## NCERT Solutions for Class 6 Maths Chapter 11 Algebra (Ex 11.3) Exercise 11.3

Free PDF download of NCERT Solutions for Class 6 Maths Chapter 11 Exercise 11.3 (Ex 11.3) and all chapter exercises at one place prepared by expert teacher as per NCERT (CBSE) books guidelines. Class 6 Maths Chapter 11 Algebra Exercise 11.3 Questions with Solutions to help you to revise complete Syllabus and Score More marks. Register and get all exercise solutions in your emails.

## Access NCERT Solution for Class 6 Maths Chapter 11- Algebra

### Exercise 11.3

1. Make up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication.

Ans: Since there are only three numbers 5, 7 and 8, only two signs from $ + $, $ - $ and $ \times $ can be used at once.

The expressions that can be formed by using $ + $ and $ - $ are as follows.

$5 + \left( {8 - 7} \right)$

$5 + \left( {7 - 8} \right)$

$7 + \left( {8 - 5} \right)$

$7 + \left( {5 - 8} \right)$

$8 + \left( {7 - 5} \right)$

$8 + \left( {5 - 7} \right)$

$5 - \left( {7 + 8} \right)$

$7 - \left( {5 + 8} \right)$

$8 - \left( {5 + 7} \right)$

The expressions that can be formed by using $ + $ and $ \times $ are as follows.

$5 + \left( {8 \times 7} \right)$

$7 + \left( {8 \times 5} \right)$

$8 + \left( {5 \times 7} \right)$

$5 \times \left( {8 + 7} \right)$

$7 \times \left( {8 + 5} \right)$

$8 \times \left( {7 + 5} \right)$

The expressions that can be formed by using $ - $ and $ \times $ are as follows.

$5 - \left( {8 \times 7} \right)$

$7 - \left( {8 \times 5} \right)$

$8 - \left( {7 \times 5} \right)$

$5 \times \left( {8 - 7} \right)$

$5 \times \left( {7 - 8} \right)$

$7 \times \left( {8 - 5} \right)$

$7 \times \left( {5 - 8} \right)$

$8 \times \left( {7 - 5} \right)$

$8 \times \left( {5 - 7} \right)$

2. Which out of the following are expressions with numbers only?

\[\mathbf{y + 3}\]

Ans: The given expression \[y + 3\] contains the variable $y$, which is not a number.

Hence, \[y + 3\] is not an expression with numbers only.

$\mathbf{\left( {7 \times 20} \right) - 8}z$

Ans: The given expression $\left( {7 \times 20} \right) - 8z$ contains the variable $z$, which is not a number.

Hence, $\left( {7 \times 20} \right) - 8z$ is not an expression with numbers only.

$\mathbf{5\left( {21 - 7} \right) + 7 \times 2}$

Ans: The given expression $5\left( {21 - 7} \right) + 7 \times 2$ does not contain variable.

Hence, $5\left( {21 - 7} \right) + 7 \times 2$ is an expression with numbers only.

5

Ans: The given expression 5 does not contain variable.

Hence, it is an expression with numbers only.

$\mathbf{3x}$

Ans: The given expression $3x$ contains a variable $x$, which is not a number.

Hence, $3x$ is not an expression with numbers only.

$\mathbf{5 - 5n}$

Ans: The given expression $5 - 5n$ contains a variable $n$, which is not a number.

Hence, $5 - 5n$ is not an expression with numbers only.

$\mathbf{\left( {7 \times 20} \right) - \left( {5 \times 10} \right) - 45 + p}$

Ans: The given expression $\left( {7 \times 20} \right) - \left( {5 \times 10} \right) - 45 + p$ contains variable $p$, which is not a number.

Hence, $\left( {7 \times 20} \right) - \left( {5 \times 10} \right) - 45 + p$ is not an expression with numbers only.

3. Identify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed.

\[\mathbf{z + 1,{\text{ }}z--1,{\text{ }}y + 17,\,{\text{ }}y--17}\]

Ans: $z + 1$ is an expression where $z$ and 1 are added.

Therefore, the required operation is addition.

$z - 1$ is an expression where 1 is subtracted from $z$.

Therefore, the required operation is subtraction.

$y + 17$ is an expression where 17 is added to $y$.

Therefore, the required operation is addition.

$y - 17$ is an expression where 17 is subtracted from $y$.

Therefore, the required operation is subtraction.

$\mathbf{17y,{\text{ }}\dfrac{y}{{17}},{\text{ }}5z}$

Ans: $17y$ is an expression where $y$ is multiplied by 17.

Therefore, the required operation is multiplication.

$\dfrac{y}{{17}}$ is an expression where $y$ is divided by 17.

Therefore, the required operation is division.

$5z$ is an expression where $z$ and 5 are to be uploaded.

Therefore, the required operation is multiplication.

$\mathbf{2y + 17,{\text{ }}2y - 17}$

Ans: $2y + 17$ is an expression where first $y$ is multiplied by 2. Then 17 is added to the obtained result.

Therefore, the required operation is multiplication and addition.

$2y - 17$ is an expression where the first $y$ is multiplied by 2. Then 17 is subtracted from the obtained result.

Therefore, the required operation is multiplication and subtraction.

\[7m,{\text{ }} - 7m + 3,{\text{ }} - 7m--3\]

Ans: \[7m\]is an expression where $m$ is multiplied by 7.

Therefore, the required operation is multiplication.

\[ - 7m + 3\] is an expression where the first $m$ is multiplied by $ - 7$. Then 3 is added to the obtained result.

Therefore, the required operation is multiplication and addition.

\[ - 7m - 3\] is an expression where the first $m$ is multiplied by $ - 7$. Then 3 is subtracted from the obtained result.

Therefore, the required operation is multiplication and subtraction.

4. Give expressions for the following cases.

7 added to $p$

Ans: In order to add 7 to $p$, use the addition operation as follows.

$ \Rightarrow p + 7$

7 subtracted from $p$

Ans: In order to subtract 7 from $p$, use the subtraction operation as follows.

$ \Rightarrow p - 7$

$p$ multiplied by 7

Ans: In order to multiply $p$ by 7, use the multiplication operation as follows.

$\Rightarrow p \times 7 $

$\Rightarrow 7p $

$p$ divided by 7

Ans: In order to divide$p$ by 7, use division operation as follows.

$ \Rightarrow \dfrac{p}{7}$

7 subtracted from $ - m$

Ans: In order to subtract 7 from $ - m$, use the subtraction operation as follows.

$ \Rightarrow - m - 7$

# -p multiplied by 5

Ans: In order to multiply $ - p$ by 5, use the multiplication operation as follows.

$\Rightarrow - p \times 5$

$\Rightarrow - 5p$

$ - p$ divided by 5

Ans: In order to divide $ - p$ by 5, use division operation as follows.

$ \Rightarrow \dfrac{{ - p}}{5}$

$ \Rightarrow - \dfrac{p}{5}$

p multiplied by $ - 5$

Ans: In order to multiply $p$ by $ - 5$, use the multiplication operation as follows.

$ \Rightarrow p \times \left( { - 5} \right) $

$ \Rightarrow - p \times 5 $

$\Rightarrow - 5p $

5. Give expressions in the following cases.

11 added to $2m$

Ans: In order to add 11 to $2m$, use addition operation as follows.

$ \Rightarrow 2m + 11$

11 subtracted from $2m$

Ans: In order to subtract 11 from $2m$, use the subtraction operation as follows.

$ \Rightarrow 2m - 11$

5 times $y$ to which 3 is added

Ans: In order to multiply $y$ by 5, use the multiplication operation as follows.

$\Rightarrow y \times 5 $

$\Rightarrow 5y $

In order to add 3 to $5y$, use the addition operation as follows.

$ \Rightarrow 5y + 3$

5 times $y$ from which 3 is subtracted

Ans: In order to multiply $y$ by 5, use the multiplication operation as follows.

$\Rightarrow y \times 5 $

$\Rightarrow 5y $

In order to subtract 3 from$5y$, use the subtraction operation as follows.

$ \Rightarrow 5y - 3$

$y$ is multiplied by $ - 8$

Ans: In order to multiply $y$ by $ - 8$, use the multiplication operation as follows.

$\Rightarrow y \times \left( { - 8} \right) $

$\Rightarrow - y \times 8 $

$\Rightarrow - 8y $

$y$ is multiplied by $ - 8$ and then 5 is added to the result

Ans: In order to multiply $y$ by $ - 8$, use the multiplication operation as follows.

$\Rightarrow y \times \left( { - 8} \right) $

$\Rightarrow - y \times 8 $

$ \Rightarrow - 8y $

In order to add 5 to $ - 8y$, use the addition operation as follows.

$ \Rightarrow - 8y + 5$

$y$ is multiplied by 5 and the result is subtracted from 16

Ans: In order to multiply $y$ by 5, use the multiplication operation as follows.

$\Rightarrow y \times 5 $

$\Rightarrow 5y $

In order to subtract$5y$ from16, use the subtraction operation as follows.

$ \Rightarrow 16 - 5y$

$y$ is multiplied by $ - 5$ and the result is added to 16.

Ans: In order to multiply $y$ by $ - 5$, use the multiplication operation as follows.

$\Rightarrow y \times \left( { - 5} \right) $

$\Rightarrow - y \times 5 $

$ \Rightarrow - 5y $

In order to add $ - 5y$ to 16, use the addition operation as follows.

$ \Rightarrow - 5y + 16$

6.

Form expressions using $t$ and 4. Use not more than one number operation. Every expression must have $t$ in it.

Ans: The expressions that can be formed by using $ + $ are as follows.

$t + 4$

$4 + t$

The expressions that can be formed by using $ - $ are as follows.

$t - 4$

$4 - t$

The expression that can be formed by using $ \times $ is as follows.

$\Rightarrow t \times 4 $

$\Rightarrow 4t $

The expressions that can be formed by using $/$ are as follows.

$\dfrac{t}{4}$

$\dfrac{4}{t}$

Form expressions using $y$, 2 and 7. Every expression must have $y$ in it. Use only two number operations. These should be different.

Ans: The expression that can be formed by using $ + $ and only two numbers are as follows.

$2y + 7$

$7y + 2$

The expressions that can be formed by using $ - $ and only two numbers are as follows.

$2y - 7$

$7y - 2$

### NCERT Solutions for Class 6 Maths Chapter 11 Algebra Exercise 11.3

Opting for the NCERT solutions for Ex 11.3 Class 6 Maths is considered as the best option for the CBSE students when it comes to exam preparation. This chapter consists of many exercises. Out of which we have provided the Exercise 11.3 Class 6 Maths NCERT solutions on this page in PDF format. You can download this solution as per your convenience or you can study it directly from our website/ app online.

Vedantu in-house subject matter experts have solved the problems/ questions from the exercise with the utmost care and by following all the guidelines by CBSE. Class 6 students who are thorough with all the concepts from the Subject Maths textbook and quite well-versed with all the problems from the exercises given in it, then any student can easily score the highest possible marks in the final exam. With the help of this Class 6 Maths Chapter 11 Exercise 11.3 solutions, students can easily understand the pattern of questions that can be asked in the exam from this chapter and also learn the marks weightage of the chapter. So that they can prepare themselves accordingly for the final exam.

Besides these NCERT solutions for Class 6 Maths Chapter 11 Exercise 11.3, there are plenty of exercises in this chapter which contain innumerable questions as well. All these questions are solved/answered by our in-house subject experts as mentioned earlier. Hence all of these are bound to be of superior quality and anyone can refer to these during the time of exam preparation. In order to score the best possible marks in the class, it is really important to understand all the concepts of the textbooks and solve the problems from the exercises given next to it.

Do not delay any more. Download the NCERT solutions for Class 6 Maths Chapter 11 Exercise 11.3 from Vedantu website now for better exam preparation. If you have the Vedantu app in your phone, you can download the same through the app as well. The best part of these solutions is these can be accessed both online and offline as well.