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# Magnetic Field in a Solenoid Formula

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Last updated date: 14th Jul 2024
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## Introduction to Solenoid

The term solenoid in Greek means "pipe-shaped". It is a type of electromagnet, its purpose is to generate a controlled magnetic field through a coil that is wound into a tightly packed helix. The coil can be arranged to produce a uniform magnetic field in a volume of space when an electric current is passed through it. According to the study of electromagnetism, a solenoid is a coil whose length is greater than its diameter; this means that it is rod-shaped. The helical coil of a solenoid does not necessarily need to revolve around a straight-line axis, for example, William Sturgeon's electromagnet of 1824 consisted of a solenoid bent in the form of horseshoe shape. Hence magnetic field formula of the solenoid equation is given as follows:

B=μ0 nl

Here B represents the magnetic flux density,

μ0 is the magnetic constant whose value is 4π x 10- Hm

or 12.57 x 10 Hm, N is a number of turns, I is the current flowing through the solenoid, and l is the length of the solenoid.

### Magnetic Field Inside a Solenoid Formula

The magnetic field inside an infinitely long solenoid is homogeneous and its strength neither depends on the distance from the axis nor the solenoid's cross-sectional area.

The derivation of the magnetic flux density surrounding a solenoid is long enough so that fringe effects can be ignored. We immediately know that from the figure, the flux density of the vector points is in the positive z-direction inside the solenoid, and outside the solenoid, it is in the negative z-direction. We can confirm this by applying the right-hand grip rule or right-hand thumb rule for the field that is present around a wire. If we wrap our right hand around a wire by pointing the thumb in the direction of the current, the curl of the fingers represents how the field behaves. Since we are dealing with a long solenoid, due to symmetry all of the components of the magnetic field that are not pointing upwards may cancel out.

Now consider the imaginary loop ‘c’ from the figure, it is located inside the solenoid. By Ampère's law, we can say that the line integral of B that is the magnetic flux density vector around this loop is zero. It happens since it encloses no electrical currents. We have shown above that the field is pointing upwards inside the solenoid, hence the horizontal portions of loop c do not contribute anything to the integral. Thus the integral of the upper side of the figure that represents one is equal to an integral part of side two that is moving downwards. Since the change in the dimensions of the loop can be done arbitrarily to get the same result, the integrands are equal. This means that the magnetic field inside the solenoid is radially uniform.

A solenoid is a coil of wire through which current flows and the magnetic field inside it is determined with the help of the contribution of each loop in the solenoid. Hence the total magnetic field depends on the number of turns of the coil and the length of the solenoid.

The magnetic field inside the solenoid is maximum, and the magnetic field inside the solenoid formula is,

B=μ0 nI

nI, Here ‘n’ represents the number of turns and ‘I’ the current flowing through the solenoid.

### Magnetic Field Outside a Solenoid Formula

A similar argument can be applied to the loop to conclude that the field outside the solenoid is radially uniform or constant. An intuitive argument can also be used to show that the flux density outside the solenoid is zero. Magnetic field lines only exist in the form of loops, they cannot diverge or converge to a point as that of the electric field lines. The magnetic field lines in the solenoid follow the longitudinal path, so outside the solenoid, these magnetic field lines must move in the opposite direction. This happens due to the lines forming a loop. However, the volume that is present outside the solenoid is much greater than that of the volume present inside. Thus the density of magnetic field lines outside the solenoid is reduced greatly. Thus we can say that the field outside the solenoid is constant. For the total number of field lines to be conserved, the field outside must go to zero as the solenoid gets longer.

Solenoid magnetic field equation outside it is

B=μ0 nl

Since the field outside the solenoid is comparatively less as that it is present inside we can consider it as zero as the length of the solenoid increases, and thus B = 0.

### Fun Facts About Magnetic Field

• The magnetic field of Earth is 1000 times weaker than a bar magnet

• We have planets in our solar system that show magnetic fields. These planets are Earth, Saturn, Jupiter, Neptune and Uranus.

• Earth has its magnetic field because of the presence of a large iron core at its center

• Maglev trains use the principles related to the magnetic field in their operation.

• Many roller coasters use an electromagnet to push their cars on the track

• The phenomenon of Aurora is observed near the poles when magnetic field lines of the earth interact with incoming solar winds.

### Conclusion

Magnetic Field in a Solenoid Formula forms a very important topic in the Class 12 Physics syllabus as well as in various national level and state level entrance exams.

Here Vedantu has covered theoretical as well as formulas associated with magnetic fields in a solenoid. To make this topic interesting for students various interesting facts related to magnetic fields are added towards the end of the article.

Vedantu is committed to delivering the best to its students in every way possible. Thus it has brought all these study materials for free for you. After reading Magnetic Field in a Solenoid Formula from Vedantu you will be in a position to solve all the questions that may arise from this topic in any given exam.

## FAQs on Magnetic Field in a Solenoid Formula

1. What is the Formula for the Magnetic Field of Solenoid?

Formula of the magnetic field of the solenoid is B = μ₀ (NI/l).

2. What will Happen When the Number of Turns in a Coil is Doubled?

The magnetic field due to the solenoid formula is as follows, B = μ₀ (NI/l) or B = μ₀nI. In both cases the number of turns is directly proportional to the magnetic field, thus by increasing or by doubling the number of turns it directly affects the magnetic field and it increases.

3. How can Magnetic Field in a Solenoid Formula help me score full marks in Physics exams?

Every year in the Physics exam at least one question is asked on the topic of Magnetic field and magnetic force. This question may also be based on Magnetic Field in a Solenoid Formula which is a sub-topic of the magnetic field. These questions are either asked for 2 or 3 or 4 marks. Thus you cannot risk not studying this topic for the exam. It is suggested you refer to content available on Vedantu’s website to enrich your knowledge base.

4. Will studying Magnetic Field in a Solenoid Formula help me in NEET exams?

Yes, studying Magnetic Field in a Solenoid Formula will surely help you in your National Eligibility Entrance Test (NEET) for MBBS. This exam contains around 30 questions from Physics out of which at least 1 question may be dedicated to this topic. These many marks can take you a step closer to your dream medical school. To ensure you do not miss any important question of Physics you can refer to Vedantu’s NEET Physics important questions. These are available for free and can be accessed from any device.

5. From where can I study Magnetic Field in a Solenoid Formula easily for free?

You can study Magnetic Field in a Solenoid Formula for free from the content made available to you on Vedantu’s website. The information made available to you is very rich in quality and it is extremely reliable because it is prepared by the subject matter experts of Vedantu. The entire topic is covered very holistically. You can access this piece of information on your mobile phone as well by downloading Vedantu’s official app. You may want to read other topics of Physics by Vedantu to score excellent marks in Physics Class 12 exams.

6. Is it possible to study Magnetic Field in a Solenoid Formula in 3 hours?

Yes it is very much possible to study Magnetic Field in a Solenoid Formula in 3 hours. You can do this if you are thorough with concepts related to the magnetic field. You should read this topic from Class 12 NCERT and then get a further understanding of the content made available to you on Vedantu's website. But to master this topic you will have to solve problems related to it. This cannot be done within the time frame of 3 hours. For this, you will have to dedicate sufficient time to and solve problems from various books. You will also have to read the properties of magnetic field lines by Vedantu.

7. How to approach Magnetic Field in a Solenoid Formula?

Correct way of approaching would be to read Class 11 and Class 12 Physics NCERT books which are available on Vedantu’s website for free. These chapters will start the topic from very basic and build upon it. These books will help you in understanding the concepts of the magnetic field first and will continue further. You should also solve all the problems given in these NCERTs, solutions to which can be found on Vedantu’s website for free. After this, you should clear this topic from this webpage. Post this, you can proceed towards solving sums from HC Verma’s Physics book.