
An airline Concorde flies ${\rm{2000}}\,{\rm{km}}$ at a speed of ${\rm{1600}}\,{\rm{km/h}}$ and then returns due to bad weather at a speed of ${\rm{1000}}\,{\rm{km/h}}$. Find the average speed for the whole trip.
Answer
586.2k+ views
Hint: In this solution, first, we have to find both the travel time of the up and down trip of the flight using the given distance dividing with the speed. For that we need to use the formula ${\rm{Time}} = \dfrac{{{\rm{distance}}}}{{{\rm{speed}}}}$. Once we get their time, we can calculate the total time. After calculating the total distance, we can find the average speed of the flight by dividing the total distance with total time.
Complete answer:
Here,
First we compute for the time in speed $1$,
Step I,
We know that,
${\rm{Time}}\left( {\rm{1}} \right){\rm{ = }}\dfrac{{{\rm{distance}}}}{{{\rm{speed}}}}$
$ = \dfrac{{{\rm{2000}}\,{\rm{km}}}}{{{\rm{1600}}\,{\rm{km/hr}}}}$
$ = {\rm{1}}{\rm{.25}}\,{\rm{hrs}}$
Again,
Since, the airline just returned.
Therefore,
We compute for the time in speed $2$,
We know that,
${\rm{Time}}\left( 2 \right){\rm{ = }}\dfrac{{{\rm{distance}}}}{{{\rm{speed}}}}$
$ = \dfrac{{{\rm{2000}}\,{\rm{km}}}}{{{\rm{1000}}\,{\rm{km/hr}}}}$
$ = {\rm{2}}\,{\rm{hrs}}$
Step II,
Now, we solve for the total time and distance.
Therefore,
Total $ = $Time $\left( 1 \right)$$ + $Time$\left( 2 \right)$
$ = \left( {{\rm{1}}{\rm{.25 + 2}}} \right)\,{\rm{hrs}}$
$ = 3.25\,{\rm{hrs}}$ ……(1)
Now,
Since it is a round trip, we will add the total distance.
Therefore,
Distance$ = $${\rm{2}}\left( {{\rm{2000}}\,{\rm{km}}} \right)\,$
$ = {\rm{2}} \times {\rm{2000}}\,{\rm{km}}$
$ = 4{\rm{000}}\,{\rm{km}}$ ……(2)
We need to find the average speed, by using the equations (1) and (2)
Average Speed$ = \dfrac{{{\rm{Total Distance}}}}{{{\rm{Total Time}}}}$
$ = \dfrac{{{\rm{4000}}\,{\rm{km}}}}{{{\rm{3}}{\rm{.25}}\,{\rm{km/hr}}}}$
$ = {\rm{1230}}{\rm{.77 km/hr}}$
Hence, the average speed for the whole trip is ${\rm{1230}}{\rm{.77 km/hr}}$.
Note: Speed of an object means the distance covered at a particular time. Here we have to determine the speed of the flight for the given data. In step I we have to determine the average time using the distance and time by using the formula time equals distance divided by speed in the first trip of the flight. Again, we have to determine the average time using the distance and time by using the formula time equal distance divided by speed in the second trip of the flight which is a round trip. Then, in step II we add the total time on both the trips of the flight. Also, we need to find the total distance of the flight (up and down trip of the flight). Then, we find the average speed by dividing the total distance by total time.
Complete answer:
Here,
First we compute for the time in speed $1$,
Step I,
We know that,
${\rm{Time}}\left( {\rm{1}} \right){\rm{ = }}\dfrac{{{\rm{distance}}}}{{{\rm{speed}}}}$
$ = \dfrac{{{\rm{2000}}\,{\rm{km}}}}{{{\rm{1600}}\,{\rm{km/hr}}}}$
$ = {\rm{1}}{\rm{.25}}\,{\rm{hrs}}$
Again,
Since, the airline just returned.
Therefore,
We compute for the time in speed $2$,
We know that,
${\rm{Time}}\left( 2 \right){\rm{ = }}\dfrac{{{\rm{distance}}}}{{{\rm{speed}}}}$
$ = \dfrac{{{\rm{2000}}\,{\rm{km}}}}{{{\rm{1000}}\,{\rm{km/hr}}}}$
$ = {\rm{2}}\,{\rm{hrs}}$
Step II,
Now, we solve for the total time and distance.
Therefore,
Total $ = $Time $\left( 1 \right)$$ + $Time$\left( 2 \right)$
$ = \left( {{\rm{1}}{\rm{.25 + 2}}} \right)\,{\rm{hrs}}$
$ = 3.25\,{\rm{hrs}}$ ……(1)
Now,
Since it is a round trip, we will add the total distance.
Therefore,
Distance$ = $${\rm{2}}\left( {{\rm{2000}}\,{\rm{km}}} \right)\,$
$ = {\rm{2}} \times {\rm{2000}}\,{\rm{km}}$
$ = 4{\rm{000}}\,{\rm{km}}$ ……(2)
We need to find the average speed, by using the equations (1) and (2)
Average Speed$ = \dfrac{{{\rm{Total Distance}}}}{{{\rm{Total Time}}}}$
$ = \dfrac{{{\rm{4000}}\,{\rm{km}}}}{{{\rm{3}}{\rm{.25}}\,{\rm{km/hr}}}}$
$ = {\rm{1230}}{\rm{.77 km/hr}}$
Hence, the average speed for the whole trip is ${\rm{1230}}{\rm{.77 km/hr}}$.
Note: Speed of an object means the distance covered at a particular time. Here we have to determine the speed of the flight for the given data. In step I we have to determine the average time using the distance and time by using the formula time equals distance divided by speed in the first trip of the flight. Again, we have to determine the average time using the distance and time by using the formula time equal distance divided by speed in the second trip of the flight which is a round trip. Then, in step II we add the total time on both the trips of the flight. Also, we need to find the total distance of the flight (up and down trip of the flight). Then, we find the average speed by dividing the total distance by total time.
Recently Updated Pages
What happens to glucose which enters nephron along class 10 biology CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

When the JanmiKudian Act was passed that granted the class 10 social science CBSE

A sector containing an angle of 120 circ is cut off class 10 maths CBSE

The sum of digits of a two digit number is 13 If t-class-10-maths-ICSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove the Pythagoras theorem-class-10-maths-CBSE

A Gulab jamun contains sugar syrup up to about 30 of class 10 maths CBSE

A Paragraph on Pollution in about 100-150 Words

