
The probability of selecting a rotten apple randomly from a heap of 900 apples is 0.18. What is the number of rotten apples in the leap?
Answer
218.4k+ views
Hint: The probability of any event happening is given by dividing the number of outcomes of that event divided by the total number of events, that is;
$P = \dfrac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}$
Apply this formula, and then use the given conditions to find the required value.
Complete step-by-step solution
Let us carefully read the given question and observe that it says that the total number of apples are 900.
Thus, in this case we get that our total number of outcomes are 900.
Let the number of outcomes of selecting a rotten apple randomly from a leap of 900 apples be $x$.
We use the formula of probability given by, $P = \dfrac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}$ and substitute the obtained values in it.
$P = \dfrac{x}{{900}}$
Now, we use the fact given in the question that the probability of selecting a rotten apple randomly from a heap of 900 apples is 0.18.
Thus, we get,
$
0.18 = \dfrac{x}{{900}} \\
\Rightarrow x = 162 \\
$
Thus, the number of rotten apples in the heap is 162.
Note: In solving these types of questions, you should be familiar with the formula to find the probability of any event happening. Then use the given conditions and values given in the question, and substitute in the formula for probability of the event, to find the missing values.
Avoid any calculation mistakes.
$P = \dfrac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}$
Apply this formula, and then use the given conditions to find the required value.
Complete step-by-step solution
Let us carefully read the given question and observe that it says that the total number of apples are 900.
Thus, in this case we get that our total number of outcomes are 900.
Let the number of outcomes of selecting a rotten apple randomly from a leap of 900 apples be $x$.
We use the formula of probability given by, $P = \dfrac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}$ and substitute the obtained values in it.
$P = \dfrac{x}{{900}}$
Now, we use the fact given in the question that the probability of selecting a rotten apple randomly from a heap of 900 apples is 0.18.
Thus, we get,
$
0.18 = \dfrac{x}{{900}} \\
\Rightarrow x = 162 \\
$
Thus, the number of rotten apples in the heap is 162.
Note: In solving these types of questions, you should be familiar with the formula to find the probability of any event happening. Then use the given conditions and values given in the question, and substitute in the formula for probability of the event, to find the missing values.
Avoid any calculation mistakes.
Recently Updated Pages
The angle of depression of the top and the bottom of class 10 maths JEE_Main

Find the value of sin 50 circ sin 70 circ + sin 10 class 10 maths JEE_Main

The amount of work in a leather factory is increased class 10 maths JEE_Main

The side BC of a triangle ABC is bisected at D O is class 10 maths JEE_Main

The circumference of the base of a 24 m high conical class 10 maths JEE_Main

Mutually Exclusive vs Independent Events: Key Differences Explained

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

JEE Main Syllabus 2026: Download Detailed Subject-wise PDF

JEE Main Previous Year Question Papers (2014–2025) with Answer Keys and Solutions

Exothermic Reactions: Real-Life Examples, Equations, and Uses

Marks vs Percentile JEE Mains 2026: Calculate Percentile Marks

Understanding Newton’s Laws of Motion

Other Pages
NCERT Solutions For Class 10 Maths Chapter 12 Surface Area And Volume

NCERT Solutions for Class 10 Maths Chapter Chapter 13 Statistics

NCERT Solutions for Class 10 Maths Chapter 11 Areas Related to Circles 2025-26

Pregnancy Week and Due Date Calculator: Find How Far Along You Are

Complete List of Class 10 Maths Formulas (Chapterwise)

NCERT Solutions for Class 10 Maths Chapter 15 Probability

