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Normality Formula

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Last updated date: 23rd Apr 2024
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Normality Formula - Normality Definition and Formula

Normality like Molarity is a way of expressing the concentration of solute in a solution. If you can recollect, Molarity was defined as the number of Moles (n) of solute present in 1lt. of the solution. Now to define ‘Normality’ or ‘equivalent concentration’, instead of using the number of Moles (n), we will use the number of equivalents (eq) of solutes.


So, Normality (N) = \[\frac{\text{Number of equivalents}}{\text{Volume in litres}}\] 

Now, calculating the number of equivalents is similar to calculating number of Moles

Number Of Moles(n)= \[\frac{\text{Given mass}}{\text{molar mass}}\]

Number Of Equivalents(Eq)= \[\frac{\text{Given mass}}{\text{equivalent Mass}}\]

The next problem is how do we find the Equivalent Mass or Equivalent Weight (E.W) or gram equivalent.

Equivalent Weight is defined as Molar Mass divided by equivalence factor (f).

\[E.W = \frac{\text{Molar Mass}}{\text{Valency Factor(f)}}\]

This equivalence factor will differ for different species and also the type of reaction under consideration.

But let us understand this with a very easy example:

Case I:

The equivalent weight of NaCl (ionic salt)

The valency factor (f) of an ionic salt is always equal to the total charge on anion ( in this case) or cation ( in this case)

So if you can observe, the valency factor (f) for NaCl =1.

Hence its Equivalent Weight = \[E.W = \frac{\ext{Molar Mass}}{\text{Valency Factor(f)}}\]

\[\frac{56.5}{1}=56.5\]

Similarly, for MgCl2, valency factor (f) = 2

And \[E.W=\frac{95}{2}=47.5\]

Case II:

For acids or bases, the valency factor (f) is equal to the number of Moles of

H+orOH-

ions 1 Mole of acid or base can furnish in an aqueous medium.

e.g. 1 Mole of H2SO4 will furnish 2 Moles of ions, so its (f) = 2, E.W = 98/2 = 49 gm/eq

1 Mole of NaOH will furnish 1 Mole of ions, so its (f) = 1, E.W = 40/1 = 40 gm/eq

1 Mole of H3PO3 will produce only 2 Moles of ions (check the structure of acid), so its (f) = 2,

E.W = 82/2 = 41 

So, what we can gather from here is that we need to know the acidity of the base and the basicity of acid to determine the valency factor (f)

Case III:

For Redox Reaction, the (f) factor for any species is the total change in the oxidation state it has undergone in that reaction.

e.g. KMnO4 as an oxidising agent in acidic media

MnO4−+8H++5e→Mn2++4H2O

KMnO4 gained 5 electrons from the reductant. 

Therefore (f) = 5

Hence E.W = 158.04/5 = 31.61 grams/equivalent.

I know there is a lot to remember in this and it looks more tricky than calculating Molarity, but with a few examples and little practice, you will get a hang of it!

Example: What is the Normality of the following of 1lt. an aqueous solution containing 80 gm of NaOH dissolved in it.

Solution: 

Firstly, In order to determine the Normality (N), we need to find the number of equivalents.

Now we know that the (f) for NaOH = 1

E.W = 40/1 = 40gm

Number of Equivalents(Eq)= \[\frac{\text{Given mass}}{\text{equivalent Mass}}\]

 = 80/40 = 2 Eq

Hence, N =

\[(N)=\frac{\text{Number of equivalents}}{\text{Volume in litres}}\] = 2/1 = 2 Eq/lt.

1. What is the Normality of 0.1381 M NaOH?

Options:

(a) 0.5231 N

(b) 0.6123 N

(c) 0.7775 N

(d) 0.1381

Ans: (d)

Solution: 

0.1381 mol/L x (1 eq/1mol) = 0.1381 eq/L = 0.1381 N 

Since the Equivalent Weight of NaOH is equal to Molar Mass hence the Molarity is equal to Normality in this case.


More About Normality Formula

Normality Formula along with its definition is available for a free download at Vedantu.

The amount of a substance in a specific Volume of solution is called Molarity and it is represented by M. The Moles of the solute in solutions per liter are called Molarity, which is also sometimes referred to as the molar concentration of a solution, that is to say, it is a way of expressing the concentration of a solute in a solution.


Now coming to the Normality, it is also, just like the Molarity, a method for expressing the concentration of solute in a solution. And as we have just seen that Molarity is defined by the number of Moles present in the one-liter solute, the Normality is defined by the number of equivalents of solutes. Normality can also be referred to as an Equivalent concentration.


Usage of Normality Formula or the Equivalent Concentration

There are many usages of the Normality formula or the equivalent concentration, some of which are mentioned below.

  • The Normality formula is used to express the hydronium ions concentration, or hydroxide ions concentration in a solution, in acid-base chemistry.

  • The Normality formula describes the capacity of accepting or donating the number of electrons that an oxidizing or the reducing agent can manage, in a redox reaction.

  • In the precipitation reactions, which is to say, the process of morphing the substance which is dissolved into an insoluble solid from the solution which is supersaturated. In such reactions, Normality is used to describe the number of electrons that can be accepted or donated by the reducing or an oxidizing agent.

FAQs on Normality Formula

1. Is understanding the Normality formula difficult?

Understanding the Normality formula is not at all difficult, but for that, you have to study with a good focus, otherwise it may become difficult for you. Also, the syllabus is prepared by considering all the things of the students and hence the difficulty level of the Normality Formula is not that much that it becomes difficult for the students to comprehend. And therefore, as long as you have studied the topic thoroughly you are not going to face that many problems in dealing with the topic.

2. How can I master the topic of the Normality Formula?

For mastering the topic of Normality formula, you need to have a good level of practice. But practicing is not possible without a good knowledge of the topic at hand, which is the Normality Formula. Therefore, it is a must for you to first understand the topic in as better a manner as possible, if you find something difficult read that part, again and again, analyze the given example and after doing all that solve the questions of the Normality formula.

3. Is it okay if I skip the topic of the Normality Formula?

No, it is not at all okay if you skip the topic of the Normality formula, not for one but quite many reasons. First of all, all the topics are included in the syllabus for a reason, and hence the Normality formula is there for a reason. Secondly, the Normality formula is an important part of the chemistry subject as a whole. And also, one more thing to remember is that the Normality formula has many uses and if you have skipped the topic right now, then those topics are going to be difficult for you to understand.

4. Where can I find the definition of Normality along with its formula?

For understanding the topic of the Normality formula it is very much important for the students to have a good definition of the topic, otherwise it becomes very difficult for the students to understand it. And hence Vedantu provides the Definition of Normality along with its formula and makes the topic easy for all the students to understand. Also, the definition that Vedantu provides for Normality along with its formula is very easy to understand and also it is completely free for all the students.

5. Why should I use the Normality formula and its Definition, provided by the Vedantu?

The Normality formula is very much important for the students of the chemistry, and if not understood properly it becomes rather a complex one, and hence the definition of it is supposed to be in such a manner that it becomes very easy to understand, and also the definition itself is supposed to be easy for the students as well as a rather short one. And Vedantu provides exactly this type of definition and makes it easy for the students to understand the Normality formula.