QUESTION

# Two years ago, Mohit was three times as old as his son and two years hence, twice of Mohit’s age will be equal to five times that of his son. Then the present age of Mohit son is :A. 14years B. 28years C. 32years D. 34years

Hint: In this question, we have to find the present age of Mohit’s son so let the age of Mohit’s son be $x$, find the mohit’s age in terms of $x$ and after 2 years compare it with his son's age.
So, let the age of Mohit’s son $= $x Now, 2 years ago Mohit’s son age = x - 2 Mohit age at that time = 3(x - 2) Now , the present age of Mohit will be \Rightarrow$3(x - 2) + 2 = 3x - 6 + 2 = 3x - 4$
Now, $2$ years hence
Mohit’s age $= (3x - 4) + 2$
$2$ years hence son’s age $= x + 2$
$\Rightarrow 5(x + 2) = 2(3x - 2) \\ \Rightarrow x = 14 \\$
Hence the present age of Mohit’s son is $14years$.
Note: In such types of questions of ratio, whatever we have to find just let that be $x$ and move ahead with the statement step by step that is given in the question.