Question

Tannu buys $20$ pieces of a toy car from a wholesaler shop for $Rs.3700$. Next day, he again buys $34$ cars. How much money does Tannu need to give the shopkeeper?

Answer 1

Hint: Cost price of an article is the price in which they purchase the article from the seller. Profit is a term used in the market. Profit occurs when the selling price of an article is more than the cost price of the article (SP>CP). It will also be known as remaining after all costs are paid. Selling price, it is the price in which they sell the article to customers. Cost price, it is the price in which they buy the article. As we know that
$\therefore \text{Profit} = \text{Selling price} - \text{Cost price}$

Complete step-by-step solution:
Given,
Total number of toy cars, ${N_1} = 20$
Price he paid, $C{P_1} = Rs3700$
Extra number of toys cars, ${N_2} = 34$
Total number of toy cars will be
$\therefore N = {N_1} + {N_2}$
Put the value,
$ \Rightarrow N = 20 + 34$
Simplify
$ \Rightarrow N = 54$
The price of $1$ toy cars will be,
\[\therefore \dfrac{{C{P_1}}}{{{N_1}}}\]
Put the value
$ = \dfrac{{3700}}{{20}}$
$ = Rs.185$
So the price of 1 toy car is $Rs.185$
Now the price of other 34 toys will be, $C{P_2} = ?$
$\therefore \text{Price of 1 toy car} \times {N_2}$
Put the value
$ \Rightarrow C{P_2} = 185 \times 34$
$ \Rightarrow C{P_2} = Rs.6290$
So the total amount of toy cars will paid by Tannu, $CP = ?$
$\therefore CP = C{P_1} + C{P_2}$
Put the value
$ \Rightarrow CP = 3700 + 6290$
Simplify
$ \Rightarrow CP = Rs.9990$
The total amount paid by Tannu is $Rs.9990$.

Note: Loss in an article is calculated when the cost price of an article is more than the selling price or shopkeeper sells an object in less price than cost price. In that condition $CP > SP$. Discount is a reduced price or which something sold at lower price less than marked price. Here we have not been asked about profit and loss. We just need to simply find the cost price of a toy, we could use the unitary method to solve this problem.