By selling 45 lemons, a vendor loses a sum equal to the selling price of 3 lemons. Find his loss percent.
Answer
327k+ views
Hint: In this question the percentage of loss can be calculated as \[{\text{Loss% = 100}} \times \dfrac{{{\text{Loss}}}}{{{\text{CP}}}}\]. The vendor gets loss when the cost price is greater than selling price. So, use this concept to reach the solution to the question.
Complete step-by-step answer:
Let selling price of 1 lemon = x
So, selling price (SP) of 45 lemons = 45 x
Given loss = selling price of 3 lemons = 3 x
We know that cost price (CP) = selling price (SP) + loss
= 45 x + 3 x
= 48 x
Consider, \[{\text{Loss% = 100}} \times \dfrac{{{\text{Loss}}}}{{{\text{CP}}}}\]
\[
{\text{Loss% = 100}} \times \dfrac{{3x}}{{48x}} \\
{\text{Loss% = 100}} \times \dfrac{1}{{16}} \\
\therefore {\text{Loss% = 100}} \times 0.625 = 6.25\% \\
\]
Thus, loss percent is 6.25%.
Note: Always remember that cost price (CP) is the amount we pay to buy an item at which it is available. Similarly selling price (SP) is the rate at which an article is sold. There is a profit when the selling price is more than the cost price and there is loss when the cost price is more than the selling price.
Complete step-by-step answer:
Let selling price of 1 lemon = x
So, selling price (SP) of 45 lemons = 45 x
Given loss = selling price of 3 lemons = 3 x
We know that cost price (CP) = selling price (SP) + loss
= 45 x + 3 x
= 48 x
Consider, \[{\text{Loss% = 100}} \times \dfrac{{{\text{Loss}}}}{{{\text{CP}}}}\]
\[
{\text{Loss% = 100}} \times \dfrac{{3x}}{{48x}} \\
{\text{Loss% = 100}} \times \dfrac{1}{{16}} \\
\therefore {\text{Loss% = 100}} \times 0.625 = 6.25\% \\
\]
Thus, loss percent is 6.25%.
Note: Always remember that cost price (CP) is the amount we pay to buy an item at which it is available. Similarly selling price (SP) is the rate at which an article is sold. There is a profit when the selling price is more than the cost price and there is loss when the cost price is more than the selling price.
Last updated date: 28th May 2023
•
Total views: 327k
•
Views today: 2.84k
Recently Updated Pages
Calculate the entropy change involved in the conversion class 11 chemistry JEE_Main

The law formulated by Dr Nernst is A First law of thermodynamics class 11 chemistry JEE_Main

For the reaction at rm0rm0rmC and normal pressure A class 11 chemistry JEE_Main

An engine operating between rm15rm0rm0rmCand rm2rm5rm0rmC class 11 chemistry JEE_Main

For the reaction rm2Clg to rmCrmlrm2rmg the signs of class 11 chemistry JEE_Main

The enthalpy change for the transition of liquid water class 11 chemistry JEE_Main
