What is Joule Thomson Effect in Thermodynamics?
Joule Thomson effect illustrates the change in temperature of a fluid when it is forced to flow through an insulated valve from a high-pressure region towards a region with low pressure. Joule Thomson effect is often termed the Joule Kelvin or Kelvin Joule effect. According to their theory, change in pressure in the valve can cause changes in the temperature of the fluid.
Joule Thomson Experiment
Refer to the image shown above that helps understand the effect of Joule Thomson law quickly. To illustrate this, a gas packet is placed opposite to the flow of direction in a Joule Thomson valve. As a result, it faces restriction, and the upstream gas will need to perform work to help it move. This work done is equivalent to the multiplication of upstream pressure and volume of a packet.
W1 = VPacket1 x P1
Further, the fluid packet has to perform certain work to make a place for itself by displacing some amount of downstream gas. This work done can be expressed as
W2 = VPacket2 x P2
However, this work performed upstream and work performed downstream is not equal because of various effects of compressibility. This internal energy of fluid follows the 1st law of thermodynamics. And the adiabatic process does not allow this system to lose any heat or work.
From the above theories, we can conclude that
U2 – U1 = W1 – W2
For cases where the fluid pressure is lowered, there is a rise in aggregate distance between molecules. As a result, the increased attractive forces also cause an increase in potential energy.
Further, it is seen that real gases need to work more downstream to make a place for the packets than they need to work upstream.
Therefore, the following equation can be written
P1 x V1 < P2 x V2
It also illustrates a decrease in potential energy as the fluid goes through restriction. Most real gases show a reduction in temperature with a decrease in pressure. However, that does not hold true for every condition or gas. To conclude, the temperature of this fluid varies with varying potential energy, given the enthalpy of the gas remains unchanged.
Joule Thomson Coefficient
It can be defined as the change in temperature of the fluid with the varying pressure in order to keep its enthalpy constant. It can be expressed as follows
μJT = (∂T / ∂P) H
Joule Thomson Expansion
The coefficient is to be derived using the law of thermodynamics and will be written as,
μ = (∂T / ∂P)H (∂T / ∂P)T (∂P / ∂T)H (∂T / ∂H)P
= -1 (∂H / ∂P)T
= − (∂H / ∂T)P (∂T/ ∂P)H (∂H / ∂P)T
= – CP μ
Further,
(∂H / ∂P)T = [v~ − T (∂v / ∂T)P
μ= RT2 PCP (∂Z / ∂T) P μ
= (∂T / ∂P)H
= 1/CP [T. (∂v / ∂T)P−v]
=−1/ CP (∂H / ∂P)T
= RT2 / PCP (∂Z / ∂T)P
Mentioned above is the expansion, which will help you calculate the Joule Thomson coefficient for real gas step by step. Learn the steps carefully to understand the derivation procedure.
Inversion temperature is the fluid’s temperature at which there is no change in pressure even with decrease in temperature.
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1. What are the applications of Joule Thomson effect?
Joule Thomson coefficient calculation has applications in liquefiers, air conditioner, refrigerators, heat pump, cryogenic applications, etc.
2. What is Joule Thomson effect?
According to the Joule Thomson effect theory, there is a change in temperature of a fluid with varying pressure applied to the fluid when the enthalpy of fluid remains constant. Further, its coefficient can be derived from the theoretical speculations.
3. What is a Joule Thomson coefficient for ideal gas?
Joule Thomson coefficient could be defined as the ratio of temperature drop to pressure drop. For an ideal gas, its value is equal to zero as the value of enthalpy depends on temperature.
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