Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# Important Questions for CBSE Class 6 Maths Chapter 10 - Mensuration

Last updated date: 10th Sep 2024
Total views: 668.4k
Views today: 11.68k

## CBSE Class 6 Maths Important Questions Chapter 10 - Mensuration - Free PDF Download

In Mathematics, mensuration deals with measurements of various shapes and patterns along with their dimensions, volume, area, perimeter, etc. Being in class 6, it is essential for every scholar to be well aware of each of the chapters to score high marks in exams. So, try and devote as much time in practising mensuration related problems.

As a helping guide, you can refer to important questions for class 6 maths chapter 10 solutions and get familiar with the techniques to solve the problems faster.

Vedantu is a platform that provides free CBSE Solutions (NCERT) and other study materials for students.You can also register Online for NCERT Class 6 Science tuition on Vedantu.com to score more marks in CBSE board examination.

Also, check CBSE Class 6 Maths Important Questions for other chapters:

 CBSE Class 6 Maths Important Questions Sl.No Chapter No Chapter Name 1 Chapter 1 Knowing Our Numbers 2 Chapter 2 Whole Numbers 3 Chapter 3 Playing with Numbers 4 Chapter 4 Basic Geometrical Ideas 5 Chapter 5 Understanding Elementary Shapes 6 Chapter 6 Integers 7 Chapter 7 Fractions 8 Chapter 8 Decimals 9 Chapter 9 Data Handling 10 Chapter 10 Mensuration 11 Chapter 11 Algebra 12 Chapter 12 Ratio and Proportion 13 Chapter 13 Symmetry 14 Chapter 14 Practical Geometry

### Very Short Answer Questions. 1 Mark

Q1. Length of boundary of a plane figure is called_____

Ans:

Perimeter

Q2. Perimeter of rectangle $=$ ____?

Ans:

We know that Perimeter of rectangle $=2(l+b),$

Here,

\begin{align} & l=\text{length} \\ & b=\text{breadth} \\ \end{align}

Q3. Perimeter of square = ___?

Ans:

We know that perimeter is the length of the boundaries of a figure.

Square has four sides.

Therefore, Perimeter of square $=4\times \text{side}$

Q4. The ratio of circumference of a circle and it’s ______ is always constant.

Ans:

The ratio of circumference of a circle and it’s diameter is always constant.

We know that, circumference of a circle $=2\pi r$

Diameter of a circle $=d=2r$

Ratio will be \begin{align} & \frac{2\pi r}{2r} \\ & =2 \\ \end{align}

Hence, the ratio is constant.

Q5. Circumference of a circle, $C=$ ________?

Ans:

We know that circumference is the total length of the boundary of a figure.

So, $C=2\pi r$

Q6. Value of $\pi$:

(a) In fractions is ________

(b) In decimals is ________

Ans:

(a) Value of $\pi$ in fraction is $\frac{22}{7}.$

(b) Value of $\pi$ in decimals is $3.14$

Q7. Area of rectangle $=(a)\_\_\_\_\_\_\_\times (b)\_\_\_\_\_\_\text{square}\text{units}.$

Ans:

We know that area of rectangle $=\text{length}\times \text{breadth}$

Therefore,

(a) Length

Q8. Area of square $=(a)\_\_\_\_\_\_\_\times (b)\_\_\_\_\_\_\text{square}\text{units}.$

Ans:

We know that area of a square is $=\text{side}\times \text{side}$

Therefore,

(a) Side

(b) Side

### Short Answer Questions.                                         2 Marks

Q1. Length and breadth of a rectangle are $12.3\text{cm}$ and $9.6\text{cm}$respectively. Find its perimeter.

Ans:

Given: Length $=12.3\text{cm}$

Breadth $=9.6\,\,\text{cm}$

We know perimeter $=2(l+b)$

\begin{align} & =2(12.3+9.6) \\ & =31.5\text{cm} \\ \end{align}

Q2. Find the cost of fencing a square field of $175\text{m}$ at Rs.$60\text{ per metre}.$

Ans:

Given: Perimeter of square field $=175\text{m}$

We need to find the cost of fencing the field.

Perimeter $=175\,\,\text{m}$

Cost of fencing per metre $=\text{Rs}\text{.}60$

So, total cost of fencing will be

\begin{align} & =175\times 60 \\ & =\text{Rs}\text{. 10,500} \\ \end{align}

Q3. Find the perimeter of a square whose has sides measuring $6.4\text{cm}$

Ans:

Given: Side of square $=6.4\text{cm}$

We need to find the perimeter of the square.

We know that the perimeter of the square $=4\times \text{side}$
So, Perimeter of square will be

\begin{align} & \text{P}=4\times 6.4 \\ & =25.6\text{cm} \\ \end{align}

Q4. Find circumference of a circle of radius $13\text{cm}.$

Ans:

Given: Radius $=13\text{cm}$

We need to find the circumference of the circle.

We know, Circumference $=2\pi r$

\begin{align} & =2\times \frac{22}{7}\times 13 \\ & =81.714\text{cm} \\ \end{align}

Q5. Find the diameter of a circle whose circumference is $88\text{cm}.$

Ans:

Given: Circumference of a circle $=88\text{cm}$

We need to find the diameter of the circle.

We know that circumference $=\pi d$

\begin{align} & \Rightarrow d=\frac{C}{\pi } \\ & =\frac{88}{\pi } \\ & =\frac{88}{22}\times 7 \\ & =4\times 7 \\ & =28\text{cm} \\ \end{align}

### Short Answer Questions. 3 Marks

Q1. The length and breadth of a rectangle field are $340\text{m}$ and $160\text{m}\text{.}$ A watchman walked $5$ rounds around the field. Find the distance covered by him.

Ans:

Given: length of rectangular field, $l=340\text{m}$

Breadth of rectangular field, $b=160\text{cm}$

We need to find the distance covered by the watchman.

We know that Perimeter, $\text{P}=2(l+b)$

\begin{align} & =2(340+160) \\ & =2(500) \\ & =1000\text{cm} \\ \end{align}

This is the length of one round but watchman walked 5 rounds.

So, distance covered by watchman will be

\begin{align} & =5\times 1000 \\ & =5000\text{cm} \\ \end{align}

Q2. The length and breadth of a rectangular box is in the ratio $4:5.$ If its perimeter $4\text{m }40\text{cm}.$ Find its dimensions.

Ans:

Given: $\frac{l}{b}=\frac{4}{5}$

Perimeter $=4\,\text{m }40\,\text{cm}$

We need to find the length and breadth of the rectangular box.

Let length of the box $=4x$

Breadth of the box $=5x$

So, we know that

\begin{align} & \text{P}=2(l+b)=4\text{m }40\text{cm} \\ & =2(4x+5x)=4\text{m }40\text{cm} \\ & =2(9x)=4.4\text{m} \\ & =18x=4.4\text{m} \\ & \Rightarrow x=\frac{4.4}{18} \\ & =0.244\text{m} \\ \end{align}

Therefore, the dimensions of the rectangular box will be

\begin{align} & l=4x \\ & =4\times 0.244 \\ & =0.976\text{ cm} \\ & =97.6\text{ m} \\ & b=5x \\ & =5\times 0.244 \\ & =1.22\text{ cm} \\ & =122\text{ m} \\ \end{align}

Q3. How many square tiles each of side $0.25\,\text{m}$ will be required to pane the floor of a room which is $4\,\text{m}$broad and $3\,\text{m}$ long?

Ans:

Given: Length of room, $l=4\,\text{m}$

Breadth of the room, $b=3\,\text{m}$

Area of the room will be

\begin{align} & =4\times 3\,\text{square meters} \\ & =12\,\text{square meters} \\ \end{align}

Side of square tile =0.25 m

\begin{align} & =\frac{1}{4}\,\text{m} \\ \end{align}

Area of each square tile will be

\begin{align} & =\left( \frac{1}{4}\times \frac{1}{4} \right)\,\text{sq}\text{. meters} \\ & =\frac{1}{16}\,\text{sq}\text{. meters} \\ \end{align}

Therefore, number of tiles needed to pane the floor of the room will be

\begin{align} & =12\div \frac{1}{16} \\ & =12\times 16 \\ & =192\,\,\text{tiles} \\ \end{align}

Q4. Calculate area( all units are in m)

Given:

We need to find the area of the figure.

We know that area of rectangle $=l\times b$

So, area of rectangle, $1={{A}_{1}}=l\times b$

\begin{align} & =3\times 1 \\ & =3\text{ sq}\text{. meters} \\ \end{align}

Area of rectangle, $2={{A}_{2}}=l\times b$

\begin{align} & =6\times 1 \\ & =6\text{ sq}\text{. meters} \\ \end{align}

Area of rectangle, $3={{A}_{3}}=l\times b$

\begin{align} & =3\times 1 \\ & =3\text{ sq}\text{. meters} \\ \end{align}

Therefore, area of the figure will be

\begin{align} & A={{A}_{1}}+{{A}_{2}}+{{A}_{3}} \\ & =3+6+3 \\ & =12\text{ sq}\text{. meters} \\ \end{align}

### Long Answer Questions. 4 Marks

Q1. Find the perimeter of a regular heptagon having each side equal to $5.5\text{ cm}$

Ans:

Given: A regular heptagon with side $5.5\text{ cm}$

We need to find the perimeter of the heptagon.

We know that perimeter is the length of outer sides of a figure.

Regular heptagon means a figure of $7$ sides and all sides are equal.

Therefore, the perimeter of the heptagon will be

\begin{align} & =7\times \text{side} \\ & =7\times 5.5 \\ & =38.5\text{ cm} \\ \end{align}

Q2. Find the perimeter of the below figure and the figure is symmetrical about its horizontal axis.

Ans:

Given: the figure which is symmetrical about its horizontal axis.

We need to find the perimeter of the given figure.

We know that the perimeter is the total length of all sides of the given figure.

Therefore, perimeter of the given figure will be

\begin{align} & =8+16+4+12+12+4+16 \\ & =8+20+21+20 \\ & =70\text{ cm} \\ \end{align}

Q3. Find the area of the following figure with each square of area $1\text{ c}{{\text{m}}^{\text{2}}}$.

Ans:

Given: The figure having each square of area $1\text{ c}{{\text{m}}^{\text{2}}}$

We need to find the area of the figure.

Total number of squares the figure have $=16$

Area of one square $=1\text{ c}{{\text{m}}^{\text{2}}}$

Therefore, the area of the figure will be

\begin{align} & =16\times 1\text{ c}{{\text{m}}^{\text{2}}} \\ & =16\text{ c}{{\text{m}}^{\text{2}}} \\ \end{align}

Q4. Find area of rectangle whose length and breadth are $35\text{ cm}$ and $15\text{ cm}$. Find the perimeter of the rectangle.

Ans:

Given: length of rectangle, $l=35\text{ cm}$

Breadth of rectangle, $b=15\text{ cm}$

We need to find the area and perimeter of the rectangle.

We know that area of rectangle $=l\times b$

Therefore, area will be

\begin{align} & =35\times 15 \\ & =525\text{ c}{{\text{m}}^{2}} \\ \end{align}

Also, we know that perimeter of a rectangle $=2(l+b)$

Therefore, perimeter will be

\begin{align} & =2(35+15) \\ & =2\times 50 \\ & =100\text{ cm} \\ \end{align}

### Long Answer Questions.                                              5 Marks

Q1. The cost of cultivating a square field is $\text{Rs}.130\text{ per meter}$ is $\text{Rs}\text{. }8,450$ . Find the length of each side of the field.

Ans:

Given: Cost of cultivating a square field $=\text{Rs}.130\text{ per meter}$

Total cost of cultivating the square field $=\text{Rs}\text{. }8,450$

We need to find the length of the side of square field.

Area of square field $=\frac{\text{Total cost of cultivating}}{\text{Per meter cost of cultivating}}$

Therefore, area will be

\begin{align} & =\frac{8450}{130} \\ & =65\text{ }{{\text{m}}^{2}} \\ \end{align}

Now, we know that area of a square $=\text{side}\times \text{side}$

Therefore, the length of the each side of square field will be

\begin{align} & 65=\text{side}\times \text{side} \\ & {{\text{s}}^{\text{2}}}=65 \\ & \text{s}=\sqrt{65} \\ & \text{s}=8.06\text{ cm} \\ \end{align}

Class 6 maths chapter 10 important questions set can be downloaded in PDF format entirely free of cost. However, you can even study the same from Vedantu's website. All the problems are worked out as per the latest CBSE rules and written in a step by step manner, making it feasible for everyone to understand.

## Mensuration Questions for Class 6 Overview

### Important Questions for Class 6 Maths Chapter 10: Questions Carrying 1 Mark

In the first section of class 6 mensuration questions PDF, you will see eight fill in the blank questions of 1 mark each. It is one of the easiest portions, and you must be thorough with the formulas and concepts to precisely answer these questions.

### Important Questions for Class 6 Maths Chapter 10: Questions Carrying 2 Marks

This segment in the PDF of important questions for class 6 maths mensuration contains 5 questions of 2 marks each. Here, you are supposed to solve the problems and find out the perimeter, area, cost of fencing a field, etc. of different shapes like square, rectangle and circle. Hence, knowing the right formula is immensely important to get correct answers.

You can refer to the solutions provided in this PDF and recapitulate knowledge of the mensuration chapter.

### Important Questions for Class 6 Maths Chapter 10: Questions Carrying 3 Marks

Here, in questions on mensuration for class 6 PDF, the questions are complicated than the previous ones. For instance, a rectangular field's length and width are provided, and it is said that a watchman has walked 5 rounds. You are asked to find out the total distance he covered.

Similar type of questions are there in the important question material, and you must go through each sum to be thorough with the solution procedures.

### Important Questions for Class 6 Maths Chapter 10: Questions Carrying 4 Marks

This section in CBSE class 6 maths mensuration questions consist of four questions, out of which three of them are diagram based. Figures with some of the dimensions are given, and you are required to find out the perimeter, area, etc. of the same.

### Important Questions for Class 6 Maths Chapter 10: Questions Carrying 5 Marks

The final section contains only three questions. First one is related to finding the length of one side of a field, the second one is about evaluating the perimeter of a given rectangle, and the last one requires you to calculate the breadth of a room.

All the necessary dimensions are provided; all you need to do is take the right approach and put the right formula to solve the sums.

So, make sure to download Vedantu's important questions for class 6 maths chapter 10 and revise the techniques to solve problems more quickly.

## What are the Benefits of Important Questions from Vedantu for Class 6 Maths Chapter 10 - Mensuration

Explore the advantages of Vedantu's Important Questions for Class 6 Maths Chapter 10 - "Mensuration." Tailored to the chapter's essence, these benefits include focusing on key topics for efficient study, alleviating exam anxiety, reinforcing fundamental concepts, imparting effective time management skills, enabling self-assessment and progress tracking, fostering a strategic approach for higher scores, covering a broad range of topics for comprehensive understanding, and providing crucial support for exam preparation, instilling confidence in class 7 students with simplicity and clarity.

## Conclusion

Delve into the key questions of Class 6 Maths Chapter 10 - "Mensuration" for a comprehensive understanding. The additional and crucial questions engage in focused discussions, covering all themes of the chapter. This method, centred on questions and answers, proves efficient for exam preparation, saving time, aiding in chapter revision, and enhancing comprehension. Regular practice of these essential questions simplifies preparation and instils confidence for upcoming exams.

## FAQs on Important Questions for CBSE Class 6 Maths Chapter 10 - Mensuration

1. What is the syllabus of class 10 CBSE maths?

Class 10 CBSE maths syllabus comprises of fourteen chapters in total. The unit names are Whole numbers, Basic Geometrical Ideas, Knowing Our Numbers, Understanding Elementary Shapes, Playing with Numbers, Integers, Fractions, Decimals, Algebra, Data Handling, Symmetry, Ratio and Proportion, Mensuration and Practical Geometry.

2. What are the uses of mensuration in day to day life?

Mensuration has a vast number of uses in real life. For instance, measurement of land, sites, floors for real estate purposes, evaluation of item quantities like milk, solid items, other edible or non-edible items, etc. Furthermore, mensuration is also necessary for estimating the cost of fencing, painting, covering a floor with carpet, etc.

Apart from these, mensuration is essential for constructing overhead tanks and knowing the water level and quantity in lakes or rivers.

3. What are the kinds of 2-D and 3-D geometrical shapes used in mathematics?

2-D objects or shapes consist of only two dimensions: length and breadth, whereas 3-D objects have three dimensions – length, breadth and thickness. However, 2-D objects are not available in the real world and can be only depicted on paper or plane surfaces. Some of the widely used 2-D shapes are circle, square, triangle, rectangle, hexagon and pentagon.

On the other hand, 3-D objects have volume and total surface area, and some of its examples are the pyramid, cone, triangle prism, cuboid, cube, cylinder, etc.

4. How many exercises are there in Chapter 10 ‘Mensuration’ of Class 6 Maths?

Ans: There are three exercises in Chapter 10 ‘Mensuration’ of Class 6 Maths. These exercises are listed as Exercise 10.1, Exercise 10.2 and Exercise 10.3. You can check out Vedantu’s official website (vedantu.com) if you want the answers to textbook questions. Additionally, this website will provide you with a lot of study material including important questions and answers, notes of the chapter, mock test papers, etc absolutely free of cost. It explains every single concept of the chapter in detail.

5. What steps do I need to follow to get important questions of Chapter 10 of Class 6 Maths?

Ans: To get important questions of Chapter 10 ‘Mensuration’ of Class 6 Maths, you need to go through the mentioned steps.

1. Check out Vendantus's website

2. This link will land you on the important questions webpage of Vedantu where you will find all the study stuff related to Chapter 10 ‘Mensuration’ of Class 6 Mathematics book.

6. What should I do to prepare well for the Chapter 10 of Class 6 Maths exam?

Ans: If you want to prepare well for the Chapter 10 ‘Mensuration’ of Class Maths exam then you must attend your school lectures regularly. You must not lose focus when your Maths teacher is teaching the chapter or solving the textbook questions. You are required to revise this chapter at your home. While understanding the chapter, you can make a separate notebook for formula and solving textbook exercises questions. These notebooks will help you to revise the chapter at a faster pace during your exam and you’ll be able to recall things easily.

7. What is Mensuration according to Chapter 10 of Class 6 Maths?

Ans: Mensuration is a branch of Mathematics that is related to the study of geometric figures. It involves the calculation of important parameters of the figures including length, volume, area, surface area, lateral surface area, etc. This branch of maths deals with the methods of calculation, important equations and properties of different geometric figures and shapes along with their applications. Mensuration helps to identify the size, density and region of both two-dimensional and three-dimensional figures.

8. Explain some important terms of Mensuration as mentioned in Chapter 10 of Class 6 Maths.

Ans: The important terms of Mensuration are as follows.

1. Area- It is defined as the surface occupied by any object. It is represented with the letter A. It has an SI unit in squares. For example, meter square, centimetre square, etc.

2. Perimeter- It is defined as the boundary’s total length. It is expressed with the letter P and is represented with a square unit.

3. Volume- It is the space occupied by a three-dimensional object. This property is only found in 3-D shapes or objects that include an additional parameter of height. It is denoted with the symbol V and is represented with cube units. For example- metre cube, centimetre cube, etc.