Hydrogen atoms inside a discharge lamp emit a series of lines in the visible part of the spectrum. This series was named after the Swiss teacher Johann Balmar and called the Balmer series. In 1885, Balmar found a way to describe the wavelengths of these lines by a trial and error method. The formula gives the wavelength:
1/ƛ = R/[¼ - 1/n]. Here n are integers starting from 3, 4, 5 and go till infinity. R is the rydberg constant. This article will look closely into rydberg or rh constant, unit of rydberg constant, and also discuss the rydberg constant derivation.
What is Rydberg Constant and its Importance
The Rydberg constant holds high importance in atomic physics as it is connected to fundamental atomic constants, i.e. e, h, c, and me. The constant can be derived with a high level of accuracy. The rydberg constant first came into existence in 1890 when Swedish physicist Johannes Rydberg analyzed several spectra. Rydberg found that many of the Balmer line series could be explained by the equation:
n = n0 - N0/(m + m’)2, where m is a natural number, m’ and n0 are quantum defects specific for a particular series. N0 is the Rydberg constant. Rydberg is used as a unit of energy.
Explanation of Rydberg Constant
When an electron changes its position from one atomic orbit to another, there is a change in the electron’s energy. If the electron shifts from a higher energy state to a lower energy state, then a photon of light gets created. If the electron goes from a low energy state to a higher one, the atom absorbs a photon of light. A distinct spectral fingerprint characterizes every element.
R∞ or RH denotes the rydberg constant, and it is a wavenumber associated with the atomic spectrum of each element. The value of rydberg constant in cm ranges from 109,678 cm−1 to 109,737 cm−1. The first value of the constant is the value of the rydberg constant for hydrogen, and the last value is for the heaviest element. The value of the rydberg constant is based on the fact that the nucleus of an atom that is emitting light is exceedingly huger than the single orbiting electron.
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Dimensional Formula of Rydberg Constant
The Rydberg formula is expressed as a mathematical formula that denotes the wavelength of light emitted by an electron that moves between energy levels within an atom. Findings of Rydberg, along with Bohr’s atomic model, gave the below formula:
1/ƛ = RZ2(1/n12 - 1/n22)
Here Z is the atomic number of the atom and n1, and n2 are integers where n2 > n1. Later it was established that n1 and n2 are related to the energy quantum number (principal quantum number). This formula works quite well for hydrogen atoms with only one electron. By changing the values of n1 and n2, we can get other spectral series as shown in the table below:
Values of Rydberg's Constant
The accepted values of the Rydberg constant, R∞, as in 1998 are:
Rydberg Constant in nm - 10 973 731.568 548(83) m-1.
Rydberg Constant in Joules - 2.179 871 90(17).10-18 J.
Rydberg Constant in Electron Volt - 13.605662285137 eV.
Rydberg Constant in Tons of TNT - 5.2100191204589E-28 tTNT.
Rydberg Constant in ergs - 2.179872E-11 ergs.
Rydberg Constant in Foot Pound-Force - 1.6077910774693E-18 ft lbf.
Rydberg Constant Derivation
In classical format, the Rydberg constant comes from the electron radius and fine structure constant. The transverse wavelength equation gives the rydberg constant in wave format. The wave format is based on K = 10 (i.e. 10 wave centers) and is used with hydrogen calculations. If a nucleus has more than two protons, it will have different amplitude factors. Hence the Rydberg constant works only with hydrogen.
There is another derivation which is based on Bohr’s radius. Bohr stated that electrons existed in orbits with discrete energies. To know the energy released as light, we need to take the energy of these distinct states of an electron and find out their difference.
Let us consider the hydrogen luminesce spectrum where the atom has energy E, which is the sum of kinetic energy K and potential energy P equal to the energy of the rotating electron.
E = K + P
K = ½ * melectorn * v2
P = (q1* q2)/4π∈or, where ∈o is the constant of permittivity of space
= (Ze)(-e)/4π∈or, where Z is the number of protons
Now we apply the Virial theorem which states that the total energy of a system is equal to the negative of its kinetic energy or half of its potential energy.
E = -K = P/2
K = M2/2mer2 - Where M is the angular momentum of the electron = me * v * r (radius of the orbit of the electron).
From these we get R∞ = αe/4πa0, where a0 is Bohr’s radius = 52.92 pm and αe is the angular momentum of the electron.