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The study of geometric figures using coordinate axes is known as coordinate geometry. Straight lines, curves, circles, ellipses, hyperbolas, and polygons can all be conveniently drawn and represented to scale in the coordinate axes. Furthermore, using the coordinate system to work algebraically and examine the characteristics of geometric figures is referred to as coordinate geometry.

In this article, We will go through some of the important concepts of co-ordinate geometry like what is coordinate geometry - definitions, explanations and formulas. Also, we will go through some of the solved coordinate geometry problems for a better understanding of the concept.

Cartesian Coordinates

Distance Formula

Distance Between Two Points

Slope

Midpoint formula

Equation of a line

Slope-Intercept Form of a Line

Point Slope Form

Euclidean Distance Formula

Coordinate geometry is a field of mathematics that aids in the presentation of geometric shapes on a two-dimensional plane and to study their properties. To get a basic understanding of Coordinate Geometry, we will learn about the coordinate plane and the coordinates of a point initially.

A cartesian plane divides plane space into two dimensions, making it easier to locate points. The coordinate plane is another name for it. The horizontal X-axis and the vertical Y-axis are the two axes of the coordinate plane. The origin is the place where these coordinate axes connect, dividing the plane into four quadrants (0, 0). Furthermore, any point in the coordinate plane is represented by a point (x, y), where the x value represents the point's position relative to the X-axis and the y value represents the point's position relative to the Y-axis.

The point represented in the four quadrants of the coordinate plane has the following properties:

The origin ‘O’ is the point of intersection of the X-axis and the Y-axis and has the coordinate points (0, 0) generally.

The X-axis to the right of the origin ‘O’ is the positive X-axis and to the left of the origin, ‘O’ is the -(ve) X-axis. Also, the Y-axis above the origin ‘O’ is the +(ve) Y-axis, and below the origin ‘O’ is the -(ve) Y-axis.

The point present in the first quadrant (x, y) has both +(ve) values and is plotted with reference to the +(ve) X-axis and the +(ve) Y-axis.

The point represented in the second quadrant is (-x, y) is plotted with reference to the -(ve) X-axis and +(ve) Y-axis.

The point represented in the third quadrant (-x, -y) is plotted with reference to the -(ve) X-axis and -(ve) Y-axis.

The point represented in the fourth quadrant (x, -y) is plotted with reference to the +(ve) X-axis and -(ve) Y-axis.

Coordinate geometry formulae make it easier to prove the various properties of lines and figures represented by coordinate axes. The distance formula, slope formula, midpoint formula, section formula, and line equation are included in the list of coordinate geometry formulas. In the below paragraph, we'll learn more about each of the formulas.

The distance between two points $({x}_{1},{y}_{1})$ and $({x}_{2},{y}_{2})$ is equal to the square root of the sum of the squares of the difference between the X-coordinates and the Y-coordinates of the two given points. The formula for the distance between two points is as given below:

D = $\sqrt{({x}_{2}-{x}_{1}{)}^{2}+({y}_{2}-{y}_{1}{)}^{2}}$

The inclination of a line is measured by its slope. The slope can be determined by selecting any two locations on the line and measuring the angle formed by the line with the positive X-axis. m = tanθ is the slope of a line that is inclined at an angle 'θ' with the positive X-axis. The slope of a line joining the two points $({x}_{1},{y}_{1})$ and ${x}_{2},{y}_{2})$ is equal to m = $\frac{({y}_{2}-{y}_{1})}{({x}_{2}-{x}_{1})}$.

m = tanθ

m = $({y}_{2}-{y}_{1})$/$({x}_{2}-{x}_{1})$

The formula for finding the midpoint of the line connecting the points $({x}_{1},{y}_{1})$ and ${x}_{2},{y}_{2})$ is a new point, whose abscissa is the average of the x values of the two given points, and the ordinate is the average of the y values of the two given points. The midpoint is on the line that connects the two points and is right in the middle of them.

$(x,y)=\left({\displaystyle \frac{{x}_{1}+{x}_{2}}{2}},{\displaystyle \frac{{y}_{1}+{y}_{2}}{2}}\right)$

The section formula is useful to find the coordinates of a point that divides the line segment joining the points $({x}_{1},{y}_{1})$ and $({x}_{2},{y}_{2})$ in the ratio $m:n$. The point that divides the provided two points is located on the line that connects them and can be found either between the two points or outside the line segment between them.

$(x,y)=\left(\frac{m{x}_{2}+n{x}_{1}}{m+n},\frac{m{y}_{2}+n{y}_{1}}{m+n}\right)$

The centroid of a triangle is the point of intersection of medians of a triangle. (Median is a line that joins the vertex of a triangle to the mid-point of the opposite side). The centroid of a triangle having its vertices A$({x}_{1},{y}_{1})$, B$({x}_{2},{y}_{2})$, and C$({x}_{3},{y}_{3})$ is obtained from the following formula.

$(x,y)=({\displaystyle \frac{{x}_{1}+{x}_{2}+{x}_{3}}{3}},{\displaystyle \frac{{y}_{1}+{y}_{2}+{y}_{3}}{3}})$

The area of a triangle having the vertices A$({x}_{1},{y}_{1})$, B$({x}_{2},{y}_{2})$, and C$({x}_{3},{y}_{3})$ is obtained from the following formula. This formula is used to find the area of a triangle for all types of triangles.

Area of a Triangle = $\frac{1}{2}}|{x}_{1}({y}_{2}-{y}_{3})+{x}_{2}({y}_{3}-{y}_{1})+{x}_{3}({y}_{1}-{y}_{2})|$

With the use of a simple linear equation, this line equation represents all of the points on the line, ax + by + c= 0 is the standard form of a line equation. There are several methods for determining a line's equation. The slope-intercept form of the equation of a line (y = mx + c) is another essential form of the equation of a line. The slope of the line is m, and the Y-intercept of the line is c. The equation of a line also includes other types of line equations, such as point-slope form, two-point form, intercept form, and normal form.

y = mx + c

Sl.no | Name of the Concept | Formulae |
---|---|---|

1. | Distance formula | $D=\sqrt{({x}_{2}-{x}_{1}{)}^{2}+({y}_{2}-{y}_{1}{)}^{2}}$ |

2. | Slope, m of line ax+by+c=0 | $m=-{\displaystyle \frac{a}{b}}$ |

3. | Angle between two lines is | $\theta ={\mathrm{tan}}^{-1}\left|{\displaystyle \frac{{m}_{2}-{m}_{1}}{1-{m}_{2}{m}_{1}}}\right|$ |

4. | Distance of a point p(x1,y1) from a line ax+by+c=0 | $d=\left|{\displaystyle \frac{a{x}_{1}+b{y}_{1}+c}{\sqrt{{a}^{2}+{b}^{2}}}}\right|$ |

5. | Distance between two parallel lines of a slope m is | $d=\left|{\displaystyle \frac{{c}_{1}-{c}_{2}}{\sqrt{1+{m}^{2}}}}\right|$ |

Question 1. Find the equation of a line passing through (-2, 3) and having a slope of -1.

Solution:

The point on the line is $({x}_{1},{y}_{1})=(-2,3)$, and the slope is $m=-1$.

From the coordinate geometry point and slope form of the equation of the line, we get:

$(y-{y}_{1})=m(x-{x}_{1})\phantom{\rule{0ex}{0ex}}(y-3)=(-1)(x-(-2))\phantom{\rule{0ex}{0ex}}y-3=-(x+2)\phantom{\rule{0ex}{0ex}}y-3=-x-2\phantom{\rule{0ex}{0ex}}x+y=3-2\phantom{\rule{0ex}{0ex}}x+y=1$

Therefore the equation of the line is: x + y = 1

Question 2. Find the equation of a line having a slope of -2 and $y$-intercept of 1.

Solution:

The given information is $m=-2$ and $y$-intercept is $c=1$

From coordinate geometry we can make use of the slope intercept form of the equation of a line.

$y=mx+c\phantom{\rule{0ex}{0ex}}y=(-2)x+1\phantom{\rule{0ex}{0ex}}y=-2x+1\phantom{\rule{0ex}{0ex}}2x+y=1$

Therefore the equation of the line we get is 2x + y = 1.

Question 1. The equations of two equal sides of an isosceles triangle are 7x − y + 3 = 0 and x + y − 3 = 0 and the third side passes through the point (1, 10). Then the equation of the third side is ___________.

Solution:

Any line passing through the point (1, 10) is given by y + 10 = m (x − 1)

Since it makes an equal angle say $\alpha $ with the given lines 7x − y + 3 = 0 and x + y − 3 = 0, therefore tan α = $[$m − 7$]$ / $[$1 + 7m$]$

= $[$m − (−1)$]$ / $[$1 + m (−1)$]$

⇒ m = $[$1/3$]$ or 3

So, the two possible equations of the third side are: 3x + y + 7 = 0 and x − 3y − 31 = 0.

Question 2. The locus of a point P, which divides the line joining (1, 0) and (2cosθ, 2sinθ) internally in the ratio 2:3 for all θ, is a ________.

Solution:

Let us consider the coordinates of the point P, that divides the line joining (1, 0) and (2 cosθ, 2sinθ) in the ratio 2:3 be (h, k). Then,

h = $[$4 cosθ + 3$]$/$[$5$]$ and k = $[$4 sinθ$]$/$[$5$]$

cosθ = $[$5h − 3$]$/$[$4$]$ and sinθ = $[$5k$]$/$[$4$]$

($[$5h − 3$]$/$[$4$]$)2 + ($[$5k$]$/$[$4$]$)2 = 1

(5h − 3)2 + (5k2) = 16

Therefore, locus of (h, k) is (5x − 3)2 + (5y)2 = 16, which is a circle.

Question 3. If the slope of a line passes through the point A (3, 2) is 3/4, then the points on the line which are 5 units away from A, are ___.

Solution:

The equation of line passes through the point (3, 2) and of slope 3/4 is 3x − 4y − 1 = 0

Let the point be (h, k) then,

3h−4k−1 = 0 …………..(i) and

(h − 3)2 + (y − 2)2 = 52 (ii)

On solving the equations above, we get h = −1, 7 and k = −1, 5.

So, the points are (1, 1) and (7, 5).

Question 1. If the coordinates of vertices of a triangle are (0, 5), (1, 4) and (2, 5) then the coordinate of the circumcentre will be.

A. (1, 5)

B. $\left({\displaystyle \frac{3}{2}},\phantom{\rule{mediummathspace}{0ex}}{\displaystyle \frac{9}{2}}\right)$

C. (1, 4)

D. None of these

Question 2. The equation of the image of pair of rays y = |x| by the line x = 1 is

A. |y| = x + 2

B. |y| + 2 = x

C. y = |x – 2|

D. None of these

Answers: 2-A, 3-C

Coordinate Geometry is recognized as one of the most fascinating mathematical concepts. Coordinate Geometry topics uses graphs with curves and lines to describe the relationship between geometry and algebra. Geometric aspects are provided in Algebra, allowing students to solve geometric problems. It is a type of geometry in which the coordinate points on a plane are expressed as an ordered pair of numbers. Here, the concepts of coordinate geometry are explained along with their formulas and solved coordinate geometry examples for better understanding.

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28th June 2022 - general

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28th June 2022 - physics

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July

24th July 2022 - Maths, Physics and Chemistry

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24th July 2022 - Maths, Physics and Chemistry

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24th July 2022 - mathematics

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24th July 2022 - physics

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24th July 2022 - Maths, Physics and Chemistry

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24th July 2022 - mathematics

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24th July 2022 - physics

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24th July 2022 - chemistry

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25th July 2022 - Maths, Physics and Chemistry

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25th July 2022 - Maths, Physics and Chemistry

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25th July 2022 - Maths, Physics and Chemistry

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26th July 2022 - Maths, Physics and Chemistry

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26th July 2022 - Maths, Physics and Chemistry

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26th July 2022 - mathematics

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27th July 2022 - Maths, Physics and Chemistry

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27th July 2022 - Maths, Physics and Chemistry

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28th July 2022 - Maths, Physics and Chemistry

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28th July 2022 - Maths, Physics and Chemistry

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28th July 2022 - mathematics

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28th July 2022 - Maths, Physics and Chemistry

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June, July

mathematics

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mathematics

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mathematics

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mathematics

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mathematics

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chemistry

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In order to prepare for JEE Main 2022, candidates should know the list of important books i.e. RD Sharma Solutions, NCERT Solutions, RS Aggarwal Solutions, HC Verma books and RS Aggarwal Solutions. They will find the high quality readymade solutions of these books on Vedantu. These books will help them in order to prepare well for the JEE Main 2022 exam so that they can grab the top rank in the all India entrance exam.

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JEE Main 2022 free online mock test series for exam preparation are available on the Vedantu website for free download. Practising these mock test papers of Physics, Chemistry and Maths prepared by expert teachers at Vedantu will help you to boost your confidence to face the JEE Main 2022 examination without any worries. The JEE Main test series for Physics, Chemistry and Maths that is based on the latest syllabus of JEE Main and also the Previous Year Question Papers.

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NTA is responsible for the release of the JEE Main 2022 June and July Session cut off score. The qualifying percentile score might remain the same for different categories. According to the latest trends, the expected cut off mark for JEE Main 2022 June and July Session is 50% for general category candidates, 45% for physically challenged candidates, and 40% for candidates from reserved categories. For the general category, JEE Main qualifying marks for 2021 ranged from 87.8992241 for general-category, while for OBC/SC/ST categories, they ranged from 68.0234447 for OBC, 46.8825338 for SC and 34.6728999 for ST category.

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JEE Main 2022 June and July Session Result - NTA has announced JEE Main result on their website. To download the Scorecard for JEE Main 2022 June and July Session, visit the official website of JEE Main NTA.

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Rank List

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JEE Main 2022 state rank lists will be released by the state counselling committees for admissions to the 85% state quota and to all seats in NITs and CFTIs colleges. JEE Main 2022 state rank lists are based on the marks obtained in entrance exams. Candidates can check the JEE Main 2022 state rank list on the official website or on our site.

Want to know which Engineering colleges in India accept the JEE Main 2022 scores for admission to Engineering? Find the list of Engineering colleges accepting JEE Main scores in India, compiled by Vedantu. There are 1622 Colleges that are accepting JEE Main. Also find more details on Fees, Ranking, Admission, and Placement.

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FAQ

**1. What is a Cartesian Plane?**

A cartesian plane in coordinate geometry is made up of two perpendicular lines called the X-axis (horizontal axis) and the Y-axis (vertical axis). The ordered pair can be used to calculate the exact position of a point in the Cartesian plane (x, y).

**2. Where is Coordinate Geometry Used in Maths?**

Coordinate geometry has a wide range of applications in mathematics. Many applications of coordinate geometry may be found in math topics such as vectors, three-dimensional geometry, equations, calculus, complex numbers, and functions. All of these topics require the presentation of data graphically in a two or three-dimensional coordinate plane.

**3. What is the Application of Coordinate Geometry Used in Real Life?**

In real life, coordinate geometry is used in a variety of ways. The coordinate system takes into account all of the maps we use to pinpoint locations, including Google Maps and physical maps. Furthermore, drawing land maps to scale is beneficial in large-scale land projects. To pinpoint any place in the seas, naval engineers employ coordinate systems.

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