Question

Find the greatest six digit number that is exactly divisible by 18, 24 and 36.

Answer 1

Hint:In order to solve this problem first take the LCM of the 3 given numbers then divide the greatest 6-digit number by the LCM obtained if there is any remainder then subtract the remainder from the greatest 6-digit number to get your answer.

Complete step-by-step answer:
So, we need to find the greatest 6-digit number that is exactly divisible by 18, 24, 36.
So we will take the LCM (Lowest common factor) of 18,24,36.

So we can see above that LCM of 18, 24, 36 = 3x3x2x2x2=72
As we know the greatest 6-digit number is 999999.
On dividing 999999 by 72 we get:

We got 13888 as a quotient and 63 as remainder.
So, the greatest 6-digit number divisible by 18, 24, 36 is 999999 – 63 = 999936
Hence the answer is 999936.

Note:Whenever you face such types of problems then obtain the lowest common factor of the given numbers then divide the greatest 6 – digit number to see that the highest point is equal to or more than the answer we required. If there is a remainder other than zero then the highest number is more than the required one. Therefore we have subtracted the reminder from the largest 6-digit number. Proceeding like this it will give you the right answer.