squeezing out as much empty space as many as possible. The packing efficiency is the fraction of crystal or known as the unit cell which is actually obtained by the atoms.
It must always be seen less than 100 percent as it is not possible to pack the spheres where atoms are usually spherical which is without having some empty space between it.
P.E = (area of circle) / (area of unit cell) With respect to our square lattice of circles, we can evaluate the packing efficiency that is PE for this particular respective lattice as following: P. E =πr2 / (2r)2 = π/4 = 78.54%.
Thus, the interstitial sites must obtain 100 % - 78.54% which is equal to 21.46%.
Let us now compare it with the hexagonal lattice of a circle. Note that:
The atomic coordination number is 6. Atomic coordination geometry is hexagonal.
The interstitial coordination number is 3 and the interstitial coordination geometry is triangular.
The calculated packing efficiency is 90.69%.
And the evaluated interstitials site is 9.31%.
By examining it thoroughly, you can see that in this packing, twice the number of 3-coordinate interstitial sites as compared to circles. For every circle, there is one pointing towards the left and the other one pointing towards the right.
Therefore, these sites are very much smaller to those in the square lattice.
The higher are the coordination numbers, the more are the bonds and the higher is the value of packing efficiency. This clearly states that this will be more stable lattice than the square one.
If we compare the squares and hexagonal lattices, we clearly see that they both are made up of columns of circles. Thus, in the
hexagonal lattice, every other column is shifted allowing the circles to nestle into the empty spaces. Therefore, it generates higher packing efficiency.
Efficiency is considered as minimum waste. And so, the packing efficiency reduces time, usage of materials and the cost of generating the products.